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Theorem List for Metamath Proof Explorer - 40301-40400   *Has distinct variable group(s)
TypeLabelDescription
Statement
 
Theoremreaddid1addid2d 40301 Given some real number 𝐵 where 𝐴 acts like a right additive identity, derive that 𝐴 is a left additive identity. Note that the hypothesis is weaker than proving that 𝐴 is a right additive identity (for all numbers). Although, if there is a right additive identity, then by readdcan 11158, 𝐴 is the right additive identity. (Contributed by Steven Nguyen, 14-Jan-2023.)
(𝜑𝐴 ∈ ℝ)    &   (𝜑𝐵 ∈ ℝ)    &   (𝜑 → (𝐵 + 𝐴) = 𝐵)       ((𝜑𝐶 ∈ ℝ) → (𝐴 + 𝐶) = 𝐶)
 
Theoremsn-1ne2 40302 A proof of 1ne2 12190 without using ax-mulcom 10944, ax-mulass 10946, ax-pre-mulgt0 10957. Based on mul02lem2 11161. (Contributed by SN, 13-Dec-2023.)
1 ≠ 2
 
Theoremnnn1suc 40303* A positive integer that is not 1 is a successor of some other positive integer. (Contributed by Steven Nguyen, 19-Aug-2023.)
((𝐴 ∈ ℕ ∧ 𝐴 ≠ 1) → ∃𝑥 ∈ ℕ (𝑥 + 1) = 𝐴)
 
Theoremnnadd1com 40304 Addition with 1 is commutative for natural numbers. (Contributed by Steven Nguyen, 9-Dec-2022.)
(𝐴 ∈ ℕ → (𝐴 + 1) = (1 + 𝐴))
 
Theoremnnaddcom 40305 Addition is commutative for natural numbers. Uses fewer axioms than addcom 11170. (Contributed by Steven Nguyen, 9-Dec-2022.)
((𝐴 ∈ ℕ ∧ 𝐵 ∈ ℕ) → (𝐴 + 𝐵) = (𝐵 + 𝐴))
 
Theoremnnaddcomli 40306 Version of addcomli 11176 for natural numbers. (Contributed by Steven Nguyen, 1-Aug-2023.)
𝐴 ∈ ℕ    &   𝐵 ∈ ℕ    &   (𝐴 + 𝐵) = 𝐶       (𝐵 + 𝐴) = 𝐶
 
Theoremnnadddir 40307 Right-distributivity for natural numbers without ax-mulcom 10944. (Contributed by SN, 5-Feb-2024.)
((𝐴 ∈ ℕ ∧ 𝐵 ∈ ℕ ∧ 𝐶 ∈ ℕ) → ((𝐴 + 𝐵) · 𝐶) = ((𝐴 · 𝐶) + (𝐵 · 𝐶)))
 
Theoremnnmul1com 40308 Multiplication with 1 is commutative for natural numbers, without ax-mulcom 10944. Since (𝐴 · 1) is 𝐴 by ax-1rid 10950, this is equivalent to remulid2 40422 for natural numbers, but using fewer axioms (avoiding ax-resscn 10937, ax-addass 10945, ax-mulass 10946, ax-rnegex 10951, ax-pre-lttri 10954, ax-pre-lttrn 10955, ax-pre-ltadd 10956). (Contributed by SN, 5-Feb-2024.)
(𝐴 ∈ ℕ → (1 · 𝐴) = (𝐴 · 1))
 
Theoremnnmulcom 40309 Multiplication is commutative for natural numbers. (Contributed by SN, 5-Feb-2024.)
((𝐴 ∈ ℕ ∧ 𝐵 ∈ ℕ) → (𝐴 · 𝐵) = (𝐵 · 𝐴))
 
Theoremmvrrsubd 40310 Move a subtraction in the RHS to a right-addition in the LHS. Converse of mvlraddd 11394. (Contributed by SN, 21-Aug-2024.)
(𝜑𝐵 ∈ ℂ)    &   (𝜑𝐶 ∈ ℂ)    &   (𝜑𝐴 = (𝐵𝐶))       (𝜑 → (𝐴 + 𝐶) = 𝐵)
 
Theoremladdrotrd 40311 Rotate the variables right in an equation with addition on the left, converting it into a subtraction. Version of mvlladdd 11395 with a commuted consequent, and of mvrladdd 11397 with a commuted hypothesis. (Contributed by SN, 21-Aug-2024.)
(𝜑𝐴 ∈ ℂ)    &   (𝜑𝐵 ∈ ℂ)    &   (𝜑 → (𝐴 + 𝐵) = 𝐶)       (𝜑 → (𝐶𝐴) = 𝐵)
 
Theoremraddcom12d 40312 Swap the first two variables in an equation with addition on the right, converting it into a subtraction. Version of mvrraddd 11396 with a commuted consequent, and of mvlraddd 11394 with a commuted hypothesis. (Contributed by SN, 21-Aug-2024.)
(𝜑𝐵 ∈ ℂ)    &   (𝜑𝐶 ∈ ℂ)    &   (𝜑𝐴 = (𝐵 + 𝐶))       (𝜑𝐵 = (𝐴𝐶))
 
Theoremlsubrotld 40313 Rotate the variables left in an equation with subtraction on the left, converting it into an addition. (Contributed by SN, 21-Aug-2024.)
(𝜑𝐴 ∈ ℂ)    &   (𝜑𝐵 ∈ ℂ)    &   (𝜑 → (𝐴𝐵) = 𝐶)       (𝜑 → (𝐵 + 𝐶) = 𝐴)
 
Theoremlsubcom23d 40314 Swap the second and third variables in an equation with subtraction on the left, converting it into an addition. (Contributed by SN, 23-Aug-2024.)
(𝜑𝐴 ∈ ℂ)    &   (𝜑𝐵 ∈ ℂ)    &   (𝜑 → (𝐴𝐵) = 𝐶)       (𝜑 → (𝐴𝐶) = 𝐵)
 
Theoremaddsubeq4com 40315 Relation between sums and differences. (Contributed by Steven Nguyen, 5-Jan-2023.)
(((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) ∧ (𝐶 ∈ ℂ ∧ 𝐷 ∈ ℂ)) → ((𝐴 + 𝐵) = (𝐶 + 𝐷) ↔ (𝐴𝐶) = (𝐷𝐵)))
 
Theoremsqsumi 40316 A sum squared. (Contributed by Steven Nguyen, 16-Sep-2022.)
𝐴 ∈ ℂ    &   𝐵 ∈ ℂ       ((𝐴 + 𝐵) · (𝐴 + 𝐵)) = (((𝐴 · 𝐴) + (𝐵 · 𝐵)) + (2 · (𝐴 · 𝐵)))
 
Theoremnegn0nposznnd 40317 Lemma for dffltz 40478. (Contributed by Steven Nguyen, 27-Feb-2023.)
(𝜑𝐴 ≠ 0)    &   (𝜑 → ¬ 0 < 𝐴)    &   (𝜑𝐴 ∈ ℤ)       (𝜑 → -𝐴 ∈ ℕ)
 
Theoremsqmid3api 40318 Value of the square of the middle term of a 3-term arithmetic progression. (Contributed by Steven Nguyen, 20-Sep-2022.)
𝐴 ∈ ℂ    &   𝑁 ∈ ℂ    &   (𝐴 + 𝑁) = 𝐵    &   (𝐵 + 𝑁) = 𝐶       (𝐵 · 𝐵) = ((𝐴 · 𝐶) + (𝑁 · 𝑁))
 
Theoremdecaddcom 40319 Commute ones place in addition. (Contributed by Steven Nguyen, 29-Jan-2023.)
𝐴 ∈ ℕ0    &   𝐵 ∈ ℕ0    &   𝐶 ∈ ℕ0       (𝐴𝐵 + 𝐶) = (𝐴𝐶 + 𝐵)
 
Theoremsqn5i 40320 The square of a number ending in 5. This shortcut only works because 5 is half of 10. (Contributed by Steven Nguyen, 16-Sep-2022.)
𝐴 ∈ ℕ0       (𝐴5 · 𝐴5) = (𝐴 · (𝐴 + 1))25
 
Theoremsqn5ii 40321 The square of a number ending in 5. This shortcut only works because 5 is half of 10. (Contributed by Steven Nguyen, 16-Sep-2022.)
𝐴 ∈ ℕ0    &   (𝐴 + 1) = 𝐵    &   (𝐴 · 𝐵) = 𝐶       (𝐴5 · 𝐴5) = 𝐶25
 
Theoremdecpmulnc 40322 Partial products algorithm for two digit multiplication, no carry. Compare muladdi 11435. (Contributed by Steven Nguyen, 9-Dec-2022.)
𝐴 ∈ ℕ0    &   𝐵 ∈ ℕ0    &   𝐶 ∈ ℕ0    &   𝐷 ∈ ℕ0    &   (𝐴 · 𝐶) = 𝐸    &   ((𝐴 · 𝐷) + (𝐵 · 𝐶)) = 𝐹    &   (𝐵 · 𝐷) = 𝐺       (𝐴𝐵 · 𝐶𝐷) = 𝐸𝐹𝐺
 
Theoremdecpmul 40323 Partial products algorithm for two digit multiplication. (Contributed by Steven Nguyen, 10-Dec-2022.)
𝐴 ∈ ℕ0    &   𝐵 ∈ ℕ0    &   𝐶 ∈ ℕ0    &   𝐷 ∈ ℕ0    &   (𝐴 · 𝐶) = 𝐸    &   ((𝐴 · 𝐷) + (𝐵 · 𝐶)) = 𝐹    &   (𝐵 · 𝐷) = 𝐺𝐻    &   (𝐸𝐺 + 𝐹) = 𝐼    &   𝐺 ∈ ℕ0    &   𝐻 ∈ ℕ0       (𝐴𝐵 · 𝐶𝐷) = 𝐼𝐻
 
Theoremsqdeccom12 40324 The square of a number in terms of its digits switched. (Contributed by Steven Nguyen, 3-Jan-2023.)
𝐴 ∈ ℕ0    &   𝐵 ∈ ℕ0       ((𝐴𝐵 · 𝐴𝐵) − (𝐵𝐴 · 𝐵𝐴)) = (99 · ((𝐴 · 𝐴) − (𝐵 · 𝐵)))
 
Theoremsq3deccom12 40325 Variant of sqdeccom12 40324 with a three digit square. (Contributed by Steven Nguyen, 3-Jan-2023.)
𝐴 ∈ ℕ0    &   𝐵 ∈ ℕ0    &   𝐶 ∈ ℕ0    &   (𝐴 + 𝐶) = 𝐷       ((𝐴𝐵𝐶 · 𝐴𝐵𝐶) − (𝐷𝐵 · 𝐷𝐵)) = (99 · ((𝐴𝐵 · 𝐴𝐵) − (𝐶 · 𝐶)))
 
Theorem235t711 40326 Calculate a product by long multiplication as a base comparison with other multiplication algorithms.

Conveniently, 711 has two ones which greatly simplifies calculations like 235 · 1. There isn't a higher level mulcomli 10993 saving the lower level uses of mulcomli 10993 within 235 · 7 since mulcom2 doesn't exist, but if commuted versions of theorems like 7t2e14 12555 are added then this proof would benefit more than ex-decpmul 40327.

For practicality, this proof doesn't have "e167085" at the end of its name like 2p2e4 12117 or 8t7e56 12566. (Contributed by Steven Nguyen, 10-Dec-2022.) (New usage is discouraged.)

(235 · 711) = 167085
 
Theoremex-decpmul 40327 Example usage of decpmul 40323. This proof is significantly longer than 235t711 40326. There is more unnecessary carrying compared to 235t711 40326. Although saving 5 visual steps, using mulcomli 10993 early on increases the compressed proof length. (Contributed by Steven Nguyen, 10-Dec-2022.) (New usage is discouraged.) (Proof modification is discouraged.)
(235 · 711) = 167085
 
20.26.5  Exponents and divisibility
 
Theoremoexpreposd 40328 Lemma for dffltz 40478. TODO-SN?: This can be used to show exp11d 40332 holds for all integers when the exponent is odd. The more standard ¬ 2 ∥ 𝑀 should be used. (Contributed by SN, 4-Mar-2023.)
(𝜑𝑁 ∈ ℝ)    &   (𝜑𝑀 ∈ ℕ)    &   (𝜑 → ¬ (𝑀 / 2) ∈ ℕ)       (𝜑 → (0 < 𝑁 ↔ 0 < (𝑁𝑀)))
 
Theoremltexp1d 40329 ltmul1d 12822 for exponentiation of positive reals. (Contributed by Steven Nguyen, 22-Aug-2023.)
(𝜑𝐴 ∈ ℝ+)    &   (𝜑𝐵 ∈ ℝ+)    &   (𝜑𝑁 ∈ ℕ)       (𝜑 → (𝐴 < 𝐵 ↔ (𝐴𝑁) < (𝐵𝑁)))
 
Theoremltexp1dd 40330 Raising both sides of 'less than' to the same positive integer preserves ordering. (Contributed by Steven Nguyen, 24-Aug-2023.)
(𝜑𝐴 ∈ ℝ+)    &   (𝜑𝐵 ∈ ℝ+)    &   (𝜑𝑁 ∈ ℕ)    &   (𝜑𝐴 < 𝐵)       (𝜑 → (𝐴𝑁) < (𝐵𝑁))
 
Theoremexp11nnd 40331 sq11d 13984 for positive real bases and positive integer exponents. The base cannot be generalized much further, since if 𝑁 is even then we have 𝐴𝑁 = -𝐴𝑁. (Contributed by SN, 14-Sep-2023.)
(𝜑𝐴 ∈ ℝ+)    &   (𝜑𝐵 ∈ ℝ+)    &   (𝜑𝑁 ∈ ℕ)    &   (𝜑 → (𝐴𝑁) = (𝐵𝑁))       (𝜑𝐴 = 𝐵)
 
Theoremexp11d 40332 exp11nnd 40331 for nonzero integer exponents. (Contributed by SN, 14-Sep-2023.)
(𝜑𝐴 ∈ ℝ+)    &   (𝜑𝐵 ∈ ℝ+)    &   (𝜑𝑁 ∈ ℤ)    &   (𝜑𝑁 ≠ 0)    &   (𝜑 → (𝐴𝑁) = (𝐵𝑁))       (𝜑𝐴 = 𝐵)
 
Theorem0dvds0 40333 0 divides 0. (Contributed by SN, 15-Sep-2024.)
0 ∥ 0
 
Theoremabsdvdsabsb 40334 Divisibility is invariant under taking the absolute value on both sides. (Contributed by SN, 15-Sep-2024.)
((𝑀 ∈ ℤ ∧ 𝑁 ∈ ℤ) → (𝑀𝑁 ↔ (abs‘𝑀) ∥ (abs‘𝑁)))
 
Theoremdvdsexpim 40335 dvdssqim 16273 generalized to nonnegative exponents. (Contributed by Steven Nguyen, 2-Apr-2023.)
((𝐴 ∈ ℤ ∧ 𝐵 ∈ ℤ ∧ 𝑁 ∈ ℕ0) → (𝐴𝐵 → (𝐴𝑁) ∥ (𝐵𝑁)))
 
Theoremgcdnn0id 40336 The gcd of a nonnegative integer and itself is the integer. (Contributed by SN, 25-Aug-2024.)
(𝑁 ∈ ℕ0 → (𝑁 gcd 𝑁) = 𝑁)
 
Theoremgcdle1d 40337 The greatest common divisor of a positive integer and another integer is less than or equal to the positive integer. (Contributed by SN, 25-Aug-2024.)
(𝜑𝑀 ∈ ℕ)    &   (𝜑𝑁 ∈ ℤ)       (𝜑 → (𝑀 gcd 𝑁) ≤ 𝑀)
 
Theoremgcdle2d 40338 The greatest common divisor of a positive integer and another integer is less than or equal to the positive integer. (Contributed by SN, 25-Aug-2024.)
(𝜑𝑀 ∈ ℤ)    &   (𝜑𝑁 ∈ ℕ)       (𝜑 → (𝑀 gcd 𝑁) ≤ 𝑁)
 
Theoremdvdsexpad 40339 Deduction associated with dvdsexpim 40335. (Contributed by SN, 21-Aug-2024.)
(𝜑𝐴 ∈ ℤ)    &   (𝜑𝐵 ∈ ℤ)    &   (𝜑𝑁 ∈ ℕ0)    &   (𝜑𝐴𝐵)       (𝜑 → (𝐴𝑁) ∥ (𝐵𝑁))
 
Theoremnn0rppwr 40340 If 𝐴 and 𝐵 are relatively prime, then so are 𝐴𝑁 and 𝐵𝑁. rppwr 16278 extended to nonnegative integers. Less general than rpexp12i 16438. (Contributed by Steven Nguyen, 4-Apr-2023.)
((𝐴 ∈ ℕ0𝐵 ∈ ℕ0𝑁 ∈ ℕ0) → ((𝐴 gcd 𝐵) = 1 → ((𝐴𝑁) gcd (𝐵𝑁)) = 1))
 
Theoremexpgcd 40341 Exponentiation distributes over GCD. sqgcd 16279 extended to nonnegative exponents. (Contributed by Steven Nguyen, 4-Apr-2023.)
((𝐴 ∈ ℕ ∧ 𝐵 ∈ ℕ ∧ 𝑁 ∈ ℕ0) → ((𝐴 gcd 𝐵)↑𝑁) = ((𝐴𝑁) gcd (𝐵𝑁)))
 
Theoremnn0expgcd 40342 Exponentiation distributes over GCD. nn0gcdsq 16465 extended to nonnegative exponents. expgcd 40341 extended to nonnegative bases. (Contributed by Steven Nguyen, 5-Apr-2023.)
((𝐴 ∈ ℕ0𝐵 ∈ ℕ0𝑁 ∈ ℕ0) → ((𝐴 gcd 𝐵)↑𝑁) = ((𝐴𝑁) gcd (𝐵𝑁)))
 
Theoremzexpgcd 40343 Exponentiation distributes over GCD. zgcdsq 16466 extended to nonnegative exponents. nn0expgcd 40342 extended to integer bases by symmetry. (Contributed by Steven Nguyen, 5-Apr-2023.)
((𝐴 ∈ ℤ ∧ 𝐵 ∈ ℤ ∧ 𝑁 ∈ ℕ0) → ((𝐴 gcd 𝐵)↑𝑁) = ((𝐴𝑁) gcd (𝐵𝑁)))
 
Theoremnumdenexp 40344 numdensq 16467 extended to nonnegative exponents. (Contributed by Steven Nguyen, 5-Apr-2023.)
((𝐴 ∈ ℚ ∧ 𝑁 ∈ ℕ0) → ((numer‘(𝐴𝑁)) = ((numer‘𝐴)↑𝑁) ∧ (denom‘(𝐴𝑁)) = ((denom‘𝐴)↑𝑁)))
 
Theoremnumexp 40345 numsq 16468 extended to nonnegative exponents. (Contributed by Steven Nguyen, 5-Apr-2023.)
((𝐴 ∈ ℚ ∧ 𝑁 ∈ ℕ0) → (numer‘(𝐴𝑁)) = ((numer‘𝐴)↑𝑁))
 
Theoremdenexp 40346 densq 16469 extended to nonnegative exponents. (Contributed by Steven Nguyen, 5-Apr-2023.)
((𝐴 ∈ ℚ ∧ 𝑁 ∈ ℕ0) → (denom‘(𝐴𝑁)) = ((denom‘𝐴)↑𝑁))
 
Theoremdvdsexpnn 40347 dvdssqlem 16280 generalized to positive integer exponents. (Contributed by SN, 20-Aug-2024.)
((𝐴 ∈ ℕ ∧ 𝐵 ∈ ℕ ∧ 𝑁 ∈ ℕ) → (𝐴𝐵 ↔ (𝐴𝑁) ∥ (𝐵𝑁)))
 
Theoremdvdsexpnn0 40348 dvdsexpnn 40347 generalized to include zero bases. (Contributed by SN, 15-Sep-2024.)
((𝐴 ∈ ℕ0𝐵 ∈ ℕ0𝑁 ∈ ℕ) → (𝐴𝐵 ↔ (𝐴𝑁) ∥ (𝐵𝑁)))
 
Theoremdvdsexpb 40349 dvdssq 16281 generalized to positive integer exponents. (Contributed by SN, 15-Sep-2024.)
((𝐴 ∈ ℤ ∧ 𝐵 ∈ ℤ ∧ 𝑁 ∈ ℕ) → (𝐴𝐵 ↔ (𝐴𝑁) ∥ (𝐵𝑁)))
 
Theoremposqsqznn 40350 When a positive rational squared is an integer, the rational is a positive integer. zsqrtelqelz 16471 with all terms squared and positive. (Contributed by SN, 23-Aug-2024.)
(𝜑 → (𝐴↑2) ∈ ℤ)    &   (𝜑𝐴 ∈ ℚ)    &   (𝜑 → 0 < 𝐴)       (𝜑𝐴 ∈ ℕ)
 
Theoremcxpgt0d 40351 A positive real raised to a real power is positive. (Contributed by SN, 6-Apr-2023.)
(𝜑𝐴 ∈ ℝ+)    &   (𝜑𝑁 ∈ ℝ)       (𝜑 → 0 < (𝐴𝑐𝑁))
 
Theoremzrtelqelz 40352 zsqrtelqelz 16471 generalized to positive integer roots. (Contributed by Steven Nguyen, 6-Apr-2023.)
((𝐴 ∈ ℤ ∧ 𝑁 ∈ ℕ ∧ (𝐴𝑐(1 / 𝑁)) ∈ ℚ) → (𝐴𝑐(1 / 𝑁)) ∈ ℤ)
 
Theoremzrtdvds 40353 A positive integer root divides its integer. (Contributed by Steven Nguyen, 6-Apr-2023.)
((𝐴 ∈ ℤ ∧ 𝑁 ∈ ℕ ∧ (𝐴𝑐(1 / 𝑁)) ∈ ℕ) → (𝐴𝑐(1 / 𝑁)) ∥ 𝐴)
 
Theoremrtprmirr 40354 The root of a prime number is irrational. (Contributed by Steven Nguyen, 6-Apr-2023.)
((𝑃 ∈ ℙ ∧ 𝑁 ∈ (ℤ‘2)) → (𝑃𝑐(1 / 𝑁)) ∈ (ℝ ∖ ℚ))
 
20.26.6  Real subtraction
 
Syntaxcresub 40355 Real number subtraction.
class
 
Definitiondf-resub 40356* Define subtraction between real numbers. This operator saves a few axioms over df-sub 11216 in certain situations. Theorem resubval 40357 shows its value, resubadd 40369 relates it to addition, and rersubcl 40368 proves its closure. It is the restriction of df-sub 11216 to the reals: subresre 40419. (Contributed by Steven Nguyen, 7-Jan-2023.)
= (𝑥 ∈ ℝ, 𝑦 ∈ ℝ ↦ (𝑧 ∈ ℝ (𝑦 + 𝑧) = 𝑥))
 
Theoremresubval 40357* Value of real subtraction, which is the (unique) real 𝑥 such that 𝐵 + 𝑥 = 𝐴. (Contributed by Steven Nguyen, 7-Jan-2023.)
((𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ) → (𝐴 𝐵) = (𝑥 ∈ ℝ (𝐵 + 𝑥) = 𝐴))
 
Theoremrenegeulemv 40358* Lemma for renegeu 40360 and similar. Derive existential uniqueness from existence. (Contributed by Steven Nguyen, 28-Jan-2023.)
(𝜑𝐵 ∈ ℝ)    &   (𝜑 → ∃𝑦 ∈ ℝ (𝐵 + 𝑦) = 𝐴)       (𝜑 → ∃!𝑥 ∈ ℝ (𝐵 + 𝑥) = 𝐴)
 
Theoremrenegeulem 40359* Lemma for renegeu 40360 and similar. Remove a change in bound variables from renegeulemv 40358. (Contributed by Steven Nguyen, 28-Jan-2023.)
(𝜑𝐵 ∈ ℝ)    &   (𝜑 → ∃𝑦 ∈ ℝ (𝐵 + 𝑦) = 𝐴)       (𝜑 → ∃!𝑦 ∈ ℝ (𝐵 + 𝑦) = 𝐴)
 
Theoremrenegeu 40360* Existential uniqueness of real negatives. (Contributed by Steven Nguyen, 7-Jan-2023.)
(𝐴 ∈ ℝ → ∃!𝑥 ∈ ℝ (𝐴 + 𝑥) = 0)
 
Theoremrernegcl 40361 Closure law for negative reals. (Contributed by Steven Nguyen, 7-Jan-2023.)
(𝐴 ∈ ℝ → (0 − 𝐴) ∈ ℝ)
 
Theoremrenegadd 40362 Relationship between real negation and addition. (Contributed by Steven Nguyen, 7-Jan-2023.)
((𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ) → ((0 − 𝐴) = 𝐵 ↔ (𝐴 + 𝐵) = 0))
 
Theoremrenegid 40363 Addition of a real number and its negative. (Contributed by Steven Nguyen, 7-Jan-2023.)
(𝐴 ∈ ℝ → (𝐴 + (0 − 𝐴)) = 0)
 
Theoremreneg0addid2 40364 Negative zero is a left additive identity. (Contributed by Steven Nguyen, 7-Jan-2023.)
(𝐴 ∈ ℝ → ((0 − 0) + 𝐴) = 𝐴)
 
Theoremresubeulem1 40365 Lemma for resubeu 40367. A value which when added to zero, results in negative zero. (Contributed by Steven Nguyen, 7-Jan-2023.)
(𝐴 ∈ ℝ → (0 + (0 − (0 + 0))) = (0 − 0))
 
Theoremresubeulem2 40366 Lemma for resubeu 40367. A value which when added to 𝐴, results in 𝐵. (Contributed by Steven Nguyen, 7-Jan-2023.)
((𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ) → (𝐴 + ((0 − 𝐴) + ((0 − (0 + 0)) + 𝐵))) = 𝐵)
 
Theoremresubeu 40367* Existential uniqueness of real differences. (Contributed by Steven Nguyen, 7-Jan-2023.)
((𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ) → ∃!𝑥 ∈ ℝ (𝐴 + 𝑥) = 𝐵)
 
Theoremrersubcl 40368 Closure for real subtraction. Based on subcl 11229. (Contributed by Steven Nguyen, 7-Jan-2023.)
((𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ) → (𝐴 𝐵) ∈ ℝ)
 
Theoremresubadd 40369 Relation between real subtraction and addition. Based on subadd 11233. (Contributed by Steven Nguyen, 7-Jan-2023.)
((𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ ∧ 𝐶 ∈ ℝ) → ((𝐴 𝐵) = 𝐶 ↔ (𝐵 + 𝐶) = 𝐴))
 
Theoremresubaddd 40370 Relationship between subtraction and addition. Based on subaddd 11359. (Contributed by Steven Nguyen, 8-Jan-2023.)
(𝜑𝐴 ∈ ℝ)    &   (𝜑𝐵 ∈ ℝ)    &   (𝜑𝐶 ∈ ℝ)       (𝜑 → ((𝐴 𝐵) = 𝐶 ↔ (𝐵 + 𝐶) = 𝐴))
 
Theoremresubf 40371 Real subtraction is an operation on the real numbers. Based on subf 11232. (Contributed by Steven Nguyen, 7-Jan-2023.)
:(ℝ × ℝ)⟶ℝ
 
Theoremrepncan2 40372 Addition and subtraction of equals. Compare pncan2 11237. (Contributed by Steven Nguyen, 8-Jan-2023.)
((𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ) → ((𝐴 + 𝐵) − 𝐴) = 𝐵)
 
Theoremrepncan3 40373 Addition and subtraction of equals. Based on pncan3 11238. (Contributed by Steven Nguyen, 8-Jan-2023.)
((𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ) → (𝐴 + (𝐵 𝐴)) = 𝐵)
 
Theoremreaddsub 40374 Law for addition and subtraction. (Contributed by Steven Nguyen, 28-Jan-2023.)
((𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ ∧ 𝐶 ∈ ℝ) → ((𝐴 + 𝐵) − 𝐶) = ((𝐴 𝐶) + 𝐵))
 
Theoremreladdrsub 40375 Move LHS of a sum into RHS of a (real) difference. Version of mvlladdd 11395 with real subtraction. (Contributed by Steven Nguyen, 8-Jan-2023.)
(𝜑𝐴 ∈ ℝ)    &   (𝜑𝐵 ∈ ℝ)    &   (𝜑 → (𝐴 + 𝐵) = 𝐶)       (𝜑𝐵 = (𝐶 𝐴))
 
Theoremreltsub1 40376 Subtraction from both sides of 'less than'. Compare ltsub1 11480. (Contributed by SN, 13-Feb-2024.)
((𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ ∧ 𝐶 ∈ ℝ) → (𝐴 < 𝐵 ↔ (𝐴 𝐶) < (𝐵 𝐶)))
 
Theoremreltsubadd2 40377 'Less than' relationship between addition and subtraction. Compare ltsubadd2 11455. (Contributed by SN, 13-Feb-2024.)
((𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ ∧ 𝐶 ∈ ℝ) → ((𝐴 𝐵) < 𝐶𝐴 < (𝐵 + 𝐶)))
 
Theoremresubcan2 40378 Cancellation law for real subtraction. Compare subcan2 11255. (Contributed by Steven Nguyen, 8-Jan-2023.)
((𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ ∧ 𝐶 ∈ ℝ) → ((𝐴 𝐶) = (𝐵 𝐶) ↔ 𝐴 = 𝐵))
 
Theoremresubsub4 40379 Law for double subtraction. Compare subsub4 11263. (Contributed by Steven Nguyen, 14-Jan-2023.)
((𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ ∧ 𝐶 ∈ ℝ) → ((𝐴 𝐵) − 𝐶) = (𝐴 (𝐵 + 𝐶)))
 
Theoremrennncan2 40380 Cancellation law for real subtraction. Compare nnncan2 11267. (Contributed by Steven Nguyen, 14-Jan-2023.)
((𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ ∧ 𝐶 ∈ ℝ) → ((𝐴 𝐶) − (𝐵 𝐶)) = (𝐴 𝐵))
 
Theoremrenpncan3 40381 Cancellation law for real subtraction. Compare npncan3 11268. (Contributed by Steven Nguyen, 28-Jan-2023.)
((𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ ∧ 𝐶 ∈ ℝ) → ((𝐴 𝐵) + (𝐶 𝐴)) = (𝐶 𝐵))
 
Theoremrepnpcan 40382 Cancellation law for addition and real subtraction. Compare pnpcan 11269. (Contributed by Steven Nguyen, 19-May-2023.)
((𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ ∧ 𝐶 ∈ ℝ) → ((𝐴 + 𝐵) − (𝐴 + 𝐶)) = (𝐵 𝐶))
 
Theoremreppncan 40383 Cancellation law for mixed addition and real subtraction. Compare ppncan 11272. (Contributed by SN, 3-Sep-2023.)
((𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ ∧ 𝐶 ∈ ℝ) → ((𝐴 + 𝐶) + (𝐵 𝐶)) = (𝐴 + 𝐵))
 
Theoremresubidaddid1lem 40384 Lemma for resubidaddid1 40385. A special case of npncan 11251. (Contributed by Steven Nguyen, 8-Jan-2023.)
(𝜑𝐴 ∈ ℝ)    &   (𝜑𝐵 ∈ ℝ)    &   (𝜑𝐶 ∈ ℝ)    &   (𝜑 → (𝐴 𝐵) = (𝐵 𝐶))       (𝜑 → ((𝐴 𝐵) + (𝐵 𝐶)) = (𝐴 𝐶))
 
Theoremresubidaddid1 40385 Any real number subtracted from itself forms a left additive identity. (Contributed by Steven Nguyen, 8-Jan-2023.)
((𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ) → ((𝐴 𝐴) + 𝐵) = 𝐵)
 
Theoremresubdi 40386 Distribution of multiplication over real subtraction. (Contributed by Steven Nguyen, 3-Jun-2023.)
((𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ ∧ 𝐶 ∈ ℝ) → (𝐴 · (𝐵 𝐶)) = ((𝐴 · 𝐵) − (𝐴 · 𝐶)))
 
Theoremre1m1e0m0 40387 Equality of two left-additive identities. See resubidaddid1 40385. Uses ax-i2m1 10948. (Contributed by SN, 25-Dec-2023.)
(1 − 1) = (0 − 0)
 
Theoremsn-00idlem1 40388 Lemma for sn-00id 40391. (Contributed by SN, 25-Dec-2023.)
(𝐴 ∈ ℝ → (𝐴 · (0 − 0)) = (𝐴 𝐴))
 
Theoremsn-00idlem2 40389 Lemma for sn-00id 40391. (Contributed by SN, 25-Dec-2023.)
((0 − 0) ≠ 0 → (0 − 0) = 1)
 
Theoremsn-00idlem3 40390 Lemma for sn-00id 40391. (Contributed by SN, 25-Dec-2023.)
((0 − 0) = 1 → (0 + 0) = 0)
 
Theoremsn-00id 40391 00id 11159 proven without ax-mulcom 10944 but using ax-1ne0 10949. (Though note that the current version of 00id 11159 can be changed to avoid ax-icn 10939, ax-addcl 10940, ax-mulcl 10942, ax-i2m1 10948, ax-cnre 10953. Most of this is by using 0cnALT3 40297 instead of 0cn 10976). (Contributed by SN, 25-Dec-2023.) (Proof modification is discouraged.)
(0 + 0) = 0
 
Theoremre0m0e0 40392 Real number version of 0m0e0 12102 proven without ax-mulcom 10944. (Contributed by SN, 23-Jan-2024.)
(0 − 0) = 0
 
Theoremreaddid2 40393 Real number version of addid2 11167. (Contributed by SN, 23-Jan-2024.)
(𝐴 ∈ ℝ → (0 + 𝐴) = 𝐴)
 
Theoremsn-addid2 40394 addid2 11167 without ax-mulcom 10944. (Contributed by SN, 23-Jan-2024.)
(𝐴 ∈ ℂ → (0 + 𝐴) = 𝐴)
 
Theoremremul02 40395 Real number version of mul02 11162 proven without ax-mulcom 10944. (Contributed by SN, 23-Jan-2024.)
(𝐴 ∈ ℝ → (0 · 𝐴) = 0)
 
Theoremsn-0ne2 40396 0ne2 12189 without ax-mulcom 10944. (Contributed by SN, 23-Jan-2024.)
0 ≠ 2
 
Theoremremul01 40397 Real number version of mul01 11163 proven without ax-mulcom 10944. (Contributed by SN, 23-Jan-2024.)
(𝐴 ∈ ℝ → (𝐴 · 0) = 0)
 
Theoremresubid 40398 Subtraction of a real number from itself (compare subid 11249). (Contributed by SN, 23-Jan-2024.)
(𝐴 ∈ ℝ → (𝐴 𝐴) = 0)
 
Theoremreaddid1 40399 Real number version of addid1 11164, without ax-mulcom 10944. (Contributed by SN, 23-Jan-2024.)
(𝐴 ∈ ℝ → (𝐴 + 0) = 𝐴)
 
Theoremresubid1 40400 Real number version of subid1 11250, without ax-mulcom 10944. (Contributed by SN, 23-Jan-2024.)
(𝐴 ∈ ℝ → (𝐴 0) = 𝐴)
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