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Theorem List for Metamath Proof Explorer - 9001-9100   *Has distinct variable group(s)
TypeLabelDescription
Statement
 
Theoremoiexg 9001 The order isomorphism on a set is a set. (Contributed by Mario Carneiro, 25-Jun-2015.)
𝐹 = OrdIso(𝑅, 𝐴)       (𝐴𝑉𝐹 ∈ V)
 
Theoremoion 9002 The order type of the well-order 𝑅 on 𝐴 is an ordinal. (Contributed by Stefan O'Rear, 11-Feb-2015.) (Revised by Mario Carneiro, 23-May-2015.)
𝐹 = OrdIso(𝑅, 𝐴)       (𝐴𝑉 → dom 𝐹 ∈ On)
 
Theoremoiiso 9003 The order isomorphism of the well-order 𝑅 on 𝐴 is an isomorphism. (Contributed by Mario Carneiro, 23-May-2015.)
𝐹 = OrdIso(𝑅, 𝐴)       ((𝐴𝑉𝑅 We 𝐴) → 𝐹 Isom E , 𝑅 (dom 𝐹, 𝐴))
 
Theoremoien 9004 The order type of a well-ordered set is equinumerous to the set. (Contributed by Mario Carneiro, 23-May-2015.)
𝐹 = OrdIso(𝑅, 𝐴)       ((𝐴𝑉𝑅 We 𝐴) → dom 𝐹𝐴)
 
Theoremoieu 9005 Uniqueness of the unique ordinal isomorphism. (Contributed by Mario Carneiro, 23-May-2015.) (Revised by Mario Carneiro, 25-Jun-2015.)
𝐹 = OrdIso(𝑅, 𝐴)       ((𝑅 We 𝐴𝑅 Se 𝐴) → ((Ord 𝐵𝐺 Isom E , 𝑅 (𝐵, 𝐴)) ↔ (𝐵 = dom 𝐹𝐺 = 𝐹)))
 
Theoremoismo 9006 When 𝐴 is a subclass of On, 𝐹 is a strictly monotone ordinal functions, and it is also complete (it is an isomorphism onto all of 𝐴). The proof avoids ax-rep 5192 (the second statement is trivial under ax-rep 5192). (Contributed by Mario Carneiro, 26-Jun-2015.)
𝐹 = OrdIso( E , 𝐴)       (𝐴 ⊆ On → (Smo 𝐹 ∧ ran 𝐹 = 𝐴))
 
Theoremoiid 9007 The order type of an ordinal under the order is itself, and the order isomorphism is the identity function. (Contributed by Mario Carneiro, 26-Jun-2015.)
(Ord 𝐴 → OrdIso( E , 𝐴) = ( I ↾ 𝐴))
 
Theoremhartogslem1 9008* Lemma for hartogs 9010. (Contributed by Mario Carneiro, 14-Jan-2013.) (Revised by Mario Carneiro, 15-May-2015.)
𝐹 = {⟨𝑟, 𝑦⟩ ∣ (((dom 𝑟𝐴 ∧ ( I ↾ dom 𝑟) ⊆ 𝑟𝑟 ⊆ (dom 𝑟 × dom 𝑟)) ∧ (𝑟 ∖ I ) We dom 𝑟) ∧ 𝑦 = dom OrdIso((𝑟 ∖ I ), dom 𝑟))}    &   𝑅 = {⟨𝑠, 𝑡⟩ ∣ ∃𝑤𝑦𝑧𝑦 ((𝑠 = (𝑓𝑤) ∧ 𝑡 = (𝑓𝑧)) ∧ 𝑤 E 𝑧)}       (dom 𝐹 ⊆ 𝒫 (𝐴 × 𝐴) ∧ Fun 𝐹 ∧ (𝐴𝑉 → ran 𝐹 = {𝑥 ∈ On ∣ 𝑥𝐴}))
 
Theoremhartogslem2 9009* Lemma for hartogs 9010. (Contributed by Mario Carneiro, 14-Jan-2013.)
𝐹 = {⟨𝑟, 𝑦⟩ ∣ (((dom 𝑟𝐴 ∧ ( I ↾ dom 𝑟) ⊆ 𝑟𝑟 ⊆ (dom 𝑟 × dom 𝑟)) ∧ (𝑟 ∖ I ) We dom 𝑟) ∧ 𝑦 = dom OrdIso((𝑟 ∖ I ), dom 𝑟))}    &   𝑅 = {⟨𝑠, 𝑡⟩ ∣ ∃𝑤𝑦𝑧𝑦 ((𝑠 = (𝑓𝑤) ∧ 𝑡 = (𝑓𝑧)) ∧ 𝑤 E 𝑧)}       (𝐴𝑉 → {𝑥 ∈ On ∣ 𝑥𝐴} ∈ V)
 
Theoremhartogs 9010* Given any set, the Hartogs number of the set is the least ordinal not dominated by that set. This theorem proves that there is always an ordinal which satisfies this. (This theorem can be proven trivially using the AC - see theorem ondomon 9987- but this proof works in ZF.) (Contributed by Jeff Hankins, 22-Oct-2009.) (Revised by Mario Carneiro, 15-May-2015.)
(𝐴𝑉 → {𝑥 ∈ On ∣ 𝑥𝐴} ∈ On)
 
Theoremwofib 9011 The only sets which are well-ordered forwards and backwards are finite sets. (Contributed by Mario Carneiro, 30-Jan-2014.) (Revised by Mario Carneiro, 23-May-2015.)
𝐴 ∈ V       ((𝑅 Or 𝐴𝐴 ∈ Fin) ↔ (𝑅 We 𝐴𝑅 We 𝐴))
 
Theoremwemaplem1 9012* Value of the lexicographic order on a sequence space. (Contributed by Stefan O'Rear, 18-Jan-2015.)
𝑇 = {⟨𝑥, 𝑦⟩ ∣ ∃𝑧𝐴 ((𝑥𝑧)𝑆(𝑦𝑧) ∧ ∀𝑤𝐴 (𝑤𝑅𝑧 → (𝑥𝑤) = (𝑦𝑤)))}       ((𝑃𝑉𝑄𝑊) → (𝑃𝑇𝑄 ↔ ∃𝑎𝐴 ((𝑃𝑎)𝑆(𝑄𝑎) ∧ ∀𝑏𝐴 (𝑏𝑅𝑎 → (𝑃𝑏) = (𝑄𝑏)))))
 
Theoremwemaplem2 9013* Lemma for wemapso 9017. Transitivity. (Contributed by Stefan O'Rear, 17-Jan-2015.)
𝑇 = {⟨𝑥, 𝑦⟩ ∣ ∃𝑧𝐴 ((𝑥𝑧)𝑆(𝑦𝑧) ∧ ∀𝑤𝐴 (𝑤𝑅𝑧 → (𝑥𝑤) = (𝑦𝑤)))}    &   (𝜑𝐴 ∈ V)    &   (𝜑𝑃 ∈ (𝐵m 𝐴))    &   (𝜑𝑋 ∈ (𝐵m 𝐴))    &   (𝜑𝑄 ∈ (𝐵m 𝐴))    &   (𝜑𝑅 Or 𝐴)    &   (𝜑𝑆 Po 𝐵)    &   (𝜑𝑎𝐴)    &   (𝜑 → (𝑃𝑎)𝑆(𝑋𝑎))    &   (𝜑 → ∀𝑐𝐴 (𝑐𝑅𝑎 → (𝑃𝑐) = (𝑋𝑐)))    &   (𝜑𝑏𝐴)    &   (𝜑 → (𝑋𝑏)𝑆(𝑄𝑏))    &   (𝜑 → ∀𝑐𝐴 (𝑐𝑅𝑏 → (𝑋𝑐) = (𝑄𝑐)))       (𝜑𝑃𝑇𝑄)
 
Theoremwemaplem3 9014* Lemma for wemapso 9017. Transitivity. (Contributed by Stefan O'Rear, 17-Jan-2015.)
𝑇 = {⟨𝑥, 𝑦⟩ ∣ ∃𝑧𝐴 ((𝑥𝑧)𝑆(𝑦𝑧) ∧ ∀𝑤𝐴 (𝑤𝑅𝑧 → (𝑥𝑤) = (𝑦𝑤)))}    &   (𝜑𝐴 ∈ V)    &   (𝜑𝑃 ∈ (𝐵m 𝐴))    &   (𝜑𝑋 ∈ (𝐵m 𝐴))    &   (𝜑𝑄 ∈ (𝐵m 𝐴))    &   (𝜑𝑅 Or 𝐴)    &   (𝜑𝑆 Po 𝐵)    &   (𝜑𝑃𝑇𝑋)    &   (𝜑𝑋𝑇𝑄)       (𝜑𝑃𝑇𝑄)
 
Theoremwemappo 9015* Construct lexicographic order on a function space based on a well-ordering of the indices and a total ordering of the values.

Without totality on the values or least differing indices, the best we can prove here is a partial order. (Contributed by Stefan O'Rear, 18-Jan-2015.)

𝑇 = {⟨𝑥, 𝑦⟩ ∣ ∃𝑧𝐴 ((𝑥𝑧)𝑆(𝑦𝑧) ∧ ∀𝑤𝐴 (𝑤𝑅𝑧 → (𝑥𝑤) = (𝑦𝑤)))}       ((𝐴𝑉𝑅 Or 𝐴𝑆 Po 𝐵) → 𝑇 Po (𝐵m 𝐴))
 
Theoremwemapsolem 9016* Lemma for wemapso 9017. (Contributed by Stefan O'Rear, 18-Jan-2015.) (Revised by Mario Carneiro, 8-Feb-2015.)
𝑇 = {⟨𝑥, 𝑦⟩ ∣ ∃𝑧𝐴 ((𝑥𝑧)𝑆(𝑦𝑧) ∧ ∀𝑤𝐴 (𝑤𝑅𝑧 → (𝑥𝑤) = (𝑦𝑤)))}    &   𝑈 ⊆ (𝐵m 𝐴)    &   (𝜑𝐴 ∈ V)    &   (𝜑𝑅 Or 𝐴)    &   (𝜑𝑆 Or 𝐵)    &   ((𝜑 ∧ ((𝑎𝑈𝑏𝑈) ∧ 𝑎𝑏)) → ∃𝑐 ∈ dom (𝑎𝑏)∀𝑑 ∈ dom (𝑎𝑏) ¬ 𝑑𝑅𝑐)       (𝜑𝑇 Or 𝑈)
 
Theoremwemapso 9017* Construct lexicographic order on a function space based on a well-ordering of the indices and a total ordering of the values. (Contributed by Stefan O'Rear, 18-Jan-2015.) (Revised by Mario Carneiro, 8-Feb-2015.)
𝑇 = {⟨𝑥, 𝑦⟩ ∣ ∃𝑧𝐴 ((𝑥𝑧)𝑆(𝑦𝑧) ∧ ∀𝑤𝐴 (𝑤𝑅𝑧 → (𝑥𝑤) = (𝑦𝑤)))}       ((𝐴𝑉𝑅 We 𝐴𝑆 Or 𝐵) → 𝑇 Or (𝐵m 𝐴))
 
Theoremwemapso2lem 9018* Lemma for wemapso2 9019. (Contributed by Mario Carneiro, 8-Feb-2015.) (Revised by AV, 1-Jul-2019.)
𝑇 = {⟨𝑥, 𝑦⟩ ∣ ∃𝑧𝐴 ((𝑥𝑧)𝑆(𝑦𝑧) ∧ ∀𝑤𝐴 (𝑤𝑅𝑧 → (𝑥𝑤) = (𝑦𝑤)))}    &   𝑈 = {𝑥 ∈ (𝐵m 𝐴) ∣ 𝑥 finSupp 𝑍}       (((𝐴𝑉𝑅 Or 𝐴𝑆 Or 𝐵) ∧ 𝑍𝑊) → 𝑇 Or 𝑈)
 
Theoremwemapso2 9019* An alternative to having a well-order on 𝑅 in wemapso 9017 is to restrict the function set to finitely-supported functions. (Contributed by Mario Carneiro, 8-Feb-2015.) (Revised by AV, 1-Jul-2019.)
𝑇 = {⟨𝑥, 𝑦⟩ ∣ ∃𝑧𝐴 ((𝑥𝑧)𝑆(𝑦𝑧) ∧ ∀𝑤𝐴 (𝑤𝑅𝑧 → (𝑥𝑤) = (𝑦𝑤)))}    &   𝑈 = {𝑥 ∈ (𝐵m 𝐴) ∣ 𝑥 finSupp 𝑍}       ((𝐴𝑉𝑅 Or 𝐴𝑆 Or 𝐵) → 𝑇 Or 𝑈)
 
Theoremcard2on 9020* The alternate definition of the cardinal of a set given in cardval2 9422 always gives a set, and indeed an ordinal. (Contributed by Mario Carneiro, 14-Jan-2013.)
{𝑥 ∈ On ∣ 𝑥𝐴} ∈ On
 
Theoremcard2inf 9021* The alternate definition of the cardinal of a set given in cardval2 9422 has the curious property that for non-numerable sets (for which ndmfv 6702 yields ), it still evaluates to a nonempty set, and indeed it contains ω. (Contributed by Mario Carneiro, 15-Jan-2013.) (Revised by Mario Carneiro, 27-Apr-2015.)
𝐴 ∈ V       (¬ ∃𝑦 ∈ On 𝑦𝐴 → ω ⊆ {𝑥 ∈ On ∣ 𝑥𝐴})
 
2.4.34  Hartogs function, order types, weak dominance
 
Syntaxchar 9022 Class symbol for the Hartogs/cardinal successor function.
class har
 
Syntaxcwdom 9023 Class symbol for the weak dominance relation.
class *
 
Definitiondf-har 9024* Define the Hartogs function , which maps all sets to the smallest ordinal that cannot be injected into the given set. In the important special case where 𝑥 is an ordinal, this is the cardinal successor operation.

Traditionally, the Hartogs number of a set is written ℵ(𝑋) and the cardinal successor 𝑋 +; we use functional notation for this, and cannot use the aleph symbol because it is taken for the enumerating function of the infinite initial ordinals df-aleph 9371.

Some authors define the Hartogs number of a set to be the least *infinite* ordinal which does not inject into it, thus causing the range to consist only of alephs. We use the simpler definition where the value can be any successor cardinal. (Contributed by Stefan O'Rear, 11-Feb-2015.)

har = (𝑥 ∈ V ↦ {𝑦 ∈ On ∣ 𝑦𝑥})
 
Definitiondf-wdom 9025* A set is weakly dominated by a "larger" set iff the "larger" set can be mapped onto the "smaller" set or the smaller set is empty; equivalently if the smaller set can be placed into bijection with some partition of the larger set. When choice is assumed (as fodom 9946), this coincides with the 1-1 definition df-dom 8513; however, it is not known whether this is a choice-equivalent or a strictly weaker form. Some discussion of this question can be found at http://boolesrings.org/asafk/2014/on-the-partition-principle/ 8513. (Contributed by Stefan O'Rear, 11-Feb-2015.)
* = {⟨𝑥, 𝑦⟩ ∣ (𝑥 = ∅ ∨ ∃𝑧 𝑧:𝑦onto𝑥)}
 
Theoremharf 9026 Functionality of the Hartogs function. (Contributed by Stefan O'Rear, 11-Feb-2015.)
har:V⟶On
 
Theoremharcl 9027 Closure of the Hartogs function in the ordinals. (Contributed by Stefan O'Rear, 11-Feb-2015.)
(har‘𝑋) ∈ On
 
Theoremharval 9028* Function value of the Hartogs function. (Contributed by Stefan O'Rear, 11-Feb-2015.)
(𝑋𝑉 → (har‘𝑋) = {𝑦 ∈ On ∣ 𝑦𝑋})
 
Theoremelharval 9029 The Hartogs number of a set is greater than all ordinals which inject into it. (Contributed by Stefan O'Rear, 11-Feb-2015.) (Revised by Mario Carneiro, 15-May-2015.)
(𝑌 ∈ (har‘𝑋) ↔ (𝑌 ∈ On ∧ 𝑌𝑋))
 
Theoremharndom 9030 The Hartogs number of a set does not inject into that set. (Contributed by Stefan O'Rear, 11-Feb-2015.) (Revised by Mario Carneiro, 15-May-2015.)
¬ (har‘𝑋) ≼ 𝑋
 
Theoremharword 9031 Weak ordering property of the Hartogs function. (Contributed by Stefan O'Rear, 14-Feb-2015.)
(𝑋𝑌 → (har‘𝑋) ⊆ (har‘𝑌))
 
Theoremrelwdom 9032 Weak dominance is a relation. (Contributed by Stefan O'Rear, 11-Feb-2015.)
Rel ≼*
 
Theorembrwdom 9033* Property of weak dominance (definitional form). (Contributed by Stefan O'Rear, 11-Feb-2015.)
(𝑌𝑉 → (𝑋* 𝑌 ↔ (𝑋 = ∅ ∨ ∃𝑧 𝑧:𝑌onto𝑋)))
 
Theorembrwdomi 9034* Property of weak dominance, forward direction only. (Contributed by Mario Carneiro, 5-May-2015.)
(𝑋* 𝑌 → (𝑋 = ∅ ∨ ∃𝑧 𝑧:𝑌onto𝑋))
 
Theorembrwdomn0 9035* Weak dominance over nonempty sets. (Contributed by Stefan O'Rear, 11-Feb-2015.) (Revised by Mario Carneiro, 5-May-2015.)
(𝑋 ≠ ∅ → (𝑋* 𝑌 ↔ ∃𝑧 𝑧:𝑌onto𝑋))
 
Theorem0wdom 9036 Any set weakly dominates the empty set. (Contributed by Stefan O'Rear, 11-Feb-2015.)
(𝑋𝑉 → ∅ ≼* 𝑋)
 
Theoremfowdom 9037 An onto function implies weak dominance. (Contributed by Stefan O'Rear, 11-Feb-2015.)
((𝐹𝑉𝐹:𝑌onto𝑋) → 𝑋* 𝑌)
 
Theoremwdomref 9038 Reflexivity of weak dominance. (Contributed by Stefan O'Rear, 11-Feb-2015.)
(𝑋𝑉𝑋* 𝑋)
 
Theorembrwdom2 9039* Alternate characterization of the weak dominance predicate which does not require special treatment of the empty set. (Contributed by Stefan O'Rear, 11-Feb-2015.)
(𝑌𝑉 → (𝑋* 𝑌 ↔ ∃𝑦 ∈ 𝒫 𝑌𝑧 𝑧:𝑦onto𝑋))
 
Theoremdomwdom 9040 Weak dominance is implied by dominance in the usual sense. (Contributed by Stefan O'Rear, 11-Feb-2015.)
(𝑋𝑌𝑋* 𝑌)
 
Theoremwdomtr 9041 Transitivity of weak dominance. (Contributed by Stefan O'Rear, 11-Feb-2015.) (Revised by Mario Carneiro, 5-May-2015.)
((𝑋* 𝑌𝑌* 𝑍) → 𝑋* 𝑍)
 
Theoremwdomen1 9042 Equality-like theorem for equinumerosity and weak dominance. (Contributed by Mario Carneiro, 18-May-2015.)
(𝐴𝐵 → (𝐴* 𝐶𝐵* 𝐶))
 
Theoremwdomen2 9043 Equality-like theorem for equinumerosity and weak dominance. (Contributed by Mario Carneiro, 18-May-2015.)
(𝐴𝐵 → (𝐶* 𝐴𝐶* 𝐵))
 
Theoremwdompwdom 9044 Weak dominance strengthens to usual dominance on the power sets. (Contributed by Stefan O'Rear, 11-Feb-2015.) (Revised by Mario Carneiro, 5-May-2015.)
(𝑋* 𝑌 → 𝒫 𝑋 ≼ 𝒫 𝑌)
 
Theoremcanthwdom 9045 Cantor's Theorem, stated using weak dominance (this is actually a stronger statement than canth2 8672, equivalent to canth 7113). (Contributed by Mario Carneiro, 15-May-2015.)
¬ 𝒫 𝐴* 𝐴
 
Theoremwdom2d 9046* Deduce weak dominance from an implicit onto function (stated in a way which avoids ax-rep 5192). (Contributed by Stefan O'Rear, 13-Feb-2015.)
(𝜑𝐴𝑉)    &   (𝜑𝐵𝑊)    &   ((𝜑𝑥𝐴) → ∃𝑦𝐵 𝑥 = 𝑋)       (𝜑𝐴* 𝐵)
 
Theoremwdomd 9047* Deduce weak dominance from an implicit onto function. (Contributed by Stefan O'Rear, 13-Feb-2015.)
(𝜑𝐵𝑊)    &   ((𝜑𝑥𝐴) → ∃𝑦𝐵 𝑥 = 𝑋)       (𝜑𝐴* 𝐵)
 
Theorembrwdom3 9048* Condition for weak dominance with a condition reminiscent of wdomd 9047. (Contributed by Stefan O'Rear, 13-Feb-2015.) (Revised by Mario Carneiro, 25-Jun-2015.)
((𝑋𝑉𝑌𝑊) → (𝑋* 𝑌 ↔ ∃𝑓𝑥𝑋𝑦𝑌 𝑥 = (𝑓𝑦)))
 
Theorembrwdom3i 9049* Weak dominance implies existence of a covering function. (Contributed by Stefan O'Rear, 13-Feb-2015.)
(𝑋* 𝑌 → ∃𝑓𝑥𝑋𝑦𝑌 𝑥 = (𝑓𝑦))
 
Theoremunwdomg 9050 Weak dominance of a (disjoint) union. (Contributed by Stefan O'Rear, 13-Feb-2015.) (Revised by Mario Carneiro, 25-Jun-2015.)
((𝐴* 𝐵𝐶* 𝐷 ∧ (𝐵𝐷) = ∅) → (𝐴𝐶) ≼* (𝐵𝐷))
 
Theoremxpwdomg 9051 Weak dominance of a Cartesian product. (Contributed by Stefan O'Rear, 13-Feb-2015.) (Revised by Mario Carneiro, 25-Jun-2015.)
((𝐴* 𝐵𝐶* 𝐷) → (𝐴 × 𝐶) ≼* (𝐵 × 𝐷))
 
Theoremwdomima2g 9052 A set is weakly dominant over its image under any function. This version of wdomimag 9053 is stated so as to avoid ax-rep 5192. (Contributed by Mario Carneiro, 25-Jun-2015.)
((Fun 𝐹𝐴𝑉 ∧ (𝐹𝐴) ∈ 𝑊) → (𝐹𝐴) ≼* 𝐴)
 
Theoremwdomimag 9053 A set is weakly dominant over its image under any function. (Contributed by Stefan O'Rear, 14-Feb-2015.) (Revised by Mario Carneiro, 25-Jun-2015.)
((Fun 𝐹𝐴𝑉) → (𝐹𝐴) ≼* 𝐴)
 
Theoremunxpwdom2 9054 Lemma for unxpwdom 9055. (Contributed by Mario Carneiro, 15-May-2015.)
((𝐴 × 𝐴) ≈ (𝐵𝐶) → (𝐴* 𝐵𝐴𝐶))
 
Theoremunxpwdom 9055 If a Cartesian product is dominated by a union, then the base set is either weakly dominated by one factor of the union or dominated by the other. Extracted from Lemma 2.3 of [KanamoriPincus] p. 420. (Contributed by Mario Carneiro, 15-May-2015.)
((𝐴 × 𝐴) ≼ (𝐵𝐶) → (𝐴* 𝐵𝐴𝐶))
 
Theoremharwdom 9056 The Hartogs function is weakly dominated by 𝒫 (𝑋 × 𝑋). This follows from a more precise analysis of the bound used in hartogs 9010 to prove that (har‘𝑋) is a set. (Contributed by Mario Carneiro, 15-May-2015.)
(𝑋𝑉 → (har‘𝑋) ≼* 𝒫 (𝑋 × 𝑋))
 
Theoremixpiunwdom 9057* Describe an onto function from the indexed cartesian product to the indexed union. Together with ixpssmapg 8494 this shows that 𝑥𝐴𝐵 and X𝑥𝐴𝐵 have closely linked cardinalities. (Contributed by Mario Carneiro, 27-Aug-2015.)
((𝐴𝑉 𝑥𝐴 𝐵𝑊X𝑥𝐴 𝐵 ≠ ∅) → 𝑥𝐴 𝐵* (X𝑥𝐴 𝐵 × 𝐴))
 
2.5  ZF Set Theory - add the Axiom of Regularity
 
2.5.1  Introduce the Axiom of Regularity
 
Axiomax-reg 9058* Axiom of Regularity. An axiom of Zermelo-Fraenkel set theory. Also called the Axiom of Foundation. A rather non-intuitive axiom that denies more than it asserts, it states (in the form of zfreg 9061) that every nonempty set contains a set disjoint from itself. One consequence is that it denies the existence of a set containing itself (elirrv 9062). A stronger version that works for proper classes is proved as zfregs 9176. (Contributed by NM, 14-Aug-1993.)
(∃𝑦 𝑦𝑥 → ∃𝑦(𝑦𝑥 ∧ ∀𝑧(𝑧𝑦 → ¬ 𝑧𝑥)))
 
Theoremaxreg2 9059* Axiom of Regularity expressed more compactly. (Contributed by NM, 14-Aug-2003.)
(𝑥𝑦 → ∃𝑥(𝑥𝑦 ∧ ∀𝑧(𝑧𝑥 → ¬ 𝑧𝑦)))
 
Theoremzfregcl 9060* The Axiom of Regularity with class variables. (Contributed by NM, 5-Aug-1994.) Replace sethood hypothesis with sethood antecedent. (Revised by BJ, 27-Apr-2021.)
(𝐴𝑉 → (∃𝑥 𝑥𝐴 → ∃𝑥𝐴𝑦𝑥 ¬ 𝑦𝐴))
 
Theoremzfreg 9061* The Axiom of Regularity using abbreviations. Axiom 6 of [TakeutiZaring] p. 21. This is called the "weak form". Axiom Reg of [BellMachover] p. 480. There is also a "strong form", not requiring that 𝐴 be a set, that can be proved with more difficulty (see zfregs 9176). (Contributed by NM, 26-Nov-1995.) Replace sethood hypothesis with sethood antecedent. (Revised by BJ, 27-Apr-2021.)
((𝐴𝑉𝐴 ≠ ∅) → ∃𝑥𝐴 (𝑥𝐴) = ∅)
 
Theoremelirrv 9062 The membership relation is irreflexive: no set is a member of itself. Theorem 105 of [Suppes] p. 54. (This is trivial to prove from zfregfr 9070 and efrirr 5538, but this proof is direct from the Axiom of Regularity.) (Contributed by NM, 19-Aug-1993.)
¬ 𝑥𝑥
 
Theoremelirr 9063 No class is a member of itself. Exercise 6 of [TakeutiZaring] p. 22. (Contributed by NM, 7-Aug-1994.) (Proof shortened by Andrew Salmon, 9-Jul-2011.)
¬ 𝐴𝐴
 
Theoremelneq 9064 A class is not equal to any of its elements. (Contributed by AV, 14-Jun-2022.)
(𝐴𝐵𝐴𝐵)
 
Theoremnelaneq 9065 A class is not an element of and equal to a class at the same time. Variant of elneq 9064 analogously to elnotel 9075 and en2lp 9071. (Proposed by BJ, 18-Jun-2022.) (Contributed by AV, 18-Jun-2022.)
¬ (𝐴𝐵𝐴 = 𝐵)
 
Theoremepinid0 9066 The membership (epsilon) relation and the identity relation are disjoint. Variable-free version of nelaneq 9065. (Proposed by BJ, 18-Jun-2022.) (Contributed by AV, 18-Jun-2022.)
( E ∩ I ) = ∅
 
Theoremsucprcreg 9067 A class is equal to its successor iff it is a proper class (assuming the Axiom of Regularity). (Contributed by NM, 9-Jul-2004.) (Proof shortened by BJ, 16-Apr-2019.)
𝐴 ∈ V ↔ suc 𝐴 = 𝐴)
 
Theoremruv 9068 The Russell class is equal to the universe V. Exercise 5 of [TakeutiZaring] p. 22. (Contributed by Alan Sare, 4-Oct-2008.)
{𝑥𝑥𝑥} = V
 
TheoremruALT 9069 Alternate proof of ru 3773, simplified using (indirectly) the Axiom of Regularity ax-reg 9058. (Contributed by Alan Sare, 4-Oct-2008.) (Proof modification is discouraged.) (New usage is discouraged.)
{𝑥𝑥𝑥} ∉ V
 
Theoremzfregfr 9070 The membership relation is well-founded on any class. (Contributed by NM, 26-Nov-1995.)
E Fr 𝐴
 
Theoremen2lp 9071 No class has 2-cycle membership loops. Theorem 7X(b) of [Enderton] p. 206. (Contributed by NM, 16-Oct-1996.) (Revised by Mario Carneiro, 25-Jun-2015.)
¬ (𝐴𝐵𝐵𝐴)
 
Theoremelnanel 9072 Two classes are not elements of each other simultaneously. This is just a rewriting of en2lp 9071 and serves as an example in the context of Godel codes, see elnanelprv 32678. (Contributed by AV, 5-Nov-2023.) (New usage is discouraged.)
(𝐴𝐵𝐵𝐴)
 
Theoremcnvepnep 9073 The membership (epsilon) relation and its converse are disjoint, i.e., E is an asymmetric relation. Variable-free version of en2lp 9071. (Proposed by BJ, 18-Jun-2022.) (Contributed by AV, 19-Jun-2022.)
( E ∩ E ) = ∅
 
Theoremepnsym 9074 The membership (epsilon) relation is not symmetric. (Contributed by AV, 18-Jun-2022.)
E ≠ E
 
Theoremelnotel 9075 A class cannot be an element of one of its elements. (Contributed by AV, 14-Jun-2022.)
(𝐴𝐵 → ¬ 𝐵𝐴)
 
Theoremelnel 9076 A class cannot be an element of one of its elements. (Contributed by AV, 14-Jun-2022.)
(𝐴𝐵𝐵𝐴)
 
Theoremen3lplem1 9077* Lemma for en3lp 9079. (Contributed by Alan Sare, 28-Oct-2011.)
((𝐴𝐵𝐵𝐶𝐶𝐴) → (𝑥 = 𝐴 → (𝑥 ∩ {𝐴, 𝐵, 𝐶}) ≠ ∅))
 
Theoremen3lplem2 9078* Lemma for en3lp 9079. (Contributed by Alan Sare, 28-Oct-2011.)
((𝐴𝐵𝐵𝐶𝐶𝐴) → (𝑥 ∈ {𝐴, 𝐵, 𝐶} → (𝑥 ∩ {𝐴, 𝐵, 𝐶}) ≠ ∅))
 
Theoremen3lp 9079 No class has 3-cycle membership loops. This proof was automatically generated from the virtual deduction proof en3lpVD 41186 using a translation program. (Contributed by Alan Sare, 24-Oct-2011.)
¬ (𝐴𝐵𝐵𝐶𝐶𝐴)
 
Theorempreleqg 9080 Equality of two unordered pairs when one member of each pair contains the other member. Closed form of preleq 9081. (Contributed by AV, 15-Jun-2022.)
(((𝐴𝐵𝐵𝑉𝐶𝐷) ∧ {𝐴, 𝐵} = {𝐶, 𝐷}) → (𝐴 = 𝐶𝐵 = 𝐷))
 
Theorempreleq 9081 Equality of two unordered pairs when one member of each pair contains the other member. (Contributed by NM, 16-Oct-1996.) (Revised by AV, 15-Jun-2022.)
𝐵 ∈ V       (((𝐴𝐵𝐶𝐷) ∧ {𝐴, 𝐵} = {𝐶, 𝐷}) → (𝐴 = 𝐶𝐵 = 𝐷))
 
TheorempreleqALT 9082 Alternate proof of preleq 9081, not based on preleqg 9080: Equality of two unordered pairs when one member of each pair contains the other member. (Contributed by NM, 16-Oct-1996.) (Proof modification is discouraged.) (New usage is discouraged.)
𝐵 ∈ V    &   𝐷 ∈ V       (((𝐴𝐵𝐶𝐷) ∧ {𝐴, 𝐵} = {𝐶, 𝐷}) → (𝐴 = 𝐶𝐵 = 𝐷))
 
Theoremopthreg 9083 Theorem for alternate representation of ordered pairs, requiring the Axiom of Regularity ax-reg 9058 (via the preleq 9081 step). See df-op 4576 for a description of other ordered pair representations. Exercise 34 of [Enderton] p. 207. (Contributed by NM, 16-Oct-1996.) (Proof shortened by AV, 15-Jun-2022.)
𝐴 ∈ V    &   𝐵 ∈ V    &   𝐶 ∈ V    &   𝐷 ∈ V       ({𝐴, {𝐴, 𝐵}} = {𝐶, {𝐶, 𝐷}} ↔ (𝐴 = 𝐶𝐵 = 𝐷))
 
Theoremsuc11reg 9084 The successor operation behaves like a one-to-one function (assuming the Axiom of Regularity). Exercise 35 of [Enderton] p. 208 and its converse. (Contributed by NM, 25-Oct-2003.)
(suc 𝐴 = suc 𝐵𝐴 = 𝐵)
 
Theoremdford2 9085* Assuming ax-reg 9058, an ordinal is a transitive class on which inclusion satisfies trichotomy. (Contributed by Scott Fenton, 27-Oct-2010.)
(Ord 𝐴 ↔ (Tr 𝐴 ∧ ∀𝑥𝐴𝑦𝐴 (𝑥𝑦𝑥 = 𝑦𝑦𝑥)))
 
2.5.2  Axiom of Infinity equivalents
 
Theoreminf0 9086* Our Axiom of Infinity derived from existence of omega. The proof shows that the especially contrived class "ran (rec((𝑣 ∈ V ↦ suc 𝑣), 𝑥) ↾ ω) " exists, is a subset of its union, and contains a given set 𝑥 (and thus is nonempty). Thus, it provides an example demonstrating that a set 𝑦 exists with the necessary properties demanded by ax-inf 9103. (Contributed by NM, 15-Oct-1996.)
ω ∈ V       𝑦(𝑥𝑦 ∧ ∀𝑧(𝑧𝑦 → ∃𝑤(𝑧𝑤𝑤𝑦)))
 
Theoreminf1 9087 Variation of Axiom of Infinity (using zfinf 9104 as a hypothesis). Axiom of Infinity in [FreydScedrov] p. 283. (Contributed by NM, 14-Oct-1996.) (Revised by David Abernethy, 1-Oct-2013.)
𝑥(𝑦𝑥 ∧ ∀𝑦(𝑦𝑥 → ∃𝑧(𝑦𝑧𝑧𝑥)))       𝑥(𝑥 ≠ ∅ ∧ ∀𝑦(𝑦𝑥 → ∃𝑧(𝑦𝑧𝑧𝑥)))
 
Theoreminf2 9088* Variation of Axiom of Infinity. There exists a nonempty set that is a subset of its union (using zfinf 9104 as a hypothesis). Abbreviated version of the Axiom of Infinity in [FreydScedrov] p. 283. (Contributed by NM, 28-Oct-1996.)
𝑥(𝑦𝑥 ∧ ∀𝑦(𝑦𝑥 → ∃𝑧(𝑦𝑧𝑧𝑥)))       𝑥(𝑥 ≠ ∅ ∧ 𝑥 𝑥)
 
Theoreminf3lema 9089* Lemma for our Axiom of Infinity => standard Axiom of Infinity. See inf3 9100 for detailed description. (Contributed by NM, 28-Oct-1996.)
𝐺 = (𝑦 ∈ V ↦ {𝑤𝑥 ∣ (𝑤𝑥) ⊆ 𝑦})    &   𝐹 = (rec(𝐺, ∅) ↾ ω)    &   𝐴 ∈ V    &   𝐵 ∈ V       (𝐴 ∈ (𝐺𝐵) ↔ (𝐴𝑥 ∧ (𝐴𝑥) ⊆ 𝐵))
 
Theoreminf3lemb 9090* Lemma for our Axiom of Infinity => standard Axiom of Infinity. See inf3 9100 for detailed description. (Contributed by NM, 28-Oct-1996.)
𝐺 = (𝑦 ∈ V ↦ {𝑤𝑥 ∣ (𝑤𝑥) ⊆ 𝑦})    &   𝐹 = (rec(𝐺, ∅) ↾ ω)    &   𝐴 ∈ V    &   𝐵 ∈ V       (𝐹‘∅) = ∅
 
Theoreminf3lemc 9091* Lemma for our Axiom of Infinity => standard Axiom of Infinity. See inf3 9100 for detailed description. (Contributed by NM, 28-Oct-1996.)
𝐺 = (𝑦 ∈ V ↦ {𝑤𝑥 ∣ (𝑤𝑥) ⊆ 𝑦})    &   𝐹 = (rec(𝐺, ∅) ↾ ω)    &   𝐴 ∈ V    &   𝐵 ∈ V       (𝐴 ∈ ω → (𝐹‘suc 𝐴) = (𝐺‘(𝐹𝐴)))
 
Theoreminf3lemd 9092* Lemma for our Axiom of Infinity => standard Axiom of Infinity. See inf3 9100 for detailed description. (Contributed by NM, 28-Oct-1996.)
𝐺 = (𝑦 ∈ V ↦ {𝑤𝑥 ∣ (𝑤𝑥) ⊆ 𝑦})    &   𝐹 = (rec(𝐺, ∅) ↾ ω)    &   𝐴 ∈ V    &   𝐵 ∈ V       (𝐴 ∈ ω → (𝐹𝐴) ⊆ 𝑥)
 
Theoreminf3lem1 9093* Lemma for our Axiom of Infinity => standard Axiom of Infinity. See inf3 9100 for detailed description. (Contributed by NM, 28-Oct-1996.)
𝐺 = (𝑦 ∈ V ↦ {𝑤𝑥 ∣ (𝑤𝑥) ⊆ 𝑦})    &   𝐹 = (rec(𝐺, ∅) ↾ ω)    &   𝐴 ∈ V    &   𝐵 ∈ V       (𝐴 ∈ ω → (𝐹𝐴) ⊆ (𝐹‘suc 𝐴))
 
Theoreminf3lem2 9094* Lemma for our Axiom of Infinity => standard Axiom of Infinity. See inf3 9100 for detailed description. (Contributed by NM, 28-Oct-1996.)
𝐺 = (𝑦 ∈ V ↦ {𝑤𝑥 ∣ (𝑤𝑥) ⊆ 𝑦})    &   𝐹 = (rec(𝐺, ∅) ↾ ω)    &   𝐴 ∈ V    &   𝐵 ∈ V       ((𝑥 ≠ ∅ ∧ 𝑥 𝑥) → (𝐴 ∈ ω → (𝐹𝐴) ≠ 𝑥))
 
Theoreminf3lem3 9095* Lemma for our Axiom of Infinity => standard Axiom of Infinity. See inf3 9100 for detailed description. In the proof, we invoke the Axiom of Regularity in the form of zfreg 9061. (Contributed by NM, 29-Oct-1996.)
𝐺 = (𝑦 ∈ V ↦ {𝑤𝑥 ∣ (𝑤𝑥) ⊆ 𝑦})    &   𝐹 = (rec(𝐺, ∅) ↾ ω)    &   𝐴 ∈ V    &   𝐵 ∈ V       ((𝑥 ≠ ∅ ∧ 𝑥 𝑥) → (𝐴 ∈ ω → (𝐹𝐴) ≠ (𝐹‘suc 𝐴)))
 
Theoreminf3lem4 9096* Lemma for our Axiom of Infinity => standard Axiom of Infinity. See inf3 9100 for detailed description. (Contributed by NM, 29-Oct-1996.)
𝐺 = (𝑦 ∈ V ↦ {𝑤𝑥 ∣ (𝑤𝑥) ⊆ 𝑦})    &   𝐹 = (rec(𝐺, ∅) ↾ ω)    &   𝐴 ∈ V    &   𝐵 ∈ V       ((𝑥 ≠ ∅ ∧ 𝑥 𝑥) → (𝐴 ∈ ω → (𝐹𝐴) ⊊ (𝐹‘suc 𝐴)))
 
Theoreminf3lem5 9097* Lemma for our Axiom of Infinity => standard Axiom of Infinity. See inf3 9100 for detailed description. (Contributed by NM, 29-Oct-1996.)
𝐺 = (𝑦 ∈ V ↦ {𝑤𝑥 ∣ (𝑤𝑥) ⊆ 𝑦})    &   𝐹 = (rec(𝐺, ∅) ↾ ω)    &   𝐴 ∈ V    &   𝐵 ∈ V       ((𝑥 ≠ ∅ ∧ 𝑥 𝑥) → ((𝐴 ∈ ω ∧ 𝐵𝐴) → (𝐹𝐵) ⊊ (𝐹𝐴)))
 
Theoreminf3lem6 9098* Lemma for our Axiom of Infinity => standard Axiom of Infinity. See inf3 9100 for detailed description. (Contributed by NM, 29-Oct-1996.)
𝐺 = (𝑦 ∈ V ↦ {𝑤𝑥 ∣ (𝑤𝑥) ⊆ 𝑦})    &   𝐹 = (rec(𝐺, ∅) ↾ ω)    &   𝐴 ∈ V    &   𝐵 ∈ V       ((𝑥 ≠ ∅ ∧ 𝑥 𝑥) → 𝐹:ω–1-1→𝒫 𝑥)
 
Theoreminf3lem7 9099* Lemma for our Axiom of Infinity => standard Axiom of Infinity. See inf3 9100 for detailed description. In the proof, we invoke the Axiom of Replacement in the form of f1dmex 7660. (Contributed by NM, 29-Oct-1996.) (Proof shortened by Mario Carneiro, 19-Jan-2013.)
𝐺 = (𝑦 ∈ V ↦ {𝑤𝑥 ∣ (𝑤𝑥) ⊆ 𝑦})    &   𝐹 = (rec(𝐺, ∅) ↾ ω)    &   𝐴 ∈ V    &   𝐵 ∈ V       ((𝑥 ≠ ∅ ∧ 𝑥 𝑥) → ω ∈ V)
 
Theoreminf3 9100 Our Axiom of Infinity ax-inf 9103 implies the standard Axiom of Infinity. The hypothesis is a variant of our Axiom of Infinity provided by inf2 9088, and the conclusion is the version of the Axiom of Infinity shown as Axiom 7 in [TakeutiZaring] p. 43. (Other standard versions are proved later as axinf2 9105 and zfinf2 9107.) The main proof is provided by inf3lema 9089 through inf3lem7 9099, and this final piece eliminates the auxiliary hypothesis of inf3lem7 9099. This proof is due to Ian Sutherland, Richard Heck, and Norman Megill and was posted on Usenet as shown below. Although the result is not new, the authors were unable to find a published proof.
       (As posted to sci.logic on 30-Oct-1996, with annotations added.)

       Theorem:  The statement "There exists a nonempty set that is a subset
       of its union" implies the Axiom of Infinity.

       Proof:  Let X be a nonempty set which is a subset of its union; the
       latter
       property is equivalent to saying that for any y in X, there exists a z
       in X
       such that y is in z.

       Define by finite recursion a function F:omega-->(power X) such that
       F_0 = 0  (See inf3lemb 9090.)
       F_n+1 = {y<X | y^X subset F_n}  (See inf3lemc 9091.)
       Note: ^ means intersect, < means \in ("element of").
       (Finite recursion as typically done requires the existence of omega;
       to avoid this we can just use transfinite recursion restricted to omega.
       F is a class-term that is not necessarily a set at this point.)

       Lemma 1.  F_n subset F_n+1.  (See inf3lem1 9093.)
       Proof:  By induction:  F_0 subset F_1.  If y < F_n+1, then y^X subset
       F_n,
       so if F_n subset F_n+1, then y^X subset F_n+1, so y < F_n+2.

       Lemma 2.  F_n =/= X.  (See inf3lem2 9094.)
       Proof:  By induction:  F_0 =/= X because X is not empty.  Assume F_n =/=
       X.
       Then there is a y in X that is not in F_n.  By definition of X, there is
       a
       z in X that contains y.  Suppose F_n+1 = X.  Then z is in F_n+1, and z^X
       contains y, so z^X is not a subset of F_n, contrary to the definition of
       F_n+1.

       Lemma 3.  F_n =/= F_n+1.  (See inf3lem3 9095.)
       Proof:  Using the identity y^X subset F_n <-> y^(X-F_n) = 0, we have
       F_n+1 = {y<X | y^(X-F_n) = 0}.  Let q = {y<X-F_n | y^(X-F_n) = 0}.
       Then q subset F_n+1.  Since X-F_n is not empty by Lemma 2 and q is the
       set of \in-minimal elements of X-F_n, by Foundation q is not empty, so q
       and therefore F_n+1 have an element not in F_n.

       Lemma 4.  F_n proper_subset F_n+1.  (See inf3lem4 9096.)
       Proof:  Lemmas 1 and 3.

       Lemma 5.  F_m proper_subset F_n, m < n.  (See inf3lem5 9097.)
       Proof:  Fix m and use induction on n > m.  Basis: F_m proper_subset
       F_m+1
       by Lemma 4.  Induction:  Assume F_m proper_subset F_n.  Then since F_n
       proper_subset F_n+1, F_m proper_subset F_n+1 by transitivity of proper
       subset.

       By Lemma 5, F_m =/= F_n for m =/= n, so F is 1-1.  (See inf3lem6 9098.)
       Thus, the inverse of F is a function with range omega and domain a
       subset
       of power X, so omega exists by Replacement.  (See inf3lem7 9099.)
       Q.E.D.
       
(Contributed by NM, 29-Oct-1996.)
𝑥(𝑥 ≠ ∅ ∧ 𝑥 𝑥)       ω ∈ V
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144 14301-14400 145 14401-14500 146 14501-14600 147 14601-14700 148 14701-14800 149 14801-14900 150 14901-15000 151 15001-15100 152 15101-15200 153 15201-15300 154 15301-15400 155 15401-15500 156 15501-15600 157 15601-15700 158 15701-15800 159 15801-15900 160 15901-16000 161 16001-16100 162 16101-16200 163 16201-16300 164 16301-16400 165 16401-16500 166 16501-16600 167 16601-16700 168 16701-16800 169 16801-16900 170 16901-17000 171 17001-17100 172 17101-17200 173 17201-17300 174 17301-17400 175 17401-17500 176 17501-17600 177 17601-17700 178 17701-17800 179 17801-17900 180 17901-18000 181 18001-18100 182 18101-18200 183 18201-18300 184 18301-18400 185 18401-18500 186 18501-18600 187 18601-18700 188 18701-18800 189 18801-18900 190 18901-19000 191 19001-19100 192 19101-19200 193 19201-19300 194 19301-19400 195 19401-19500 196 19501-19600 197 19601-19700 198 19701-19800 199 19801-19900 200 19901-20000 201 20001-20100 202 20101-20200 203 20201-20300 204 20301-20400 205 20401-20500 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268 26701-26800 269 26801-26900 270 26901-27000 271 27001-27100 272 27101-27200 273 27201-27300 274 27301-27400 275 27401-27500 276 27501-27600 277 27601-27700 278 27701-27800 279 27801-27900 280 27901-28000 281 28001-28100 282 28101-28200 283 28201-28300 284 28301-28400 285 28401-28500 286 28501-28600 287 28601-28700 288 28701-28800 289 28801-28900 290 28901-29000 291 29001-29100 292 29101-29200 293 29201-29300 294 29301-29400 295 29401-29500 296 29501-29600 297 29601-29700 298 29701-29800 299 29801-29900 300 29901-30000 301 30001-30100 302 30101-30200 303 30201-30300 304 30301-30400 305 30401-30500 306 30501-30600 307 30601-30700 308 30701-30800 309 30801-30900 310 30901-31000 311 31001-31100 312 31101-31200 313 31201-31300 314 31301-31400 315 31401-31500 316 31501-31600 317 31601-31700 318 31701-31800 319 31801-31900 320 31901-32000 321 32001-32100 322 32101-32200 323 32201-32300 324 32301-32400 325 32401-32500 326 32501-32600 327 32601-32700 328 32701-32800 329 32801-32900 330 32901-33000 331 33001-33100 332 33101-33200 333 33201-33300 334 33301-33400 335 33401-33500 336 33501-33600 337 33601-33700 338 33701-33800 339 33801-33900 340 33901-34000 341 34001-34100 342 34101-34200 343 34201-34300 344 34301-34400 345 34401-34500 346 34501-34600 347 34601-34700 348 34701-34800 349 34801-34900 350 34901-35000 351 35001-35100 352 35101-35200 353 35201-35300 354 35301-35400 355 35401-35500 356 35501-35600 357 35601-35700 358 35701-35800 359 35801-35900 360 35901-36000 361 36001-36100 362 36101-36200 363 36201-36300 364 36301-36400 365 36401-36500 366 36501-36600 367 36601-36700 368 36701-36800 369 36801-36900 370 36901-37000 371 37001-37100 372 37101-37200 373 37201-37300 374 37301-37400 375 37401-37500 376 37501-37600 377 37601-37700 378 37701-37800 379 37801-37900 380 37901-38000 381 38001-38100 382 38101-38200 383 38201-38300 384 38301-38400 385 38401-38500 386 38501-38600 387 38601-38700 388 38701-38800 389 38801-38900 390 38901-39000 391 39001-39100 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