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Type | Label | Description |
---|---|---|
Statement | ||
Theorem | bitr 801 | Theorem *4.22 of [WhiteheadRussell] p. 117. bitri 274 in closed form. (Contributed by NM, 3-Jan-2005.) |
⊢ (((𝜑 ↔ 𝜓) ∧ (𝜓 ↔ 𝜒)) → (𝜑 ↔ 𝜒)) | ||
Theorem | biantr 802 | A transitive law of equivalence. Compare Theorem *4.22 of [WhiteheadRussell] p. 117. (Contributed by NM, 18-Aug-1993.) |
⊢ (((𝜑 ↔ 𝜓) ∧ (𝜒 ↔ 𝜓)) → (𝜑 ↔ 𝜒)) | ||
Theorem | pm4.14 803 | Theorem *4.14 of [WhiteheadRussell] p. 117. Related to con34b 315. (Contributed by NM, 3-Jan-2005.) (Proof shortened by Wolf Lammen, 23-Oct-2012.) |
⊢ (((𝜑 ∧ 𝜓) → 𝜒) ↔ ((𝜑 ∧ ¬ 𝜒) → ¬ 𝜓)) | ||
Theorem | pm3.37 804 | Theorem *3.37 (Transp) of [WhiteheadRussell] p. 112. (Contributed by NM, 3-Jan-2005.) (Proof shortened by Wolf Lammen, 23-Oct-2012.) |
⊢ (((𝜑 ∧ 𝜓) → 𝜒) → ((𝜑 ∧ ¬ 𝜒) → ¬ 𝜓)) | ||
Theorem | anim12 805 | Conjoin antecedents and consequents of two premises. This is the closed theorem form of anim12d 608. Theorem *3.47 of [WhiteheadRussell] p. 113. It was proved by Leibniz, and it evidently pleased him enough to call it praeclarum theorema (splendid theorem). (Contributed by NM, 12-Aug-1993.) (Proof shortened by Wolf Lammen, 7-Apr-2013.) |
⊢ (((𝜑 → 𝜓) ∧ (𝜒 → 𝜃)) → ((𝜑 ∧ 𝜒) → (𝜓 ∧ 𝜃))) | ||
Theorem | pm3.4 806 | Conjunction implies implication. Theorem *3.4 of [WhiteheadRussell] p. 113. (Contributed by NM, 31-Jul-1995.) |
⊢ ((𝜑 ∧ 𝜓) → (𝜑 → 𝜓)) | ||
Theorem | exbiri 807 | Inference form of exbir 41987. This proof is exbiriVD 42363 automatically translated and minimized. (Contributed by Alan Sare, 31-Dec-2011.) (Proof shortened by Wolf Lammen, 27-Jan-2013.) |
⊢ ((𝜑 ∧ 𝜓) → (𝜒 ↔ 𝜃)) ⇒ ⊢ (𝜑 → (𝜓 → (𝜃 → 𝜒))) | ||
Theorem | pm2.61ian 808 | Elimination of an antecedent. (Contributed by NM, 1-Jan-2005.) |
⊢ ((𝜑 ∧ 𝜓) → 𝜒) & ⊢ ((¬ 𝜑 ∧ 𝜓) → 𝜒) ⇒ ⊢ (𝜓 → 𝜒) | ||
Theorem | pm2.61dan 809 | Elimination of an antecedent. (Contributed by NM, 1-Jan-2005.) |
⊢ ((𝜑 ∧ 𝜓) → 𝜒) & ⊢ ((𝜑 ∧ ¬ 𝜓) → 𝜒) ⇒ ⊢ (𝜑 → 𝜒) | ||
Theorem | pm2.61ddan 810 | Elimination of two antecedents. (Contributed by NM, 9-Jul-2013.) |
⊢ ((𝜑 ∧ 𝜓) → 𝜃) & ⊢ ((𝜑 ∧ 𝜒) → 𝜃) & ⊢ ((𝜑 ∧ (¬ 𝜓 ∧ ¬ 𝜒)) → 𝜃) ⇒ ⊢ (𝜑 → 𝜃) | ||
Theorem | pm2.61dda 811 | Elimination of two antecedents. (Contributed by NM, 9-Jul-2013.) |
⊢ ((𝜑 ∧ ¬ 𝜓) → 𝜃) & ⊢ ((𝜑 ∧ ¬ 𝜒) → 𝜃) & ⊢ ((𝜑 ∧ (𝜓 ∧ 𝜒)) → 𝜃) ⇒ ⊢ (𝜑 → 𝜃) | ||
Theorem | mtand 812 | A modus tollens deduction. (Contributed by Jeff Hankins, 19-Aug-2009.) |
⊢ (𝜑 → ¬ 𝜒) & ⊢ ((𝜑 ∧ 𝜓) → 𝜒) ⇒ ⊢ (𝜑 → ¬ 𝜓) | ||
Theorem | pm2.65da 813 | Deduction for proof by contradiction. (Contributed by NM, 12-Jun-2014.) |
⊢ ((𝜑 ∧ 𝜓) → 𝜒) & ⊢ ((𝜑 ∧ 𝜓) → ¬ 𝜒) ⇒ ⊢ (𝜑 → ¬ 𝜓) | ||
Theorem | condan 814 | Proof by contradiction. (Contributed by NM, 9-Feb-2006.) (Proof shortened by Wolf Lammen, 19-Jun-2014.) |
⊢ ((𝜑 ∧ ¬ 𝜓) → 𝜒) & ⊢ ((𝜑 ∧ ¬ 𝜓) → ¬ 𝜒) ⇒ ⊢ (𝜑 → 𝜓) | ||
Theorem | biadan 815 | An implication is equivalent to the equivalence of some implied equivalence and some other equivalence involving a conjunction. A utility lemma as illustrated in biadanii 818 and elelb 35009. (Contributed by BJ, 4-Mar-2023.) (Proof shortened by Wolf Lammen, 8-Mar-2023.) |
⊢ ((𝜑 → 𝜓) ↔ ((𝜓 → (𝜑 ↔ 𝜒)) ↔ (𝜑 ↔ (𝜓 ∧ 𝜒)))) | ||
Theorem | biadani 816 | Inference associated with biadan 815. (Contributed by BJ, 4-Mar-2023.) |
⊢ (𝜑 → 𝜓) ⇒ ⊢ ((𝜓 → (𝜑 ↔ 𝜒)) ↔ (𝜑 ↔ (𝜓 ∧ 𝜒))) | ||
Theorem | biadaniALT 817 | Alternate proof of biadani 816 not using biadan 815. (Contributed by BJ, 4-Mar-2023.) (Proof modification is discouraged.) (New usage is discouraged.) |
⊢ (𝜑 → 𝜓) ⇒ ⊢ ((𝜓 → (𝜑 ↔ 𝜒)) ↔ (𝜑 ↔ (𝜓 ∧ 𝜒))) | ||
Theorem | biadanii 818 | Inference associated with biadani 816. Add a conjunction to an equivalence. (Contributed by Jeff Madsen, 20-Jun-2011.) (Proof shortened by BJ, 4-Mar-2023.) |
⊢ (𝜑 → 𝜓) & ⊢ (𝜓 → (𝜑 ↔ 𝜒)) ⇒ ⊢ (𝜑 ↔ (𝜓 ∧ 𝜒)) | ||
Theorem | biadanid 819 | Deduction associated with biadani 816. Add a conjunction to an equivalence. (Contributed by Thierry Arnoux, 16-Jun-2024.) |
⊢ ((𝜑 ∧ 𝜓) → 𝜒) & ⊢ ((𝜑 ∧ 𝜒) → (𝜓 ↔ 𝜃)) ⇒ ⊢ (𝜑 → (𝜓 ↔ (𝜒 ∧ 𝜃))) | ||
Theorem | pm5.1 820 | Two propositions are equivalent if they are both true. Theorem *5.1 of [WhiteheadRussell] p. 123. (Contributed by NM, 21-May-1994.) |
⊢ ((𝜑 ∧ 𝜓) → (𝜑 ↔ 𝜓)) | ||
Theorem | pm5.21 821 | Two propositions are equivalent if they are both false. Theorem *5.21 of [WhiteheadRussell] p. 124. (Contributed by NM, 21-May-1994.) |
⊢ ((¬ 𝜑 ∧ ¬ 𝜓) → (𝜑 ↔ 𝜓)) | ||
Theorem | pm5.35 822 | Theorem *5.35 of [WhiteheadRussell] p. 125. Closed form of 2thd 264. (Contributed by NM, 3-Jan-2005.) |
⊢ (((𝜑 → 𝜓) ∧ (𝜑 → 𝜒)) → (𝜑 → (𝜓 ↔ 𝜒))) | ||
Theorem | abai 823 | Introduce one conjunct as an antecedent to the other. "abai" stands for "and, biconditional, and, implication". (Contributed by NM, 12-Aug-1993.) (Proof shortened by Wolf Lammen, 7-Dec-2012.) |
⊢ ((𝜑 ∧ 𝜓) ↔ (𝜑 ∧ (𝜑 → 𝜓))) | ||
Theorem | pm4.45im 824 | Conjunction with implication. Compare Theorem *4.45 of [WhiteheadRussell] p. 119. (Contributed by NM, 17-May-1998.) |
⊢ (𝜑 ↔ (𝜑 ∧ (𝜓 → 𝜑))) | ||
Theorem | impimprbi 825 | An implication and its reverse are equivalent exactly when both operands are equivalent. The right hand side resembles that of dfbi2 474, but ↔ is a weaker operator than ∧. Note that an implication and its reverse can never be simultaneously false, because of pm2.521 176. (Contributed by Wolf Lammen, 18-Dec-2023.) |
⊢ ((𝜑 ↔ 𝜓) ↔ ((𝜑 → 𝜓) ↔ (𝜓 → 𝜑))) | ||
Theorem | nan 826 | Theorem to move a conjunct in and out of a negation. (Contributed by NM, 9-Nov-2003.) |
⊢ ((𝜑 → ¬ (𝜓 ∧ 𝜒)) ↔ ((𝜑 ∧ 𝜓) → ¬ 𝜒)) | ||
Theorem | pm5.31 827 | Theorem *5.31 of [WhiteheadRussell] p. 125. (Contributed by NM, 3-Jan-2005.) |
⊢ ((𝜒 ∧ (𝜑 → 𝜓)) → (𝜑 → (𝜓 ∧ 𝜒))) | ||
Theorem | pm5.31r 828 | Variant of pm5.31 827. (Contributed by Rodolfo Medina, 15-Oct-2010.) |
⊢ ((𝜒 ∧ (𝜑 → 𝜓)) → (𝜑 → (𝜒 ∧ 𝜓))) | ||
Theorem | pm4.15 829 | Theorem *4.15 of [WhiteheadRussell] p. 117. (Contributed by NM, 3-Jan-2005.) (Proof shortened by Wolf Lammen, 18-Nov-2012.) |
⊢ (((𝜑 ∧ 𝜓) → ¬ 𝜒) ↔ ((𝜓 ∧ 𝜒) → ¬ 𝜑)) | ||
Theorem | pm5.36 830 | Theorem *5.36 of [WhiteheadRussell] p. 125. (Contributed by NM, 3-Jan-2005.) |
⊢ ((𝜑 ∧ (𝜑 ↔ 𝜓)) ↔ (𝜓 ∧ (𝜑 ↔ 𝜓))) | ||
Theorem | annotanannot 831 | A conjunction with a negated conjunction. (Contributed by AV, 8-Mar-2022.) (Proof shortened by Wolf Lammen, 1-Apr-2022.) |
⊢ ((𝜑 ∧ ¬ (𝜑 ∧ 𝜓)) ↔ (𝜑 ∧ ¬ 𝜓)) | ||
Theorem | pm5.33 832 | Theorem *5.33 of [WhiteheadRussell] p. 125. (Contributed by NM, 3-Jan-2005.) |
⊢ ((𝜑 ∧ (𝜓 → 𝜒)) ↔ (𝜑 ∧ ((𝜑 ∧ 𝜓) → 𝜒))) | ||
Theorem | syl12anc 833 | Syllogism combined with contraction. (Contributed by Jeff Hankins, 1-Aug-2009.) |
⊢ (𝜑 → 𝜓) & ⊢ (𝜑 → 𝜒) & ⊢ (𝜑 → 𝜃) & ⊢ ((𝜓 ∧ (𝜒 ∧ 𝜃)) → 𝜏) ⇒ ⊢ (𝜑 → 𝜏) | ||
Theorem | syl21anc 834 | Syllogism combined with contraction. (Contributed by Jeff Hankins, 1-Aug-2009.) |
⊢ (𝜑 → 𝜓) & ⊢ (𝜑 → 𝜒) & ⊢ (𝜑 → 𝜃) & ⊢ (((𝜓 ∧ 𝜒) ∧ 𝜃) → 𝜏) ⇒ ⊢ (𝜑 → 𝜏) | ||
Theorem | syl22anc 835 | Syllogism combined with contraction. (Contributed by NM, 11-Mar-2012.) |
⊢ (𝜑 → 𝜓) & ⊢ (𝜑 → 𝜒) & ⊢ (𝜑 → 𝜃) & ⊢ (𝜑 → 𝜏) & ⊢ (((𝜓 ∧ 𝜒) ∧ (𝜃 ∧ 𝜏)) → 𝜂) ⇒ ⊢ (𝜑 → 𝜂) | ||
Theorem | syl1111anc 836 | Four-hypothesis elimination deduction for an assertion with a singleton virtual hypothesis collection. Similar to syl112anc 1372 except the unification theorem uses left-nested conjunction. (Contributed by Alan Sare, 17-Oct-2017.) |
⊢ (𝜑 → 𝜓) & ⊢ (𝜑 → 𝜒) & ⊢ (𝜑 → 𝜃) & ⊢ (𝜑 → 𝜏) & ⊢ ((((𝜓 ∧ 𝜒) ∧ 𝜃) ∧ 𝜏) → 𝜂) ⇒ ⊢ (𝜑 → 𝜂) | ||
Theorem | syldbl2 837 | Stacked hypotheseis implies goal. (Contributed by Stanislas Polu, 9-Mar-2020.) |
⊢ ((𝜑 ∧ 𝜓) → (𝜓 → 𝜃)) ⇒ ⊢ ((𝜑 ∧ 𝜓) → 𝜃) | ||
Theorem | mpsyl4anc 838 | An elimination deduction. (Contributed by Alan Sare, 17-Oct-2017.) |
⊢ 𝜑 & ⊢ 𝜓 & ⊢ 𝜒 & ⊢ (𝜃 → 𝜏) & ⊢ ((((𝜑 ∧ 𝜓) ∧ 𝜒) ∧ 𝜏) → 𝜂) ⇒ ⊢ (𝜃 → 𝜂) | ||
Theorem | pm4.87 839 | Theorem *4.87 of [WhiteheadRussell] p. 122. (Contributed by NM, 3-Jan-2005.) (Proof shortened by Eric Schmidt, 26-Oct-2006.) |
⊢ (((((𝜑 ∧ 𝜓) → 𝜒) ↔ (𝜑 → (𝜓 → 𝜒))) ∧ ((𝜑 → (𝜓 → 𝜒)) ↔ (𝜓 → (𝜑 → 𝜒)))) ∧ ((𝜓 → (𝜑 → 𝜒)) ↔ ((𝜓 ∧ 𝜑) → 𝜒))) | ||
Theorem | bimsc1 840 | Removal of conjunct from one side of an equivalence. (Contributed by NM, 21-Jun-1993.) |
⊢ (((𝜑 → 𝜓) ∧ (𝜒 ↔ (𝜓 ∧ 𝜑))) → (𝜒 ↔ 𝜑)) | ||
Theorem | a2and 841 | Deduction distributing a conjunction as embedded antecedent. (Contributed by AV, 25-Oct-2019.) (Proof shortened by Wolf Lammen, 19-Jan-2020.) |
⊢ (𝜑 → ((𝜓 ∧ 𝜌) → (𝜏 → 𝜃))) & ⊢ (𝜑 → ((𝜓 ∧ 𝜌) → 𝜒)) ⇒ ⊢ (𝜑 → (((𝜓 ∧ 𝜒) → 𝜏) → ((𝜓 ∧ 𝜌) → 𝜃))) | ||
Theorem | animpimp2impd 842 | Deduction deriving nested implications from conjunctions. (Contributed by AV, 21-Aug-2022.) |
⊢ ((𝜓 ∧ 𝜑) → (𝜒 → (𝜃 → 𝜂))) & ⊢ ((𝜓 ∧ (𝜑 ∧ 𝜃)) → (𝜂 → 𝜏)) ⇒ ⊢ (𝜑 → ((𝜓 → 𝜒) → (𝜓 → (𝜃 → 𝜏)))) | ||
This section defines disjunction of two formulas, denoted by infix "∨ " and read "or". It is defined in terms of implication and negation, which is possible in classical logic (but not in intuitionistic logic: see iset.mm). This section contains only theorems proved without df-an 396 (theorems that are proved using df-an 396 are deferred to the next section). Basic theorems that help simplifying and applying disjunction are olc 864, orc 863, and orcom 866. As mentioned in the "note on definitions" in the section comment for logical equivalence, all theorems in this and the previous section can be stated in terms of implication and negation only. Additionally, in classical logic (but not in intuitionistic logic: see iset.mm), it is also possible to translate conjunction into disjunction and conversely via the De Morgan law anor 979: conjunction and disjunction are dual connectives. Either is sufficient to develop all propositional calculus of the logic (together with implication and negation). In practice, conjunction is more efficient, its big advantage being the possibility to use it to group antecedents in a convenient way, using imp 406 and ex 412 as noted in the previous section. An illustration of the conservativity of df-an 396 is given by orim12dALT 908, which is an alternate proof of orim12d 961 not using df-an 396. | ||
Syntax | wo 843 | Extend wff definition to include disjunction ("or"). |
wff (𝜑 ∨ 𝜓) | ||
Definition | df-or 844 |
Define disjunction (logical "or"). Definition of [Margaris] p. 49. When
the left operand, right operand, or both are true, the result is true;
when both sides are false, the result is false. For example, it is true
that (2 = 3 ∨ 4 = 4) (ex-or 28686). After we define the constant
true ⊤ (df-tru 1542) and the constant false ⊥ (df-fal 1552), we
will be able to prove these truth table values:
((⊤ ∨ ⊤) ↔ ⊤) (truortru 1576), ((⊤ ∨ ⊥)
↔ ⊤)
(truorfal 1577), ((⊥ ∨ ⊤)
↔ ⊤) (falortru 1578), and
((⊥ ∨ ⊥) ↔ ⊥) (falorfal 1579).
Contrast with ∧ (df-an 396), → (wi 4), ⊼ (df-nan 1484), and ⊻ (df-xor 1504). (Contributed by NM, 27-Dec-1992.) |
⊢ ((𝜑 ∨ 𝜓) ↔ (¬ 𝜑 → 𝜓)) | ||
Theorem | pm4.64 845 | Theorem *4.64 of [WhiteheadRussell] p. 120. (Contributed by NM, 3-Jan-2005.) |
⊢ ((¬ 𝜑 → 𝜓) ↔ (𝜑 ∨ 𝜓)) | ||
Theorem | pm4.66 846 | Theorem *4.66 of [WhiteheadRussell] p. 120. (Contributed by NM, 3-Jan-2005.) |
⊢ ((¬ 𝜑 → ¬ 𝜓) ↔ (𝜑 ∨ ¬ 𝜓)) | ||
Theorem | pm2.53 847 | Theorem *2.53 of [WhiteheadRussell] p. 107. (Contributed by NM, 3-Jan-2005.) |
⊢ ((𝜑 ∨ 𝜓) → (¬ 𝜑 → 𝜓)) | ||
Theorem | pm2.54 848 | Theorem *2.54 of [WhiteheadRussell] p. 107. (Contributed by NM, 3-Jan-2005.) |
⊢ ((¬ 𝜑 → 𝜓) → (𝜑 ∨ 𝜓)) | ||
Theorem | imor 849 | Implication in terms of disjunction. Theorem *4.6 of [WhiteheadRussell] p. 120. (Contributed by NM, 3-Jan-1993.) |
⊢ ((𝜑 → 𝜓) ↔ (¬ 𝜑 ∨ 𝜓)) | ||
Theorem | imori 850 | Infer disjunction from implication. (Contributed by NM, 12-Mar-2012.) |
⊢ (𝜑 → 𝜓) ⇒ ⊢ (¬ 𝜑 ∨ 𝜓) | ||
Theorem | imorri 851 | Infer implication from disjunction. (Contributed by Jonathan Ben-Naim, 3-Jun-2011.) |
⊢ (¬ 𝜑 ∨ 𝜓) ⇒ ⊢ (𝜑 → 𝜓) | ||
Theorem | pm4.62 852 | Theorem *4.62 of [WhiteheadRussell] p. 120. (Contributed by NM, 3-Jan-2005.) |
⊢ ((𝜑 → ¬ 𝜓) ↔ (¬ 𝜑 ∨ ¬ 𝜓)) | ||
Theorem | jaoi 853 | Inference disjoining the antecedents of two implications. (Contributed by NM, 5-Apr-1994.) |
⊢ (𝜑 → 𝜓) & ⊢ (𝜒 → 𝜓) ⇒ ⊢ ((𝜑 ∨ 𝜒) → 𝜓) | ||
Theorem | jao1i 854 | Add a disjunct in the antecedent of an implication. (Contributed by Rodolfo Medina, 24-Sep-2010.) |
⊢ (𝜓 → (𝜒 → 𝜑)) ⇒ ⊢ ((𝜑 ∨ 𝜓) → (𝜒 → 𝜑)) | ||
Theorem | jaod 855 | Deduction disjoining the antecedents of two implications. (Contributed by NM, 18-Aug-1994.) |
⊢ (𝜑 → (𝜓 → 𝜒)) & ⊢ (𝜑 → (𝜃 → 𝜒)) ⇒ ⊢ (𝜑 → ((𝜓 ∨ 𝜃) → 𝜒)) | ||
Theorem | mpjaod 856 | Eliminate a disjunction in a deduction. (Contributed by Mario Carneiro, 29-May-2016.) |
⊢ (𝜑 → (𝜓 → 𝜒)) & ⊢ (𝜑 → (𝜃 → 𝜒)) & ⊢ (𝜑 → (𝜓 ∨ 𝜃)) ⇒ ⊢ (𝜑 → 𝜒) | ||
Theorem | ori 857 | Infer implication from disjunction. (Contributed by NM, 11-Jun-1994.) |
⊢ (𝜑 ∨ 𝜓) ⇒ ⊢ (¬ 𝜑 → 𝜓) | ||
Theorem | orri 858 | Infer disjunction from implication. (Contributed by NM, 11-Jun-1994.) |
⊢ (¬ 𝜑 → 𝜓) ⇒ ⊢ (𝜑 ∨ 𝜓) | ||
Theorem | orrd 859 | Deduce disjunction from implication. (Contributed by NM, 27-Nov-1995.) |
⊢ (𝜑 → (¬ 𝜓 → 𝜒)) ⇒ ⊢ (𝜑 → (𝜓 ∨ 𝜒)) | ||
Theorem | ord 860 | Deduce implication from disjunction. (Contributed by NM, 18-May-1994.) |
⊢ (𝜑 → (𝜓 ∨ 𝜒)) ⇒ ⊢ (𝜑 → (¬ 𝜓 → 𝜒)) | ||
Theorem | orci 861 | Deduction introducing a disjunct. (Contributed by NM, 19-Jan-2008.) (Proof shortened by Wolf Lammen, 14-Nov-2012.) |
⊢ 𝜑 ⇒ ⊢ (𝜑 ∨ 𝜓) | ||
Theorem | olci 862 | Deduction introducing a disjunct. (Contributed by NM, 19-Jan-2008.) (Proof shortened by Wolf Lammen, 14-Nov-2012.) |
⊢ 𝜑 ⇒ ⊢ (𝜓 ∨ 𝜑) | ||
Theorem | orc 863 | Introduction of a disjunct. Theorem *2.2 of [WhiteheadRussell] p. 104. (Contributed by NM, 30-Aug-1993.) |
⊢ (𝜑 → (𝜑 ∨ 𝜓)) | ||
Theorem | olc 864 | Introduction of a disjunct. Axiom *1.3 of [WhiteheadRussell] p. 96. (Contributed by NM, 30-Aug-1993.) |
⊢ (𝜑 → (𝜓 ∨ 𝜑)) | ||
Theorem | pm1.4 865 | Axiom *1.4 of [WhiteheadRussell] p. 96. (Contributed by NM, 3-Jan-2005.) |
⊢ ((𝜑 ∨ 𝜓) → (𝜓 ∨ 𝜑)) | ||
Theorem | orcom 866 | Commutative law for disjunction. Theorem *4.31 of [WhiteheadRussell] p. 118. (Contributed by NM, 3-Jan-1993.) (Proof shortened by Wolf Lammen, 15-Nov-2012.) |
⊢ ((𝜑 ∨ 𝜓) ↔ (𝜓 ∨ 𝜑)) | ||
Theorem | orcomd 867 | Commutation of disjuncts in consequent. (Contributed by NM, 2-Dec-2010.) |
⊢ (𝜑 → (𝜓 ∨ 𝜒)) ⇒ ⊢ (𝜑 → (𝜒 ∨ 𝜓)) | ||
Theorem | orcoms 868 | Commutation of disjuncts in antecedent. (Contributed by NM, 2-Dec-2012.) |
⊢ ((𝜑 ∨ 𝜓) → 𝜒) ⇒ ⊢ ((𝜓 ∨ 𝜑) → 𝜒) | ||
Theorem | orcd 869 | Deduction introducing a disjunct. A translation of natural deduction rule ∨ IR (∨ insertion right), see natded 28668. (Contributed by NM, 20-Sep-2007.) |
⊢ (𝜑 → 𝜓) ⇒ ⊢ (𝜑 → (𝜓 ∨ 𝜒)) | ||
Theorem | olcd 870 | Deduction introducing a disjunct. A translation of natural deduction rule ∨ IL (∨ insertion left), see natded 28668. (Contributed by NM, 11-Apr-2008.) (Proof shortened by Wolf Lammen, 3-Oct-2013.) |
⊢ (𝜑 → 𝜓) ⇒ ⊢ (𝜑 → (𝜒 ∨ 𝜓)) | ||
Theorem | orcs 871 | Deduction eliminating disjunct. Notational convention: We sometimes suffix with "s" the label of an inference that manipulates an antecedent, leaving the consequent unchanged. The "s" means that the inference eliminates the need for a syllogism (syl 17) -type inference in a proof. (Contributed by NM, 21-Jun-1994.) |
⊢ ((𝜑 ∨ 𝜓) → 𝜒) ⇒ ⊢ (𝜑 → 𝜒) | ||
Theorem | olcs 872 | Deduction eliminating disjunct. (Contributed by NM, 21-Jun-1994.) (Proof shortened by Wolf Lammen, 3-Oct-2013.) |
⊢ ((𝜑 ∨ 𝜓) → 𝜒) ⇒ ⊢ (𝜓 → 𝜒) | ||
Theorem | olcnd 873 | A lemma for Conjunctive Normal Form unit propagation, in deduction form. (Contributed by Giovanni Mascellani, 15-Sep-2017.) (Proof shortened by Wolf Lammen, 13-Apr-2024.) |
⊢ (𝜑 → (𝜓 ∨ 𝜒)) & ⊢ (𝜑 → ¬ 𝜒) ⇒ ⊢ (𝜑 → 𝜓) | ||
Theorem | unitreslOLD 874 | Obsolete version of olcnd 873 as of 13-Apr-2024. (Contributed by Giovanni Mascellani, 15-Sep-2017.) (Proof modification is discouraged.) (New usage is discouraged.) |
⊢ (𝜑 → (𝜓 ∨ 𝜒)) & ⊢ (𝜑 → ¬ 𝜒) ⇒ ⊢ (𝜑 → 𝜓) | ||
Theorem | orcnd 875 | A lemma for Conjunctive Normal Form unit propagation, in deduction form. (Contributed by Giovanni Mascellani, 15-Sep-2017.) |
⊢ (𝜑 → (𝜓 ∨ 𝜒)) & ⊢ (𝜑 → ¬ 𝜓) ⇒ ⊢ (𝜑 → 𝜒) | ||
Theorem | mtord 876 | A modus tollens deduction involving disjunction. (Contributed by Jeff Hankins, 15-Jul-2009.) |
⊢ (𝜑 → ¬ 𝜒) & ⊢ (𝜑 → ¬ 𝜃) & ⊢ (𝜑 → (𝜓 → (𝜒 ∨ 𝜃))) ⇒ ⊢ (𝜑 → ¬ 𝜓) | ||
Theorem | pm3.2ni 877 | Infer negated disjunction of negated premises. (Contributed by NM, 4-Apr-1995.) |
⊢ ¬ 𝜑 & ⊢ ¬ 𝜓 ⇒ ⊢ ¬ (𝜑 ∨ 𝜓) | ||
Theorem | pm2.45 878 | Theorem *2.45 of [WhiteheadRussell] p. 106. (Contributed by NM, 3-Jan-2005.) |
⊢ (¬ (𝜑 ∨ 𝜓) → ¬ 𝜑) | ||
Theorem | pm2.46 879 | Theorem *2.46 of [WhiteheadRussell] p. 106. (Contributed by NM, 3-Jan-2005.) |
⊢ (¬ (𝜑 ∨ 𝜓) → ¬ 𝜓) | ||
Theorem | pm2.47 880 | Theorem *2.47 of [WhiteheadRussell] p. 107. (Contributed by NM, 3-Jan-2005.) |
⊢ (¬ (𝜑 ∨ 𝜓) → (¬ 𝜑 ∨ 𝜓)) | ||
Theorem | pm2.48 881 | Theorem *2.48 of [WhiteheadRussell] p. 107. (Contributed by NM, 3-Jan-2005.) |
⊢ (¬ (𝜑 ∨ 𝜓) → (𝜑 ∨ ¬ 𝜓)) | ||
Theorem | pm2.49 882 | Theorem *2.49 of [WhiteheadRussell] p. 107. (Contributed by NM, 3-Jan-2005.) |
⊢ (¬ (𝜑 ∨ 𝜓) → (¬ 𝜑 ∨ ¬ 𝜓)) | ||
Theorem | norbi 883 | If neither of two propositions is true, then these propositions are equivalent. (Contributed by BJ, 26-Apr-2019.) |
⊢ (¬ (𝜑 ∨ 𝜓) → (𝜑 ↔ 𝜓)) | ||
Theorem | nbior 884 | If two propositions are not equivalent, then at least one is true. (Contributed by BJ, 19-Apr-2019.) (Proof shortened by Wolf Lammen, 19-Jan-2020.) |
⊢ (¬ (𝜑 ↔ 𝜓) → (𝜑 ∨ 𝜓)) | ||
Theorem | orel1 885 | Elimination of disjunction by denial of a disjunct. Theorem *2.55 of [WhiteheadRussell] p. 107. (Contributed by NM, 12-Aug-1994.) (Proof shortened by Wolf Lammen, 21-Jul-2012.) |
⊢ (¬ 𝜑 → ((𝜑 ∨ 𝜓) → 𝜓)) | ||
Theorem | pm2.25 886 | Theorem *2.25 of [WhiteheadRussell] p. 104. (Contributed by NM, 3-Jan-2005.) |
⊢ (𝜑 ∨ ((𝜑 ∨ 𝜓) → 𝜓)) | ||
Theorem | orel2 887 | Elimination of disjunction by denial of a disjunct. Theorem *2.56 of [WhiteheadRussell] p. 107. (Contributed by NM, 12-Aug-1994.) (Proof shortened by Wolf Lammen, 5-Apr-2013.) |
⊢ (¬ 𝜑 → ((𝜓 ∨ 𝜑) → 𝜓)) | ||
Theorem | pm2.67-2 888 | Slight generalization of Theorem *2.67 of [WhiteheadRussell] p. 107. (Contributed by NM, 3-Jan-2005.) |
⊢ (((𝜑 ∨ 𝜒) → 𝜓) → (𝜑 → 𝜓)) | ||
Theorem | pm2.67 889 | Theorem *2.67 of [WhiteheadRussell] p. 107. (Contributed by NM, 3-Jan-2005.) |
⊢ (((𝜑 ∨ 𝜓) → 𝜓) → (𝜑 → 𝜓)) | ||
Theorem | curryax 890 | A non-intuitionistic positive statement, sometimes called a paradox of material implication. Sometimes called Curry's axiom. Similar to exmid 891 (obtained by substituting ⊥ for 𝜓) but positive. For another non-intuitionistic positive statement, see peirce 201. (Contributed by BJ, 4-Apr-2021.) |
⊢ (𝜑 ∨ (𝜑 → 𝜓)) | ||
Theorem | exmid 891 | Law of excluded middle, also called the principle of tertium non datur. Theorem *2.11 of [WhiteheadRussell] p. 101. It says that something is either true or not true; there are no in-between values of truth. This is an essential distinction of our classical logic and is not a theorem of intuitionistic logic. In intuitionistic logic, if this statement is true for some 𝜑, then 𝜑 is decidable. (Contributed by NM, 29-Dec-1992.) |
⊢ (𝜑 ∨ ¬ 𝜑) | ||
Theorem | exmidd 892 | Law of excluded middle in a context. (Contributed by Mario Carneiro, 9-Feb-2017.) |
⊢ (𝜑 → (𝜓 ∨ ¬ 𝜓)) | ||
Theorem | pm2.1 893 | Theorem *2.1 of [WhiteheadRussell] p. 101. (Contributed by NM, 3-Jan-2005.) (Proof shortened by Wolf Lammen, 23-Nov-2012.) |
⊢ (¬ 𝜑 ∨ 𝜑) | ||
Theorem | pm2.13 894 | Theorem *2.13 of [WhiteheadRussell] p. 101. (Contributed by NM, 3-Jan-2005.) |
⊢ (𝜑 ∨ ¬ ¬ ¬ 𝜑) | ||
Theorem | pm2.621 895 | Theorem *2.621 of [WhiteheadRussell] p. 107. (Contributed by NM, 3-Jan-2005.) |
⊢ ((𝜑 → 𝜓) → ((𝜑 ∨ 𝜓) → 𝜓)) | ||
Theorem | pm2.62 896 | Theorem *2.62 of [WhiteheadRussell] p. 107. (Contributed by NM, 3-Jan-2005.) (Proof shortened by Wolf Lammen, 13-Dec-2013.) |
⊢ ((𝜑 ∨ 𝜓) → ((𝜑 → 𝜓) → 𝜓)) | ||
Theorem | pm2.68 897 | Theorem *2.68 of [WhiteheadRussell] p. 108. (Contributed by NM, 3-Jan-2005.) |
⊢ (((𝜑 → 𝜓) → 𝜓) → (𝜑 ∨ 𝜓)) | ||
Theorem | dfor2 898 | Logical 'or' expressed in terms of implication only. Theorem *5.25 of [WhiteheadRussell] p. 124. (Contributed by NM, 12-Aug-2004.) (Proof shortened by Wolf Lammen, 20-Oct-2012.) |
⊢ ((𝜑 ∨ 𝜓) ↔ ((𝜑 → 𝜓) → 𝜓)) | ||
Theorem | pm2.07 899 | Theorem *2.07 of [WhiteheadRussell] p. 101. (Contributed by NM, 3-Jan-2005.) |
⊢ (𝜑 → (𝜑 ∨ 𝜑)) | ||
Theorem | pm1.2 900 | Axiom *1.2 of [WhiteheadRussell] p. 96, which they call "Taut". (Contributed by NM, 3-Jan-2005.) |
⊢ ((𝜑 ∨ 𝜑) → 𝜑) |
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