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Type | Label | Description |
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Statement | ||
Theorem | asinbnd 26401 | The arcsine function has range within a vertical strip of the complex plane with real part between -Ο / 2 and Ο / 2. (Contributed by Mario Carneiro, 2-Apr-2015.) |
β’ (π΄ β β β (ββ(arcsinβπ΄)) β (-(Ο / 2)[,](Ο / 2))) | ||
Theorem | acosbnd 26402 | The arccosine function has range within a vertical strip of the complex plane with real part between 0 and Ο. (Contributed by Mario Carneiro, 2-Apr-2015.) |
β’ (π΄ β β β (ββ(arccosβπ΄)) β (0[,]Ο)) | ||
Theorem | asinrebnd 26403 | Bounds on the arcsine function. (Contributed by Mario Carneiro, 2-Apr-2015.) |
β’ (π΄ β (-1[,]1) β (arcsinβπ΄) β (-(Ο / 2)[,](Ο / 2))) | ||
Theorem | asinrecl 26404 | The arcsine function is real in its principal domain. (Contributed by Mario Carneiro, 2-Apr-2015.) |
β’ (π΄ β (-1[,]1) β (arcsinβπ΄) β β) | ||
Theorem | acosrecl 26405 | The arccosine function is real in its principal domain. (Contributed by Mario Carneiro, 2-Apr-2015.) |
β’ (π΄ β (-1[,]1) β (arccosβπ΄) β β) | ||
Theorem | cosasin 26406 | The cosine of the arcsine of π΄ is β(1 β π΄β2). (Contributed by Mario Carneiro, 2-Apr-2015.) |
β’ (π΄ β β β (cosβ(arcsinβπ΄)) = (ββ(1 β (π΄β2)))) | ||
Theorem | sinacos 26407 | The sine of the arccosine of π΄ is β(1 β π΄β2). (Contributed by Mario Carneiro, 2-Apr-2015.) |
β’ (π΄ β β β (sinβ(arccosβπ΄)) = (ββ(1 β (π΄β2)))) | ||
Theorem | atandmneg 26408 | The domain of the arctangent function is closed under negatives. (Contributed by Mario Carneiro, 3-Apr-2015.) |
β’ (π΄ β dom arctan β -π΄ β dom arctan) | ||
Theorem | atanneg 26409 | The arctangent function is odd. (Contributed by Mario Carneiro, 3-Apr-2015.) |
β’ (π΄ β dom arctan β (arctanβ-π΄) = -(arctanβπ΄)) | ||
Theorem | atan0 26410 | The arctangent of zero is zero. (Contributed by Mario Carneiro, 31-Mar-2015.) |
β’ (arctanβ0) = 0 | ||
Theorem | atandmcj 26411 | The arctangent function distributes under conjugation. (Contributed by Mario Carneiro, 31-Mar-2015.) |
β’ (π΄ β dom arctan β (ββπ΄) β dom arctan) | ||
Theorem | atancj 26412 | The arctangent function distributes under conjugation. (The condition that β(π΄) β 0 is necessary because the branch cuts are chosen so that the negative imaginary line "agrees with" neighboring values with negative real part, while the positive imaginary line agrees with values with positive real part. This makes atanneg 26409 true unconditionally but messes up conjugation symmetry, and it is impossible to have both in a single-valued function. The claim is true on the imaginary line between -1 and 1, though.) (Contributed by Mario Carneiro, 31-Mar-2015.) |
β’ ((π΄ β β β§ (ββπ΄) β 0) β (π΄ β dom arctan β§ (ββ(arctanβπ΄)) = (arctanβ(ββπ΄)))) | ||
Theorem | atanrecl 26413 | The arctangent function is real for all real inputs. (Contributed by Mario Carneiro, 31-Mar-2015.) |
β’ (π΄ β β β (arctanβπ΄) β β) | ||
Theorem | efiatan 26414 | Value of the exponential of an artcangent. (Contributed by Mario Carneiro, 2-Apr-2015.) |
β’ (π΄ β dom arctan β (expβ(i Β· (arctanβπ΄))) = ((ββ(1 + (i Β· π΄))) / (ββ(1 β (i Β· π΄))))) | ||
Theorem | atanlogaddlem 26415 | Lemma for atanlogadd 26416. (Contributed by Mario Carneiro, 3-Apr-2015.) |
β’ ((π΄ β dom arctan β§ 0 β€ (ββπ΄)) β ((logβ(1 + (i Β· π΄))) + (logβ(1 β (i Β· π΄)))) β ran log) | ||
Theorem | atanlogadd 26416 | The rule β(π§π€) = (βπ§)(βπ€) is not always true on the complex numbers, but it is true when the arguments of π§ and π€ sum to within the interval (-Ο, Ο], so there are some cases such as this one with π§ = 1 + iπ΄ and π€ = 1 β iπ΄ which are true unconditionally. This result can also be stated as "β(1 + π§) + β(1 β π§) is analytic". (Contributed by Mario Carneiro, 3-Apr-2015.) |
β’ (π΄ β dom arctan β ((logβ(1 + (i Β· π΄))) + (logβ(1 β (i Β· π΄)))) β ran log) | ||
Theorem | atanlogsublem 26417 | Lemma for atanlogsub 26418. (Contributed by Mario Carneiro, 4-Apr-2015.) |
β’ ((π΄ β dom arctan β§ 0 < (ββπ΄)) β (ββ((logβ(1 + (i Β· π΄))) β (logβ(1 β (i Β· π΄))))) β (-Ο(,)Ο)) | ||
Theorem | atanlogsub 26418 | A variation on atanlogadd 26416, to show that β(1 + iπ§) / β(1 β iπ§) = β((1 + iπ§) / (1 β iπ§)) under more limited conditions. (Contributed by Mario Carneiro, 4-Apr-2015.) |
β’ ((π΄ β dom arctan β§ (ββπ΄) β 0) β ((logβ(1 + (i Β· π΄))) β (logβ(1 β (i Β· π΄)))) β ran log) | ||
Theorem | efiatan2 26419 | Value of the exponential of an artcangent. (Contributed by Mario Carneiro, 3-Apr-2015.) |
β’ (π΄ β dom arctan β (expβ(i Β· (arctanβπ΄))) = ((1 + (i Β· π΄)) / (ββ(1 + (π΄β2))))) | ||
Theorem | 2efiatan 26420 | Value of the exponential of an artcangent. (Contributed by Mario Carneiro, 2-Apr-2015.) |
β’ (π΄ β dom arctan β (expβ(2 Β· (i Β· (arctanβπ΄)))) = (((2 Β· i) / (π΄ + i)) β 1)) | ||
Theorem | tanatan 26421 | The arctangent function is an inverse to tan. (Contributed by Mario Carneiro, 2-Apr-2015.) |
β’ (π΄ β dom arctan β (tanβ(arctanβπ΄)) = π΄) | ||
Theorem | atandmtan 26422 | The tangent function has range contained in the domain of the arctangent. (Contributed by Mario Carneiro, 31-Mar-2015.) |
β’ ((π΄ β β β§ (cosβπ΄) β 0) β (tanβπ΄) β dom arctan) | ||
Theorem | cosatan 26423 | The cosine of an arctangent. (Contributed by Mario Carneiro, 3-Apr-2015.) |
β’ (π΄ β dom arctan β (cosβ(arctanβπ΄)) = (1 / (ββ(1 + (π΄β2))))) | ||
Theorem | cosatanne0 26424 | The arctangent function has range contained in the domain of the tangent. (Contributed by Mario Carneiro, 3-Apr-2015.) |
β’ (π΄ β dom arctan β (cosβ(arctanβπ΄)) β 0) | ||
Theorem | atantan 26425 | The arctangent function is an inverse to tan. (Contributed by Mario Carneiro, 5-Apr-2015.) |
β’ ((π΄ β β β§ (ββπ΄) β (-(Ο / 2)(,)(Ο / 2))) β (arctanβ(tanβπ΄)) = π΄) | ||
Theorem | atantanb 26426 | Relationship between tangent and arctangent. (Contributed by Mario Carneiro, 5-Apr-2015.) |
β’ ((π΄ β dom arctan β§ π΅ β β β§ (ββπ΅) β (-(Ο / 2)(,)(Ο / 2))) β ((arctanβπ΄) = π΅ β (tanβπ΅) = π΄)) | ||
Theorem | atanbndlem 26427 | Lemma for atanbnd 26428. (Contributed by Mario Carneiro, 5-Apr-2015.) |
β’ (π΄ β β+ β (arctanβπ΄) β (-(Ο / 2)(,)(Ο / 2))) | ||
Theorem | atanbnd 26428 | The arctangent function is bounded by Ο / 2 on the reals. (Contributed by Mario Carneiro, 5-Apr-2015.) |
β’ (π΄ β β β (arctanβπ΄) β (-(Ο / 2)(,)(Ο / 2))) | ||
Theorem | atanord 26429 | The arctangent function is strictly increasing. (Contributed by Mario Carneiro, 5-Apr-2015.) |
β’ ((π΄ β β β§ π΅ β β) β (π΄ < π΅ β (arctanβπ΄) < (arctanβπ΅))) | ||
Theorem | atan1 26430 | The arctangent of 1 is Ο / 4. (Contributed by Mario Carneiro, 2-Apr-2015.) |
β’ (arctanβ1) = (Ο / 4) | ||
Theorem | bndatandm 26431 | A point in the open unit disk is in the domain of the arctangent. (Contributed by Mario Carneiro, 5-Apr-2015.) |
β’ ((π΄ β β β§ (absβπ΄) < 1) β π΄ β dom arctan) | ||
Theorem | atans 26432* | The "domain of continuity" of the arctangent. (Contributed by Mario Carneiro, 7-Apr-2015.) |
β’ π· = (β β (-β(,]0)) & β’ π = {π¦ β β β£ (1 + (π¦β2)) β π·} β β’ (π΄ β π β (π΄ β β β§ (1 + (π΄β2)) β π·)) | ||
Theorem | atans2 26433* | It suffices to show that 1 β iπ΄ and 1 + iπ΄ are in the continuity domain of log to show that π΄ is in the continuity domain of arctangent. (Contributed by Mario Carneiro, 7-Apr-2015.) |
β’ π· = (β β (-β(,]0)) & β’ π = {π¦ β β β£ (1 + (π¦β2)) β π·} β β’ (π΄ β π β (π΄ β β β§ (1 β (i Β· π΄)) β π· β§ (1 + (i Β· π΄)) β π·)) | ||
Theorem | atansopn 26434* | The domain of continuity of the arctangent is an open set. (Contributed by Mario Carneiro, 7-Apr-2015.) |
β’ π· = (β β (-β(,]0)) & β’ π = {π¦ β β β£ (1 + (π¦β2)) β π·} β β’ π β (TopOpenββfld) | ||
Theorem | atansssdm 26435* | The domain of continuity of the arctangent is a subset of the actual domain of the arctangent. (Contributed by Mario Carneiro, 7-Apr-2015.) |
β’ π· = (β β (-β(,]0)) & β’ π = {π¦ β β β£ (1 + (π¦β2)) β π·} β β’ π β dom arctan | ||
Theorem | ressatans 26436* | The real number line is a subset of the domain of continuity of the arctangent. (Contributed by Mario Carneiro, 7-Apr-2015.) |
β’ π· = (β β (-β(,]0)) & β’ π = {π¦ β β β£ (1 + (π¦β2)) β π·} β β’ β β π | ||
Theorem | dvatan 26437* | The derivative of the arctangent. (Contributed by Mario Carneiro, 7-Apr-2015.) |
β’ π· = (β β (-β(,]0)) & β’ π = {π¦ β β β£ (1 + (π¦β2)) β π·} β β’ (β D (arctan βΎ π)) = (π₯ β π β¦ (1 / (1 + (π₯β2)))) | ||
Theorem | atancn 26438* | The arctangent is a continuous function. (Contributed by Mario Carneiro, 7-Apr-2015.) |
β’ π· = (β β (-β(,]0)) & β’ π = {π¦ β β β£ (1 + (π¦β2)) β π·} β β’ (arctan βΎ π) β (πβcnββ) | ||
Theorem | atantayl 26439* | The Taylor series for arctan(π΄). (Contributed by Mario Carneiro, 1-Apr-2015.) |
β’ πΉ = (π β β β¦ (((i Β· ((-iβπ) β (iβπ))) / 2) Β· ((π΄βπ) / π))) β β’ ((π΄ β β β§ (absβπ΄) < 1) β seq1( + , πΉ) β (arctanβπ΄)) | ||
Theorem | atantayl2 26440* | The Taylor series for arctan(π΄). (Contributed by Mario Carneiro, 1-Apr-2015.) |
β’ πΉ = (π β β β¦ if(2 β₯ π, 0, ((-1β((π β 1) / 2)) Β· ((π΄βπ) / π)))) β β’ ((π΄ β β β§ (absβπ΄) < 1) β seq1( + , πΉ) β (arctanβπ΄)) | ||
Theorem | atantayl3 26441* | The Taylor series for arctan(π΄). (Contributed by Mario Carneiro, 7-Apr-2015.) |
β’ πΉ = (π β β0 β¦ ((-1βπ) Β· ((π΄β((2 Β· π) + 1)) / ((2 Β· π) + 1)))) β β’ ((π΄ β β β§ (absβπ΄) < 1) β seq0( + , πΉ) β (arctanβπ΄)) | ||
Theorem | leibpilem1 26442 | Lemma for leibpi 26444. (Contributed by Mario Carneiro, 7-Apr-2015.) (Proof shortened by Steven Nguyen, 23-Mar-2023.) |
β’ ((π β β0 β§ (Β¬ π = 0 β§ Β¬ 2 β₯ π)) β (π β β β§ ((π β 1) / 2) β β0)) | ||
Theorem | leibpilem2 26443* | The Leibniz formula for Ο. (Contributed by Mario Carneiro, 7-Apr-2015.) |
β’ πΉ = (π β β0 β¦ ((-1βπ) / ((2 Β· π) + 1))) & β’ πΊ = (π β β0 β¦ if((π = 0 β¨ 2 β₯ π), 0, ((-1β((π β 1) / 2)) / π))) & β’ π΄ β V β β’ (seq0( + , πΉ) β π΄ β seq0( + , πΊ) β π΄) | ||
Theorem | leibpi 26444 | The Leibniz formula for Ο. This proof depends on three main facts: (1) the series πΉ is convergent, because it is an alternating series (iseralt 15630). (2) Using leibpilem2 26443 to rewrite the series as a power series, it is the π₯ = 1 special case of the Taylor series for arctan (atantayl2 26440). (3) Although we cannot directly plug π₯ = 1 into atantayl2 26440, Abel's theorem (abelth2 25953) says that the limit along any sequence converging to 1, such as 1 β 1 / π, of the power series converges to the power series extended to 1, and then since arctan is continuous at 1 (atancn 26438) we get the desired result. This is Metamath 100 proof #26. (Contributed by Mario Carneiro, 7-Apr-2015.) |
β’ πΉ = (π β β0 β¦ ((-1βπ) / ((2 Β· π) + 1))) β β’ seq0( + , πΉ) β (Ο / 4) | ||
Theorem | leibpisum 26445 | The Leibniz formula for Ο. This version of leibpi 26444 looks nicer but does not assert that the series is convergent so is not as practically useful. (Contributed by Mario Carneiro, 7-Apr-2015.) |
β’ Ξ£π β β0 ((-1βπ) / ((2 Β· π) + 1)) = (Ο / 4) | ||
Theorem | log2cnv 26446 | Using the Taylor series for arctan(i / 3), produce a rapidly convergent series for log2. (Contributed by Mario Carneiro, 7-Apr-2015.) |
β’ πΉ = (π β β0 β¦ (2 / ((3 Β· ((2 Β· π) + 1)) Β· (9βπ)))) β β’ seq0( + , πΉ) β (logβ2) | ||
Theorem | log2tlbnd 26447* | Bound the error term in the series of log2cnv 26446. (Contributed by Mario Carneiro, 7-Apr-2015.) |
β’ (π β β0 β ((logβ2) β Ξ£π β (0...(π β 1))(2 / ((3 Β· ((2 Β· π) + 1)) Β· (9βπ)))) β (0[,](3 / ((4 Β· ((2 Β· π) + 1)) Β· (9βπ))))) | ||
Theorem | log2ublem1 26448 | Lemma for log2ub 26451. The proof of log2ub 26451, which is simply the evaluation of log2tlbnd 26447 for π = 4, takes the form of the addition of five fractions and showing this is less than another fraction. We could just perform exact arithmetic on these fractions, get a large rational number, and just multiply everything to verify the claim, but as anyone who uses decimal numbers for this task knows, it is often better to pick a common denominator π (usually a large power of 10) and work with the closest approximations of the form π / π for some integer π instead. It turns out that for our purposes it is sufficient to take π = (3β7) Β· 5 Β· 7, which is also nice because it shares many factors in common with the fractions in question. (Contributed by Mario Carneiro, 17-Apr-2015.) |
β’ (((3β7) Β· (5 Β· 7)) Β· π΄) β€ π΅ & β’ π΄ β β & β’ π· β β0 & β’ πΈ β β & β’ π΅ β β0 & β’ πΉ β β0 & β’ πΆ = (π΄ + (π· / πΈ)) & β’ (π΅ + πΉ) = πΊ & β’ (((3β7) Β· (5 Β· 7)) Β· π·) β€ (πΈ Β· πΉ) β β’ (((3β7) Β· (5 Β· 7)) Β· πΆ) β€ πΊ | ||
Theorem | log2ublem2 26449* | Lemma for log2ub 26451. (Contributed by Mario Carneiro, 17-Apr-2015.) |
β’ (((3β7) Β· (5 Β· 7)) Β· Ξ£π β (0...πΎ)(2 / ((3 Β· ((2 Β· π) + 1)) Β· (9βπ)))) β€ (2 Β· π΅) & β’ π΅ β β0 & β’ πΉ β β0 & β’ π β β0 & β’ (π β 1) = πΎ & β’ (π΅ + πΉ) = πΊ & β’ π β β0 & β’ (π + π) = 3 & β’ ((5 Β· 7) Β· (9βπ)) = (((2 Β· π) + 1) Β· πΉ) β β’ (((3β7) Β· (5 Β· 7)) Β· Ξ£π β (0...π)(2 / ((3 Β· ((2 Β· π) + 1)) Β· (9βπ)))) β€ (2 Β· πΊ) | ||
Theorem | log2ublem3 26450 | Lemma for log2ub 26451. In decimal, this is a proof that the first four terms of the series for log2 is less than 53056 / 76545. (Contributed by Mario Carneiro, 17-Apr-2015.) (Proof shortened by AV, 15-Sep-2021.) |
β’ (((3β7) Β· (5 Β· 7)) Β· Ξ£π β (0...3)(2 / ((3 Β· ((2 Β· π) + 1)) Β· (9βπ)))) β€ ;;;;53056 | ||
Theorem | log2ub 26451 | log2 is less than 253 / 365. If written in decimal, this is because log2 = 0.693147... is less than 253/365 = 0.693151... , so this is a very tight bound, at five decimal places. (Contributed by Mario Carneiro, 7-Apr-2015.) (Proof shortened by AV, 16-Sep-2021.) |
β’ (logβ2) < (;;253 / ;;365) | ||
Theorem | log2le1 26452 | log2 is less than 1. This is just a weaker form of log2ub 26451 when no tight upper bound is required. (Contributed by Thierry Arnoux, 27-Sep-2017.) |
β’ (logβ2) < 1 | ||
Theorem | birthdaylem1 26453* | Lemma for birthday 26456. (Contributed by Mario Carneiro, 17-Apr-2015.) |
β’ π = {π β£ π:(1...πΎ)βΆ(1...π)} & β’ π = {π β£ π:(1...πΎ)β1-1β(1...π)} β β’ (π β π β§ π β Fin β§ (π β β β π β β )) | ||
Theorem | birthdaylem2 26454* | For general π and πΎ, count the fraction of injective functions from 1...πΎ to 1...π. (Contributed by Mario Carneiro, 7-May-2015.) |
β’ π = {π β£ π:(1...πΎ)βΆ(1...π)} & β’ π = {π β£ π:(1...πΎ)β1-1β(1...π)} β β’ ((π β β β§ πΎ β (0...π)) β ((β―βπ) / (β―βπ)) = (expβΞ£π β (0...(πΎ β 1))(logβ(1 β (π / π))))) | ||
Theorem | birthdaylem3 26455* | For general π and πΎ, upper-bound the fraction of injective functions from 1...πΎ to 1...π. (Contributed by Mario Carneiro, 17-Apr-2015.) |
β’ π = {π β£ π:(1...πΎ)βΆ(1...π)} & β’ π = {π β£ π:(1...πΎ)β1-1β(1...π)} β β’ ((πΎ β β0 β§ π β β) β ((β―βπ) / (β―βπ)) β€ (expβ-((((πΎβ2) β πΎ) / 2) / π))) | ||
Theorem | birthday 26456* | The Birthday Problem. There is a more than even chance that out of 23 people in a room, at least two of them have the same birthday. Mathematically, this is asserting that for πΎ = 23 and π = 365, fewer than half of the set of all functions from 1...πΎ to 1...π are injective. This is Metamath 100 proof #93. (Contributed by Mario Carneiro, 17-Apr-2015.) |
β’ π = {π β£ π:(1...πΎ)βΆ(1...π)} & β’ π = {π β£ π:(1...πΎ)β1-1β(1...π)} & β’ πΎ = ;23 & β’ π = ;;365 β β’ ((β―βπ) / (β―βπ)) < (1 / 2) | ||
Syntax | carea 26457 | Area of regions in the complex plane. |
class area | ||
Definition | df-area 26458* | Define the area of a subset of β Γ β. (Contributed by Mario Carneiro, 21-Jun-2015.) |
β’ area = (π β {π‘ β π« (β Γ β) β£ (βπ₯ β β (π‘ β {π₯}) β (β‘vol β β) β§ (π₯ β β β¦ (volβ(π‘ β {π₯}))) β πΏ1)} β¦ β«β(volβ(π β {π₯})) dπ₯) | ||
Theorem | dmarea 26459* | The domain of the area function is the set of finitely measurable subsets of β Γ β. (Contributed by Mario Carneiro, 21-Jun-2015.) |
β’ (π΄ β dom area β (π΄ β (β Γ β) β§ βπ₯ β β (π΄ β {π₯}) β (β‘vol β β) β§ (π₯ β β β¦ (volβ(π΄ β {π₯}))) β πΏ1)) | ||
Theorem | areambl 26460 | The fibers of a measurable region are finitely measurable subsets of β. (Contributed by Mario Carneiro, 21-Jun-2015.) |
β’ ((π β dom area β§ π΄ β β) β ((π β {π΄}) β dom vol β§ (volβ(π β {π΄})) β β)) | ||
Theorem | areass 26461 | A measurable region is a subset of β Γ β. (Contributed by Mario Carneiro, 21-Jun-2015.) |
β’ (π β dom area β π β (β Γ β)) | ||
Theorem | dfarea 26462* | Rewrite df-area 26458 self-referentially. (Contributed by Mario Carneiro, 21-Jun-2015.) |
β’ area = (π β dom area β¦ β«β(volβ(π β {π₯})) dπ₯) | ||
Theorem | areaf 26463 | Area measurement is a function whose values are nonnegative reals. (Contributed by Mario Carneiro, 21-Jun-2015.) |
β’ area:dom areaβΆ(0[,)+β) | ||
Theorem | areacl 26464 | The area of a measurable region is a real number. (Contributed by Mario Carneiro, 21-Jun-2015.) |
β’ (π β dom area β (areaβπ) β β) | ||
Theorem | areage0 26465 | The area of a measurable region is greater than or equal to zero. (Contributed by Mario Carneiro, 21-Jun-2015.) |
β’ (π β dom area β 0 β€ (areaβπ)) | ||
Theorem | areaval 26466* | The area of a measurable region is greater than or equal to zero. (Contributed by Mario Carneiro, 21-Jun-2015.) |
β’ (π β dom area β (areaβπ) = β«β(volβ(π β {π₯})) dπ₯) | ||
Theorem | rlimcnp 26467* | Relate a limit of a real-valued sequence at infinity to the continuity of the function π(π¦) = π (1 / π¦) at zero. (Contributed by Mario Carneiro, 1-Mar-2015.) |
β’ (π β π΄ β (0[,)+β)) & β’ (π β 0 β π΄) & β’ (π β π΅ β β+) & β’ ((π β§ π₯ β π΄) β π β β) & β’ ((π β§ π₯ β β+) β (π₯ β π΄ β (1 / π₯) β π΅)) & β’ (π₯ = 0 β π = πΆ) & β’ (π₯ = (1 / π¦) β π = π) & β’ π½ = (TopOpenββfld) & β’ πΎ = (π½ βΎt π΄) β β’ (π β ((π¦ β π΅ β¦ π) βπ πΆ β (π₯ β π΄ β¦ π ) β ((πΎ CnP π½)β0))) | ||
Theorem | rlimcnp2 26468* | Relate a limit of a real-valued sequence at infinity to the continuity of the function π(π¦) = π (1 / π¦) at zero. (Contributed by Mario Carneiro, 1-Mar-2015.) |
β’ (π β π΄ β (0[,)+β)) & β’ (π β 0 β π΄) & β’ (π β π΅ β β) & β’ (π β πΆ β β) & β’ ((π β§ π¦ β π΅) β π β β) & β’ ((π β§ π¦ β β+) β (π¦ β π΅ β (1 / π¦) β π΄)) & β’ (π¦ = (1 / π₯) β π = π ) & β’ π½ = (TopOpenββfld) & β’ πΎ = (π½ βΎt π΄) β β’ (π β ((π¦ β π΅ β¦ π) βπ πΆ β (π₯ β π΄ β¦ if(π₯ = 0, πΆ, π )) β ((πΎ CnP π½)β0))) | ||
Theorem | rlimcnp3 26469* | Relate a limit of a real-valued sequence at infinity to the continuity of the function π(π¦) = π (1 / π¦) at zero. (Contributed by Mario Carneiro, 1-Mar-2015.) |
β’ (π β πΆ β β) & β’ ((π β§ π¦ β β+) β π β β) & β’ (π¦ = (1 / π₯) β π = π ) & β’ π½ = (TopOpenββfld) & β’ πΎ = (π½ βΎt (0[,)+β)) β β’ (π β ((π¦ β β+ β¦ π) βπ πΆ β (π₯ β (0[,)+β) β¦ if(π₯ = 0, πΆ, π )) β ((πΎ CnP π½)β0))) | ||
Theorem | xrlimcnp 26470* | Relate a limit of a real-valued sequence at infinity to the continuity of the corresponding extended real function at +β. Since any βπ limit can be written in the form on the left side of the implication, this shows that real limits are a special case of topological continuity at a point. (Contributed by Mario Carneiro, 8-Sep-2015.) |
β’ (π β π΄ = (π΅ βͺ {+β})) & β’ (π β π΅ β β) & β’ ((π β§ π₯ β π΄) β π β β) & β’ (π₯ = +β β π = πΆ) & β’ π½ = (TopOpenββfld) & β’ πΎ = ((ordTopβ β€ ) βΎt π΄) β β’ (π β ((π₯ β π΅ β¦ π ) βπ πΆ β (π₯ β π΄ β¦ π ) β ((πΎ CnP π½)β+β))) | ||
Theorem | efrlim 26471* | The limit of the sequence (1 + π΄ / π)βπ is the exponential function. This is often taken as an alternate definition of the exponential function (see also dfef2 26472). (Contributed by Mario Carneiro, 1-Mar-2015.) |
β’ π = (0(ballβ(abs β β ))(1 / ((absβπ΄) + 1))) β β’ (π΄ β β β (π β β+ β¦ ((1 + (π΄ / π))βππ)) βπ (expβπ΄)) | ||
Theorem | dfef2 26472* | The limit of the sequence (1 + π΄ / π)βπ as π goes to +β is (expβπ΄). This is another common definition of e. (Contributed by Mario Carneiro, 1-Mar-2015.) |
β’ (π β πΉ β π) & β’ (π β π΄ β β) & β’ ((π β§ π β β) β (πΉβπ) = ((1 + (π΄ / π))βπ)) β β’ (π β πΉ β (expβπ΄)) | ||
Theorem | cxplim 26473* | A power to a negative exponent goes to zero as the base becomes large. (Contributed by Mario Carneiro, 15-Sep-2014.) (Revised by Mario Carneiro, 18-May-2016.) |
β’ (π΄ β β+ β (π β β+ β¦ (1 / (πβππ΄))) βπ 0) | ||
Theorem | sqrtlim 26474 | The inverse square root function converges to zero. (Contributed by Mario Carneiro, 18-May-2016.) |
β’ (π β β+ β¦ (1 / (ββπ))) βπ 0 | ||
Theorem | rlimcxp 26475* | Any power to a positive exponent of a converging sequence also converges. (Contributed by Mario Carneiro, 18-Sep-2014.) |
β’ ((π β§ π β π΄) β π΅ β π) & β’ (π β (π β π΄ β¦ π΅) βπ 0) & β’ (π β πΆ β β+) β β’ (π β (π β π΄ β¦ (π΅βππΆ)) βπ 0) | ||
Theorem | o1cxp 26476* | An eventually bounded function taken to a nonnegative power is eventually bounded. (Contributed by Mario Carneiro, 15-Sep-2014.) |
β’ (π β πΆ β β) & β’ (π β 0 β€ (ββπΆ)) & β’ ((π β§ π₯ β π΄) β π΅ β π) & β’ (π β (π₯ β π΄ β¦ π΅) β π(1)) β β’ (π β (π₯ β π΄ β¦ (π΅βππΆ)) β π(1)) | ||
Theorem | cxp2limlem 26477* | A linear factor grows slower than any exponential with base greater than 1. (Contributed by Mario Carneiro, 15-Sep-2014.) |
β’ ((π΄ β β β§ 1 < π΄) β (π β β+ β¦ (π / (π΄βππ))) βπ 0) | ||
Theorem | cxp2lim 26478* | Any power grows slower than any exponential with base greater than 1. (Contributed by Mario Carneiro, 18-Sep-2014.) |
β’ ((π΄ β β β§ π΅ β β β§ 1 < π΅) β (π β β+ β¦ ((πβππ΄) / (π΅βππ))) βπ 0) | ||
Theorem | cxploglim 26479* | The logarithm grows slower than any positive power. (Contributed by Mario Carneiro, 18-Sep-2014.) |
β’ (π΄ β β+ β (π β β+ β¦ ((logβπ) / (πβππ΄))) βπ 0) | ||
Theorem | cxploglim2 26480* | Every power of the logarithm grows slower than any positive power. (Contributed by Mario Carneiro, 20-May-2016.) |
β’ ((π΄ β β β§ π΅ β β+) β (π β β+ β¦ (((logβπ)βππ΄) / (πβππ΅))) βπ 0) | ||
Theorem | divsqrtsumlem 26481* | Lemma for divsqrsum 26483 and divsqrtsum2 26484. (Contributed by Mario Carneiro, 18-May-2016.) |
β’ πΉ = (π₯ β β+ β¦ (Ξ£π β (1...(ββπ₯))(1 / (ββπ)) β (2 Β· (ββπ₯)))) β β’ (πΉ:β+βΆβ β§ πΉ β dom βπ β§ ((πΉ βπ πΏ β§ π΄ β β+) β (absβ((πΉβπ΄) β πΏ)) β€ (1 / (ββπ΄)))) | ||
Theorem | divsqrsumf 26482* | The function πΉ used in divsqrsum 26483 is a real function. (Contributed by Mario Carneiro, 12-May-2016.) |
β’ πΉ = (π₯ β β+ β¦ (Ξ£π β (1...(ββπ₯))(1 / (ββπ)) β (2 Β· (ββπ₯)))) β β’ πΉ:β+βΆβ | ||
Theorem | divsqrsum 26483* | The sum Ξ£π β€ π₯(1 / βπ) is asymptotic to 2βπ₯ + πΏ with a finite limit πΏ. (In fact, this limit is ΞΆ(1 / 2) β -1.46....) (Contributed by Mario Carneiro, 9-May-2016.) |
β’ πΉ = (π₯ β β+ β¦ (Ξ£π β (1...(ββπ₯))(1 / (ββπ)) β (2 Β· (ββπ₯)))) β β’ πΉ β dom βπ | ||
Theorem | divsqrtsum2 26484* | A bound on the distance of the sum Ξ£π β€ π₯(1 / βπ) from its asymptotic value 2βπ₯ + πΏ. (Contributed by Mario Carneiro, 18-May-2016.) |
β’ πΉ = (π₯ β β+ β¦ (Ξ£π β (1...(ββπ₯))(1 / (ββπ)) β (2 Β· (ββπ₯)))) & β’ (π β πΉ βπ πΏ) β β’ ((π β§ π΄ β β+) β (absβ((πΉβπ΄) β πΏ)) β€ (1 / (ββπ΄))) | ||
Theorem | divsqrtsumo1 26485* | The sum Ξ£π β€ π₯(1 / βπ) has the asymptotic expansion 2βπ₯ + πΏ + π(1 / βπ₯), for some πΏ. (Contributed by Mario Carneiro, 10-May-2016.) |
β’ πΉ = (π₯ β β+ β¦ (Ξ£π β (1...(ββπ₯))(1 / (ββπ)) β (2 Β· (ββπ₯)))) & β’ (π β πΉ βπ πΏ) β β’ (π β (π¦ β β+ β¦ (((πΉβπ¦) β πΏ) Β· (ββπ¦))) β π(1)) | ||
Theorem | cvxcl 26486* | Closure of a 0-1 linear combination in a convex set. (Contributed by Mario Carneiro, 21-Jun-2015.) |
β’ (π β π· β β) & β’ ((π β§ (π₯ β π· β§ π¦ β π·)) β (π₯[,]π¦) β π·) β β’ ((π β§ (π β π· β§ π β π· β§ π β (0[,]1))) β ((π Β· π) + ((1 β π) Β· π)) β π·) | ||
Theorem | scvxcvx 26487* | A strictly convex function is convex. (Contributed by Mario Carneiro, 20-Jun-2015.) |
β’ (π β π· β β) & β’ (π β πΉ:π·βΆβ) & β’ ((π β§ (π β π· β§ π β π·)) β (π[,]π) β π·) & β’ ((π β§ (π₯ β π· β§ π¦ β π· β§ π₯ < π¦) β§ π‘ β (0(,)1)) β (πΉβ((π‘ Β· π₯) + ((1 β π‘) Β· π¦))) < ((π‘ Β· (πΉβπ₯)) + ((1 β π‘) Β· (πΉβπ¦)))) β β’ ((π β§ (π β π· β§ π β π· β§ π β (0[,]1))) β (πΉβ((π Β· π) + ((1 β π) Β· π))) β€ ((π Β· (πΉβπ)) + ((1 β π) Β· (πΉβπ)))) | ||
Theorem | jensenlem1 26488* | Lemma for jensen 26490. (Contributed by Mario Carneiro, 4-Jun-2016.) |
β’ (π β π· β β) & β’ (π β πΉ:π·βΆβ) & β’ ((π β§ (π β π· β§ π β π·)) β (π[,]π) β π·) & β’ (π β π΄ β Fin) & β’ (π β π:π΄βΆ(0[,)+β)) & β’ (π β π:π΄βΆπ·) & β’ (π β 0 < (βfld Ξ£g π)) & β’ ((π β§ (π₯ β π· β§ π¦ β π· β§ π‘ β (0[,]1))) β (πΉβ((π‘ Β· π₯) + ((1 β π‘) Β· π¦))) β€ ((π‘ Β· (πΉβπ₯)) + ((1 β π‘) Β· (πΉβπ¦)))) & β’ (π β Β¬ π§ β π΅) & β’ (π β (π΅ βͺ {π§}) β π΄) & β’ π = (βfld Ξ£g (π βΎ π΅)) & β’ πΏ = (βfld Ξ£g (π βΎ (π΅ βͺ {π§}))) β β’ (π β πΏ = (π + (πβπ§))) | ||
Theorem | jensenlem2 26489* | Lemma for jensen 26490. (Contributed by Mario Carneiro, 21-Jun-2015.) |
β’ (π β π· β β) & β’ (π β πΉ:π·βΆβ) & β’ ((π β§ (π β π· β§ π β π·)) β (π[,]π) β π·) & β’ (π β π΄ β Fin) & β’ (π β π:π΄βΆ(0[,)+β)) & β’ (π β π:π΄βΆπ·) & β’ (π β 0 < (βfld Ξ£g π)) & β’ ((π β§ (π₯ β π· β§ π¦ β π· β§ π‘ β (0[,]1))) β (πΉβ((π‘ Β· π₯) + ((1 β π‘) Β· π¦))) β€ ((π‘ Β· (πΉβπ₯)) + ((1 β π‘) Β· (πΉβπ¦)))) & β’ (π β Β¬ π§ β π΅) & β’ (π β (π΅ βͺ {π§}) β π΄) & β’ π = (βfld Ξ£g (π βΎ π΅)) & β’ πΏ = (βfld Ξ£g (π βΎ (π΅ βͺ {π§}))) & β’ (π β π β β+) & β’ (π β ((βfld Ξ£g ((π βf Β· π) βΎ π΅)) / π) β π·) & β’ (π β (πΉβ((βfld Ξ£g ((π βf Β· π) βΎ π΅)) / π)) β€ ((βfld Ξ£g ((π βf Β· (πΉ β π)) βΎ π΅)) / π)) β β’ (π β (((βfld Ξ£g ((π βf Β· π) βΎ (π΅ βͺ {π§}))) / πΏ) β π· β§ (πΉβ((βfld Ξ£g ((π βf Β· π) βΎ (π΅ βͺ {π§}))) / πΏ)) β€ ((βfld Ξ£g ((π βf Β· (πΉ β π)) βΎ (π΅ βͺ {π§}))) / πΏ))) | ||
Theorem | jensen 26490* | Jensen's inequality, a finite extension of the definition of convexity (the last hypothesis). (Contributed by Mario Carneiro, 21-Jun-2015.) (Proof shortened by AV, 27-Jul-2019.) |
β’ (π β π· β β) & β’ (π β πΉ:π·βΆβ) & β’ ((π β§ (π β π· β§ π β π·)) β (π[,]π) β π·) & β’ (π β π΄ β Fin) & β’ (π β π:π΄βΆ(0[,)+β)) & β’ (π β π:π΄βΆπ·) & β’ (π β 0 < (βfld Ξ£g π)) & β’ ((π β§ (π₯ β π· β§ π¦ β π· β§ π‘ β (0[,]1))) β (πΉβ((π‘ Β· π₯) + ((1 β π‘) Β· π¦))) β€ ((π‘ Β· (πΉβπ₯)) + ((1 β π‘) Β· (πΉβπ¦)))) β β’ (π β (((βfld Ξ£g (π βf Β· π)) / (βfld Ξ£g π)) β π· β§ (πΉβ((βfld Ξ£g (π βf Β· π)) / (βfld Ξ£g π))) β€ ((βfld Ξ£g (π βf Β· (πΉ β π))) / (βfld Ξ£g π)))) | ||
Theorem | amgmlem 26491 | Lemma for amgm 26492. (Contributed by Mario Carneiro, 21-Jun-2015.) |
β’ π = (mulGrpββfld) & β’ (π β π΄ β Fin) & β’ (π β π΄ β β ) & β’ (π β πΉ:π΄βΆβ+) β β’ (π β ((π Ξ£g πΉ)βπ(1 / (β―βπ΄))) β€ ((βfld Ξ£g πΉ) / (β―βπ΄))) | ||
Theorem | amgm 26492 | Inequality of arithmetic and geometric means. Here (π Ξ£g πΉ) calculates the group sum within the multiplicative monoid of the complex numbers (or in other words, it multiplies the elements πΉ(π₯), π₯ β π΄ together), and (βfld Ξ£g πΉ) calculates the group sum in the additive group (i.e. the sum of the elements). This is Metamath 100 proof #38. (Contributed by Mario Carneiro, 20-Jun-2015.) |
β’ π = (mulGrpββfld) β β’ ((π΄ β Fin β§ π΄ β β β§ πΉ:π΄βΆ(0[,)+β)) β ((π Ξ£g πΉ)βπ(1 / (β―βπ΄))) β€ ((βfld Ξ£g πΉ) / (β―βπ΄))) | ||
Syntax | cem 26493 | The Euler-Mascheroni constant. (The label abbreviates Euler-Mascheroni.) |
class Ξ³ | ||
Definition | df-em 26494 | Define the Euler-Mascheroni constant, Ξ³ = 0.57721.... This is the limit of the series Ξ£π β (1...π)(1 / π) β (logβπ), with a proof that the limit exists in emcl 26504. (Contributed by Mario Carneiro, 11-Jul-2014.) |
β’ Ξ³ = Ξ£π β β ((1 / π) β (logβ(1 + (1 / π)))) | ||
Theorem | logdifbnd 26495 | Bound on the difference of logs. (Contributed by Mario Carneiro, 23-May-2016.) |
β’ (π΄ β β+ β ((logβ(π΄ + 1)) β (logβπ΄)) β€ (1 / π΄)) | ||
Theorem | logdiflbnd 26496 | Lower bound on the difference of logs. (Contributed by Mario Carneiro, 3-Jul-2017.) |
β’ (π΄ β β+ β (1 / (π΄ + 1)) β€ ((logβ(π΄ + 1)) β (logβπ΄))) | ||
Theorem | emcllem1 26497* | Lemma for emcl 26504. The series πΉ and πΊ are sequences of real numbers that approach Ξ³ from above and below, respectively. (Contributed by Mario Carneiro, 11-Jul-2014.) |
β’ πΉ = (π β β β¦ (Ξ£π β (1...π)(1 / π) β (logβπ))) & β’ πΊ = (π β β β¦ (Ξ£π β (1...π)(1 / π) β (logβ(π + 1)))) β β’ (πΉ:ββΆβ β§ πΊ:ββΆβ) | ||
Theorem | emcllem2 26498* | Lemma for emcl 26504. πΉ is increasing, and πΊ is decreasing. (Contributed by Mario Carneiro, 11-Jul-2014.) |
β’ πΉ = (π β β β¦ (Ξ£π β (1...π)(1 / π) β (logβπ))) & β’ πΊ = (π β β β¦ (Ξ£π β (1...π)(1 / π) β (logβ(π + 1)))) β β’ (π β β β ((πΉβ(π + 1)) β€ (πΉβπ) β§ (πΊβπ) β€ (πΊβ(π + 1)))) | ||
Theorem | emcllem3 26499* | Lemma for emcl 26504. The function π» is the difference between πΉ and πΊ. (Contributed by Mario Carneiro, 11-Jul-2014.) |
β’ πΉ = (π β β β¦ (Ξ£π β (1...π)(1 / π) β (logβπ))) & β’ πΊ = (π β β β¦ (Ξ£π β (1...π)(1 / π) β (logβ(π + 1)))) & β’ π» = (π β β β¦ (logβ(1 + (1 / π)))) β β’ (π β β β (π»βπ) = ((πΉβπ) β (πΊβπ))) | ||
Theorem | emcllem4 26500* | Lemma for emcl 26504. The difference between series πΉ and πΊ tends to zero. (Contributed by Mario Carneiro, 11-Jul-2014.) |
β’ πΉ = (π β β β¦ (Ξ£π β (1...π)(1 / π) β (logβπ))) & β’ πΊ = (π β β β¦ (Ξ£π β (1...π)(1 / π) β (logβ(π + 1)))) & β’ π» = (π β β β¦ (logβ(1 + (1 / π)))) β β’ π» β 0 |
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