P. 340 of Theorem List - Metamath Proof Explorer

Theorem List for Metamath Proof Explorer - 33901-34000   *Has distinct variable group(s)

Type	Label	Description
Statement
Theorem	drgextlsp 33901	The scalar field is a subspace of a subring algebra. (Contributed by Thierry Arnoux, 17-Jul-2023.)
⊢ 𝐵 = ((subringAlg ‘𝐸)‘𝑈)    &   ⊢ (𝜑 → 𝐸 ∈ DivRing)    &   ⊢ (𝜑 → 𝑈 ∈ (SubRing‘𝐸))    &   ⊢ 𝐹 = (𝐸 ↾s 𝑈)    &   ⊢ (𝜑 → 𝐹 ∈ DivRing)    ⇒   ⊢ (𝜑 → 𝑈 ∈ (LSubSp‘𝐵))
Theorem	drgextgsum 33902*	Group sum in a division ring extension. (Contributed by Thierry Arnoux, 17-Jul-2023.)
⊢ 𝐵 = ((subringAlg ‘𝐸)‘𝑈)    &   ⊢ (𝜑 → 𝐸 ∈ DivRing)    &   ⊢ (𝜑 → 𝑈 ∈ (SubRing‘𝐸))    &   ⊢ 𝐹 = (𝐸 ↾s 𝑈)    &   ⊢ (𝜑 → 𝐹 ∈ DivRing)    &   ⊢ (𝜑 → 𝑋 ∈ 𝑉)    ⇒   ⊢ (𝜑 → (𝐸 Σg (𝑖 ∈ 𝑋 ↦ 𝑌)) = (𝐵 Σg (𝑖 ∈ 𝑋 ↦ 𝑌)))
21.3.10.53  Vector Spaces
Theorem	lvecdimfi 33903	Finite version of lvecdim 21250 which does not require the axiom of choice. The axiom of choice is used in acsmapd 18600, which is required in the infinite case. Suggested by Gérard Lang. (Contributed by Thierry Arnoux, 24-May-2023.)
⊢ 𝐽 = (LBasis‘𝑊)    &   ⊢ (𝜑 → 𝑊 ∈ LVec)    &   ⊢ (𝜑 → 𝑆 ∈ 𝐽)    &   ⊢ (𝜑 → 𝑇 ∈ 𝐽)    &   ⊢ (𝜑 → 𝑆 ∈ Fin)    ⇒   ⊢ (𝜑 → 𝑆 ≈ 𝑇)
Theorem	exsslsb 33904*	Any finite generating set 𝑆 of a vector space 𝑊 contains a basis. (Contributed by Thierry Arnoux, 13-Oct-2025.)
⊢ 𝐵 = (Base‘𝑊)    &   ⊢ 𝐽 = (LBasis‘𝑊)    &   ⊢ 𝐾 = (LSpan‘𝑊)    &   ⊢ (𝜑 → 𝑊 ∈ LVec)    &   ⊢ (𝜑 → 𝑆 ∈ Fin)    &   ⊢ (𝜑 → 𝑆 ⊆ 𝐵)    &   ⊢ (𝜑 → (𝐾‘𝑆) = 𝐵)    ⇒   ⊢ (𝜑 → ∃𝑠 ∈ 𝐽 𝑠 ⊆ 𝑆)
Theorem	lbslelsp 33905	The size of a basis 𝑋 of a vector space 𝑊 is less than the size of a generating set 𝑌. (Contributed by Thierry Arnoux, 13-Oct-2025.)
⊢ 𝐵 = (Base‘𝑊)    &   ⊢ 𝐽 = (LBasis‘𝑊)    &   ⊢ 𝐾 = (LSpan‘𝑊)    &   ⊢ (𝜑 → 𝑊 ∈ LVec)    &   ⊢ (𝜑 → 𝑋 ∈ 𝐽)    &   ⊢ (𝜑 → 𝑌 ⊆ 𝐵)    &   ⊢ (𝜑 → (𝐾‘𝑌) = 𝐵)    ⇒   ⊢ (𝜑 → (♯‘𝑋) ≤ (♯‘𝑌))
21.3.10.54  Vector Space Dimension
Syntax	cldim 33906	Extend class notation with the dimension of a vector space.
class dim
Definition	df-dim 33907	Define the dimension of a vector space as the cardinality of its bases. Note that by lvecdim 21250, all bases are equinumerous. (Contributed by Thierry Arnoux, 6-May-2023.)
⊢ dim = (𝑓 ∈ V ↦ ∪ (♯ “ (LBasis‘𝑓)))
Theorem	dimval 33908	The dimension of a vector space 𝐹 is the cardinality of one of its bases. (Contributed by Thierry Arnoux, 6-May-2023.)
⊢ 𝐽 = (LBasis‘𝐹)    ⇒   ⊢ ((𝐹 ∈ LVec ∧ 𝑆 ∈ 𝐽) → (dim‘𝐹) = (♯‘𝑆))
Theorem	dimvalfi 33909	The dimension of a vector space 𝐹 is the cardinality of one of its bases. This version of dimval 33908 does not depend on the axiom of choice, but it is limited to the case where the base 𝑆 is finite. (Contributed by Thierry Arnoux, 24-May-2023.)
⊢ 𝐽 = (LBasis‘𝐹)    ⇒   ⊢ ((𝐹 ∈ LVec ∧ 𝑆 ∈ 𝐽 ∧ 𝑆 ∈ Fin) → (dim‘𝐹) = (♯‘𝑆))
Theorem	dimcl 33910	Closure of the vector space dimension. (Contributed by Thierry Arnoux, 18-May-2023.)
⊢ (𝑉 ∈ LVec → (dim‘𝑉) ∈ ℕ0*)
Theorem	lmimdim 33911	Module isomorphisms preserve vector space dimensions. (Contributed by Thierry Arnoux, 25-Feb-2025.)
⊢ (𝜑 → 𝐹 ∈ (𝑆 LMIso 𝑇))    &   ⊢ (𝜑 → 𝑆 ∈ LVec)    ⇒   ⊢ (𝜑 → (dim‘𝑆) = (dim‘𝑇))
Theorem	lmicdim 33912	Module isomorphisms preserve vector space dimensions. (Contributed by Thierry Arnoux, 25-Mar-2025.)
⊢ (𝜑 → 𝑆 ≃𝑚 𝑇)    &   ⊢ (𝜑 → 𝑆 ∈ LVec)    ⇒   ⊢ (𝜑 → (dim‘𝑆) = (dim‘𝑇))
Theorem	lvecdim0i 33913	A vector space of dimension zero is reduced to its identity element. (Contributed by Thierry Arnoux, 31-Jul-2023.)
⊢ 0 = (0g‘𝑉)    ⇒   ⊢ ((𝑉 ∈ LVec ∧ (dim‘𝑉) = 0) → (Base‘𝑉) = { 0 })
Theorem	lvecdim0 33914	A vector space of dimension zero is reduced to its identity element, biconditional version. (Contributed by Thierry Arnoux, 31-Jul-2023.)
⊢ 0 = (0g‘𝑉)    ⇒   ⊢ (𝑉 ∈ LVec → ((dim‘𝑉) = 0 ↔ (Base‘𝑉) = { 0 }))
Theorem	lssdimle 33915	The dimension of a linear subspace is less than or equal to the dimension of the parent vector space. This is corollary 5.4 of [Lang] p. 141. (Contributed by Thierry Arnoux, 20-May-2023.)
⊢ 𝑋 = (𝑊 ↾s 𝑈)    ⇒   ⊢ ((𝑊 ∈ LVec ∧ 𝑈 ∈ (LSubSp‘𝑊)) → (dim‘𝑋) ≤ (dim‘𝑊))
Theorem	dimpropd 33916*	If two structures have the same components (properties), they have the same dimension. (Contributed by Thierry Arnoux, 18-May-2023.)
⊢ (𝜑 → 𝐵 = (Base‘𝐾))    &   ⊢ (𝜑 → 𝐵 = (Base‘𝐿))    &   ⊢ (𝜑 → 𝐵 ⊆ 𝑊)    &   ⊢ ((𝜑 ∧ (𝑥 ∈ 𝑊 ∧ 𝑦 ∈ 𝑊)) → (𝑥(+g‘𝐾)𝑦) = (𝑥(+g‘𝐿)𝑦))    &   ⊢ ((𝜑 ∧ (𝑥 ∈ 𝑃 ∧ 𝑦 ∈ 𝐵)) → (𝑥( ·𝑠 ‘𝐾)𝑦) ∈ 𝑊)    &   ⊢ ((𝜑 ∧ (𝑥 ∈ 𝑃 ∧ 𝑦 ∈ 𝐵)) → (𝑥( ·𝑠 ‘𝐾)𝑦) = (𝑥( ·𝑠 ‘𝐿)𝑦))    &   ⊢ 𝐹 = (Scalar‘𝐾)    &   ⊢ 𝐺 = (Scalar‘𝐿)    &   ⊢ (𝜑 → 𝑃 = (Base‘𝐹))    &   ⊢ (𝜑 → 𝑃 = (Base‘𝐺))    &   ⊢ ((𝜑 ∧ (𝑥 ∈ 𝑃 ∧ 𝑦 ∈ 𝑃)) → (𝑥(+g‘𝐹)𝑦) = (𝑥(+g‘𝐺)𝑦))    &   ⊢ (𝜑 → 𝐾 ∈ LVec)    &   ⊢ (𝜑 → 𝐿 ∈ LVec)    ⇒   ⊢ (𝜑 → (dim‘𝐾) = (dim‘𝐿))
Theorem	rlmdim 33917	The left vector space induced by a ring over itself has dimension 1. (Contributed by Thierry Arnoux, 5-Aug-2023.) Generalize to division rings. (Revised by SN, 22-Mar-2025.)
⊢ 𝑉 = (ringLMod‘𝐹)    ⇒   ⊢ (𝐹 ∈ DivRing → (dim‘𝑉) = 1)
Theorem	frlmdim 33918	Dimension of a free left module. (Contributed by Thierry Arnoux, 20-May-2023.)
⊢ 𝐹 = (𝑅 freeLMod 𝐼)    ⇒   ⊢ ((𝑅 ∈ DivRing ∧ 𝐼 ∈ 𝑉) → (dim‘𝐹) = (♯‘𝐼))
Theorem	tnglvec 33919	Augmenting a structure with a norm conserves left vector spaces. (Contributed by Thierry Arnoux, 20-May-2023.)
⊢ 𝑇 = (𝐺 toNrmGrp 𝑁)    ⇒   ⊢ (𝑁 ∈ 𝑉 → (𝐺 ∈ LVec ↔ 𝑇 ∈ LVec))
Theorem	tngdim 33920	Dimension of a left vector space augmented with a norm. (Contributed by Thierry Arnoux, 20-May-2023.)
⊢ 𝑇 = (𝐺 toNrmGrp 𝑁)    ⇒   ⊢ ((𝐺 ∈ LVec ∧ 𝑁 ∈ 𝑉) → (dim‘𝐺) = (dim‘𝑇))
Theorem	rrxdim 33921	Dimension of the generalized Euclidean space. (Contributed by Thierry Arnoux, 20-May-2023.)
⊢ 𝐻 = (ℝ^‘𝐼)    ⇒   ⊢ (𝐼 ∈ 𝑉 → (dim‘𝐻) = (♯‘𝐼))
Theorem	matdim 33922	Dimension of the space of square matrices. (Contributed by Thierry Arnoux, 20-May-2023.)
⊢ 𝐴 = (𝐼 Mat 𝑅)    &   ⊢ 𝑁 = (♯‘𝐼)    ⇒   ⊢ ((𝐼 ∈ Fin ∧ 𝑅 ∈ DivRing) → (dim‘𝐴) = (𝑁 · 𝑁))
Theorem	lbslsat 33923	A nonzero vector 𝑋 is a basis of a line spanned by the singleton 𝑋. Spans of nonzero singletons are sometimes called "atoms", see df-lsatoms 39612 and for example lsatlspsn 39629. (Contributed by Thierry Arnoux, 20-May-2023.)
⊢ 𝑉 = (Base‘𝑊)    &   ⊢ 𝑁 = (LSpan‘𝑊)    &   ⊢ 0 = (0g‘𝑊)    &   ⊢ 𝑌 = (𝑊 ↾s (𝑁‘{𝑋}))    ⇒   ⊢ ((𝑊 ∈ LVec ∧ 𝑋 ∈ 𝑉 ∧ 𝑋 ≠ 0 ) → {𝑋} ∈ (LBasis‘𝑌))
Theorem	lsatdim 33924	A line, spanned by a nonzero singleton, has dimension 1. (Contributed by Thierry Arnoux, 20-May-2023.)
⊢ 𝑉 = (Base‘𝑊)    &   ⊢ 𝑁 = (LSpan‘𝑊)    &   ⊢ 0 = (0g‘𝑊)    &   ⊢ 𝑌 = (𝑊 ↾s (𝑁‘{𝑋}))    ⇒   ⊢ ((𝑊 ∈ LVec ∧ 𝑋 ∈ 𝑉 ∧ 𝑋 ≠ 0 ) → (dim‘𝑌) = 1)
Theorem	drngdimgt0 33925	The dimension of a vector space that is also a division ring is greater than zero. (Contributed by Thierry Arnoux, 29-Jul-2023.)
⊢ ((𝐹 ∈ LVec ∧ 𝐹 ∈ DivRing) → 0 < (dim‘𝐹))
Theorem	lmhmlvec2 33926	A homomorphism of left vector spaces has a left vector space as codomain. (Contributed by Thierry Arnoux, 7-May-2023.)
⊢ ((𝑉 ∈ LVec ∧ 𝐹 ∈ (𝑉 LMHom 𝑈)) → 𝑈 ∈ LVec)
Theorem	kerlmhm 33927	The kernel of a vector space homomorphism is a vector space itself. (Contributed by Thierry Arnoux, 7-May-2023.)
⊢ 0 = (0g‘𝑈)    &   ⊢ 𝐾 = (𝑉 ↾s (◡𝐹 “ { 0 }))    ⇒   ⊢ ((𝑉 ∈ LVec ∧ 𝐹 ∈ (𝑉 LMHom 𝑈)) → 𝐾 ∈ LVec)
Theorem	imlmhm 33928	The image of a vector space homomorphism is a vector space itself. (Contributed by Thierry Arnoux, 7-May-2023.)
⊢ 𝐼 = (𝑈 ↾s ran 𝐹)    ⇒   ⊢ ((𝑉 ∈ LVec ∧ 𝐹 ∈ (𝑉 LMHom 𝑈)) → 𝐼 ∈ LVec)
Theorem	ply1degltdimlem 33929*	Lemma for ply1degltdim 33930. (Contributed by Thierry Arnoux, 20-Feb-2025.)
⊢ 𝑃 = (Poly1‘𝑅)    &   ⊢ 𝐷 = (deg1‘𝑅)    &   ⊢ 𝑆 = (◡𝐷 “ (-∞[,)𝑁))    &   ⊢ (𝜑 → 𝑁 ∈ ℕ0)    &   ⊢ (𝜑 → 𝑅 ∈ DivRing)    &   ⊢ 𝐸 = (𝑃 ↾s 𝑆)    &   ⊢ 𝐹 = (𝑛 ∈ (0..^𝑁) ↦ (𝑛(.g‘(mulGrp‘𝑃))(var1‘𝑅)))    ⇒   ⊢ (𝜑 → ran 𝐹 ∈ (LBasis‘𝐸))
Theorem	ply1degltdim 33930	The space 𝑆 of the univariate polynomials of degree less than 𝑁 has dimension 𝑁. (Contributed by Thierry Arnoux, 20-Feb-2025.)
⊢ 𝑃 = (Poly1‘𝑅)    &   ⊢ 𝐷 = (deg1‘𝑅)    &   ⊢ 𝑆 = (◡𝐷 “ (-∞[,)𝑁))    &   ⊢ (𝜑 → 𝑁 ∈ ℕ0)    &   ⊢ (𝜑 → 𝑅 ∈ DivRing)    &   ⊢ 𝐸 = (𝑃 ↾s 𝑆)    ⇒   ⊢ (𝜑 → (dim‘𝐸) = 𝑁)
Theorem	lindsunlem 33931	Lemma for lindsun 33932. (Contributed by Thierry Arnoux, 9-May-2023.)
⊢ 𝑁 = (LSpan‘𝑊)    &   ⊢ 0 = (0g‘𝑊)    &   ⊢ (𝜑 → 𝑊 ∈ LVec)    &   ⊢ (𝜑 → 𝑈 ∈ (LIndS‘𝑊))    &   ⊢ (𝜑 → 𝑉 ∈ (LIndS‘𝑊))    &   ⊢ (𝜑 → ((𝑁‘𝑈) ∩ (𝑁‘𝑉)) = { 0 })    &   ⊢ 𝑂 = (0g‘(Scalar‘𝑊))    &   ⊢ 𝐹 = (Base‘(Scalar‘𝑊))    &   ⊢ (𝜑 → 𝐶 ∈ 𝑈)    &   ⊢ (𝜑 → 𝐾 ∈ (𝐹 ∖ {𝑂}))    &   ⊢ (𝜑 → (𝐾( ·𝑠 ‘𝑊)𝐶) ∈ (𝑁‘((𝑈 ∪ 𝑉) ∖ {𝐶})))    ⇒   ⊢ (𝜑 → ⊥)
Theorem	lindsun 33932	Condition for the union of two independent sets to be an independent set. (Contributed by Thierry Arnoux, 9-May-2023.)
⊢ 𝑁 = (LSpan‘𝑊)    &   ⊢ 0 = (0g‘𝑊)    &   ⊢ (𝜑 → 𝑊 ∈ LVec)    &   ⊢ (𝜑 → 𝑈 ∈ (LIndS‘𝑊))    &   ⊢ (𝜑 → 𝑉 ∈ (LIndS‘𝑊))    &   ⊢ (𝜑 → ((𝑁‘𝑈) ∩ (𝑁‘𝑉)) = { 0 })    ⇒   ⊢ (𝜑 → (𝑈 ∪ 𝑉) ∈ (LIndS‘𝑊))
Theorem	lbsdiflsp0 33933	The linear spans of two disjunct independent sets only have a trivial intersection. This can be seen as the opposite direction of lindsun 33932. (Contributed by Thierry Arnoux, 17-May-2023.)
⊢ 𝐽 = (LBasis‘𝑊)    &   ⊢ 𝑁 = (LSpan‘𝑊)    &   ⊢ 0 = (0g‘𝑊)    ⇒   ⊢ ((𝑊 ∈ LVec ∧ 𝐵 ∈ 𝐽 ∧ 𝑉 ⊆ 𝐵) → ((𝑁‘(𝐵 ∖ 𝑉)) ∩ (𝑁‘𝑉)) = { 0 })
Theorem	dimkerim 33934	Given a linear map 𝐹 between vector spaces 𝑉 and 𝑈, the dimension of the vector space 𝑉 is the sum of the dimension of 𝐹 's kernel and the dimension of 𝐹's image. Second part of theorem 5.3 in [Lang] p. 141 This can also be described as the Rank-nullity theorem, (dim‘𝐼) being the rank of 𝐹 (the dimension of its image), and (dim‘𝐾) its nullity (the dimension of its kernel). (Contributed by Thierry Arnoux, 17-May-2023.)
⊢ 0 = (0g‘𝑈)    &   ⊢ 𝐾 = (𝑉 ↾s (◡𝐹 “ { 0 }))    &   ⊢ 𝐼 = (𝑈 ↾s ran 𝐹)    ⇒   ⊢ ((𝑉 ∈ LVec ∧ 𝐹 ∈ (𝑉 LMHom 𝑈)) → (dim‘𝑉) = ((dim‘𝐾) +𝑒 (dim‘𝐼)))
Theorem	qusdimsum 33935	Let 𝑊 be a vector space, and let 𝑋 be a subspace. Then the dimension of 𝑊 is the sum of the dimension of 𝑋 and the dimension of the quotient space of 𝑋. First part of theorem 5.3 in [Lang] p. 141. (Contributed by Thierry Arnoux, 20-May-2023.)
⊢ 𝑋 = (𝑊 ↾s 𝑈)    &   ⊢ 𝑌 = (𝑊 /s (𝑊 ~QG 𝑈))    ⇒   ⊢ ((𝑊 ∈ LVec ∧ 𝑈 ∈ (LSubSp‘𝑊)) → (dim‘𝑊) = ((dim‘𝑋) +𝑒 (dim‘𝑌)))
Theorem	fedgmullem1 33936*	Lemma for fedgmul 33938. (Contributed by Thierry Arnoux, 20-Jul-2023.)
⊢ 𝐴 = ((subringAlg ‘𝐸)‘𝑉)    &   ⊢ 𝐵 = ((subringAlg ‘𝐸)‘𝑈)    &   ⊢ 𝐶 = ((subringAlg ‘𝐹)‘𝑉)    &   ⊢ 𝐹 = (𝐸 ↾s 𝑈)    &   ⊢ 𝐾 = (𝐸 ↾s 𝑉)    &   ⊢ (𝜑 → 𝐸 ∈ DivRing)    &   ⊢ (𝜑 → 𝐹 ∈ DivRing)    &   ⊢ (𝜑 → 𝐾 ∈ DivRing)    &   ⊢ (𝜑 → 𝑈 ∈ (SubRing‘𝐸))    &   ⊢ (𝜑 → 𝑉 ∈ (SubRing‘𝐹))    &   ⊢ 𝐷 = (𝑗 ∈ 𝑌, 𝑖 ∈ 𝑋 ↦ (𝑖(.r‘𝐸)𝑗))    &   ⊢ 𝐻 = (𝑗 ∈ 𝑌, 𝑖 ∈ 𝑋 ↦ ((𝐺‘𝑗)‘𝑖))    &   ⊢ (𝜑 → 𝑋 ∈ (LBasis‘𝐶))    &   ⊢ (𝜑 → 𝑌 ∈ (LBasis‘𝐵))    &   ⊢ (𝜑 → 𝑍 ∈ (Base‘𝐴))    &   ⊢ (𝜑 → 𝐿:𝑌⟶(Base‘(Scalar‘𝐵)))    &   ⊢ (𝜑 → 𝐿 finSupp (0g‘(Scalar‘𝐵)))    &   ⊢ (𝜑 → 𝑍 = (𝐵 Σg (𝑗 ∈ 𝑌 ↦ ((𝐿‘𝑗)( ·𝑠 ‘𝐵)𝑗))))    &   ⊢ (𝜑 → 𝐺:𝑌⟶((Base‘(Scalar‘𝐶)) ↑m 𝑋))    &   ⊢ ((𝜑 ∧ 𝑗 ∈ 𝑌) → (𝐺‘𝑗) finSupp (0g‘(Scalar‘𝐶)))    &   ⊢ ((𝜑 ∧ 𝑗 ∈ 𝑌) → (𝐿‘𝑗) = (𝐶 Σg (𝑖 ∈ 𝑋 ↦ (((𝐺‘𝑗)‘𝑖)( ·𝑠 ‘𝐶)𝑖))))    ⇒   ⊢ (𝜑 → (𝐻 finSupp (0g‘(Scalar‘𝐴)) ∧ 𝑍 = (𝐴 Σg (𝐻 ∘f ( ·𝑠 ‘𝐴)𝐷))))
Theorem	fedgmullem2 33937*	Lemma for fedgmul 33938. (Contributed by Thierry Arnoux, 20-Jul-2023.)
⊢ 𝐴 = ((subringAlg ‘𝐸)‘𝑉)    &   ⊢ 𝐵 = ((subringAlg ‘𝐸)‘𝑈)    &   ⊢ 𝐶 = ((subringAlg ‘𝐹)‘𝑉)    &   ⊢ 𝐹 = (𝐸 ↾s 𝑈)    &   ⊢ 𝐾 = (𝐸 ↾s 𝑉)    &   ⊢ (𝜑 → 𝐸 ∈ DivRing)    &   ⊢ (𝜑 → 𝐹 ∈ DivRing)    &   ⊢ (𝜑 → 𝐾 ∈ DivRing)    &   ⊢ (𝜑 → 𝑈 ∈ (SubRing‘𝐸))    &   ⊢ (𝜑 → 𝑉 ∈ (SubRing‘𝐹))    &   ⊢ 𝐷 = (𝑗 ∈ 𝑌, 𝑖 ∈ 𝑋 ↦ (𝑖(.r‘𝐸)𝑗))    &   ⊢ 𝐻 = (𝑗 ∈ 𝑌, 𝑖 ∈ 𝑋 ↦ ((𝐺‘𝑗)‘𝑖))    &   ⊢ (𝜑 → 𝑋 ∈ (LBasis‘𝐶))    &   ⊢ (𝜑 → 𝑌 ∈ (LBasis‘𝐵))    &   ⊢ (𝜑 → 𝑊 ∈ (Base‘((Scalar‘𝐴) freeLMod (𝑌 × 𝑋))))    &   ⊢ (𝜑 → (𝐴 Σg (𝑊 ∘f ( ·𝑠 ‘𝐴)𝐷)) = (0g‘𝐴))    ⇒   ⊢ (𝜑 → 𝑊 = ((𝑌 × 𝑋) × {(0g‘(Scalar‘𝐴))}))
Theorem	fedgmul 33938	The multiplicativity formula for degrees of field extensions. Given 𝐸 a field extension of 𝐹, itself a field extension of 𝐾, we have [𝐸:𝐾] = [𝐸:𝐹][𝐹:𝐾]. Proposition 1.2 of [Lang], p. 224. Here (dim‘𝐴) is the degree of the extension 𝐸 of 𝐾, (dim‘𝐵) is the degree of the extension 𝐸 of 𝐹, and (dim‘𝐶) is the degree of the extension 𝐹 of 𝐾. This proof is valid for infinite dimensions, and is actually valid for division ring extensions, not just field extensions. (Contributed by Thierry Arnoux, 25-Jul-2023.)
⊢ 𝐴 = ((subringAlg ‘𝐸)‘𝑉)    &   ⊢ 𝐵 = ((subringAlg ‘𝐸)‘𝑈)    &   ⊢ 𝐶 = ((subringAlg ‘𝐹)‘𝑉)    &   ⊢ 𝐹 = (𝐸 ↾s 𝑈)    &   ⊢ 𝐾 = (𝐸 ↾s 𝑉)    &   ⊢ (𝜑 → 𝐸 ∈ DivRing)    &   ⊢ (𝜑 → 𝐹 ∈ DivRing)    &   ⊢ (𝜑 → 𝐾 ∈ DivRing)    &   ⊢ (𝜑 → 𝑈 ∈ (SubRing‘𝐸))    &   ⊢ (𝜑 → 𝑉 ∈ (SubRing‘𝐹))    ⇒   ⊢ (𝜑 → (dim‘𝐴) = ((dim‘𝐵) ·e (dim‘𝐶)))
Theorem	dimlssid 33939	If the dimension of a linear subspace 𝐿 is the dimension of the whole vector space 𝐸, then 𝐿 is the whole space. (Contributed by Thierry Arnoux, 3-Aug-2025.)
⊢ 𝐵 = (Base‘𝐸)    &   ⊢ (𝜑 → 𝐸 ∈ LVec)    &   ⊢ (𝜑 → (dim‘𝐸) ∈ ℕ0)    &   ⊢ (𝜑 → 𝐿 ∈ (LSubSp‘𝐸))    &   ⊢ (𝜑 → (dim‘(𝐸 ↾s 𝐿)) = (dim‘𝐸))    ⇒   ⊢ (𝜑 → 𝐿 = 𝐵)
Theorem	lvecendof1f1o 33940	If an endomorphism 𝑈 of a vector space 𝐸 of finite dimension is injective, then it is bijective. Item (b) of Corollary of Proposition 9 in [BourbakiAlg1] p. 298 . (Contributed by Thierry Arnoux, 3-Aug-2025.)
⊢ 𝐵 = (Base‘𝐸)    &   ⊢ (𝜑 → 𝐸 ∈ LVec)    &   ⊢ (𝜑 → (dim‘𝐸) ∈ ℕ0)    &   ⊢ (𝜑 → 𝑈 ∈ (𝐸 LMHom 𝐸))    &   ⊢ (𝜑 → 𝑈:𝐵–1-1→𝐵)    ⇒   ⊢ (𝜑 → 𝑈:𝐵–1-1-onto→𝐵)
Theorem	lactlmhm 33941*	In an associative algebra 𝐴, left-multiplication by a fixed element of the algebra is a module homomorphism, analogous to ringlghm 20386. (Contributed by Thierry Arnoux, 3-Aug-2025.)
⊢ 𝐵 = (Base‘𝐴)    &   ⊢ · = (.r‘𝐴)    &   ⊢ 𝐹 = (𝑥 ∈ 𝐵 ↦ (𝐶 · 𝑥))    &   ⊢ (𝜑 → 𝐴 ∈ AssAlg)    &   ⊢ (𝜑 → 𝐶 ∈ 𝐵)    ⇒   ⊢ (𝜑 → 𝐹 ∈ (𝐴 LMHom 𝐴))
Theorem	assalactf1o 33942*	In an associative algebra 𝐴, left-multiplication by a fixed element of the algebra is bijective. See also lactlmhm 33941. (Contributed by Thierry Arnoux, 3-Aug-2025.)
⊢ 𝐵 = (Base‘𝐴)    &   ⊢ · = (.r‘𝐴)    &   ⊢ 𝐹 = (𝑥 ∈ 𝐵 ↦ (𝐶 · 𝑥))    &   ⊢ (𝜑 → 𝐴 ∈ AssAlg)    &   ⊢ 𝐸 = (RLReg‘𝐴)    &   ⊢ 𝐾 = (Scalar‘𝐴)    &   ⊢ (𝜑 → 𝐾 ∈ DivRing)    &   ⊢ (𝜑 → (dim‘𝐴) ∈ ℕ0)    &   ⊢ (𝜑 → 𝐶 ∈ 𝐸)    ⇒   ⊢ (𝜑 → 𝐹:𝐵–1-1-onto→𝐵)
Theorem	assarrginv 33943	If an element 𝑋 of an associative algebra 𝐴 over a division ring 𝐾 is regular, then it is a unit. Proposition 2. in Chapter 5. of [BourbakiAlg2] p. 113. (Contributed by Thierry Arnoux, 3-Aug-2025.)
⊢ 𝐸 = (RLReg‘𝐴)    &   ⊢ 𝑈 = (Unit‘𝐴)    &   ⊢ 𝐾 = (Scalar‘𝐴)    &   ⊢ (𝜑 → 𝐴 ∈ AssAlg)    &   ⊢ (𝜑 → 𝐾 ∈ DivRing)    &   ⊢ (𝜑 → (dim‘𝐴) ∈ ℕ0)    &   ⊢ (𝜑 → 𝑋 ∈ 𝐸)    ⇒   ⊢ (𝜑 → 𝑋 ∈ 𝑈)
Theorem	assafld 33944	If an algebra 𝐴 of finite degree over a division ring 𝐾 is an integral domain, then it is a field. Corollary of Proposition 2. in Chapter 5. of [BourbakiAlg2] p. 113. (Contributed by Thierry Arnoux, 3-Aug-2025.)
⊢ 𝐾 = (Scalar‘𝐴)    &   ⊢ (𝜑 → 𝐴 ∈ AssAlg)    &   ⊢ (𝜑 → 𝐴 ∈ IDomn)    &   ⊢ (𝜑 → 𝐾 ∈ DivRing)    &   ⊢ (𝜑 → (dim‘𝐴) ∈ ℕ0)    ⇒   ⊢ (𝜑 → 𝐴 ∈ Field)
21.3.11  Field Extensions
Syntax	cfldext 33945	Syntax for the field extension relation.
class /FldExt
Syntax	cfinext 33946	Syntax for the finite field extension relation.
class /FinExt
Syntax	cextdg 33947	Syntax for the field extension degree operation.
class [:]
Definition	df-fldext 33948*	Definition of the field extension relation. (Contributed by Thierry Arnoux, 29-Jul-2023.)
⊢ /FldExt = {⟨𝑒, 𝑓⟩ ∣ ((𝑒 ∈ Field ∧ 𝑓 ∈ Field) ∧ (𝑓 = (𝑒 ↾s (Base‘𝑓)) ∧ (Base‘𝑓) ∈ (SubRing‘𝑒)))}
Definition	df-extdg 33949*	Definition of the field extension degree operation. (Contributed by Thierry Arnoux, 29-Jul-2023.)
⊢ [:] = (𝑒 ∈ V, 𝑓 ∈ (/FldExt “ {𝑒}) ↦ (dim‘((subringAlg ‘𝑒)‘(Base‘𝑓))))
Definition	df-finext 33950*	Definition of the finite field extension relation. (Contributed by Thierry Arnoux, 29-Jul-2023.)
⊢ /FinExt = {⟨𝑒, 𝑓⟩ ∣ (𝑒/FldExt𝑓 ∧ (𝑒[:]𝑓) ∈ ℕ0)}
Theorem	relfldext 33951	The field extension is a relation. (Contributed by Thierry Arnoux, 29-Jul-2023.)
⊢ Rel /FldExt
Theorem	brfldext 33952	The field extension relation explicited. (Contributed by Thierry Arnoux, 29-Jul-2023.)
⊢ ((𝐸 ∈ Field ∧ 𝐹 ∈ Field) → (𝐸/FldExt𝐹 ↔ (𝐹 = (𝐸 ↾s (Base‘𝐹)) ∧ (Base‘𝐹) ∈ (SubRing‘𝐸))))
Theorem	ccfldextrr 33953	The field of the complex numbers is an extension of the field of the real numbers. (Contributed by Thierry Arnoux, 20-Jul-2023.)
⊢ ℂfld/FldExtℝfld
Theorem	fldextfld1 33954	A field extension is only defined if the extension is a field. (Contributed by Thierry Arnoux, 29-Jul-2023.)
⊢ (𝐸/FldExt𝐹 → 𝐸 ∈ Field)
Theorem	fldextfld2 33955	A field extension is only defined if the subfield is a field. (Contributed by Thierry Arnoux, 29-Jul-2023.)
⊢ (𝐸/FldExt𝐹 → 𝐹 ∈ Field)
Theorem	fldextsubrg 33956	Field extension implies a subring relation. (Contributed by Thierry Arnoux, 29-Jul-2023.)
⊢ 𝑈 = (Base‘𝐹)    ⇒   ⊢ (𝐸/FldExt𝐹 → 𝑈 ∈ (SubRing‘𝐸))
Theorem	sdrgfldext 33957	A field 𝐸 and any sub-division-ring 𝐹 of 𝐸 form a field extension. (Contributed by Thierry Arnoux, 26-Oct-2025.)
⊢ 𝐵 = (Base‘𝐸)    &   ⊢ (𝜑 → 𝐸 ∈ Field)    &   ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐸))    ⇒   ⊢ (𝜑 → 𝐸/FldExt(𝐸 ↾s 𝐹))
Theorem	fldextress 33958	Field extension implies a structure restriction relation. (Contributed by Thierry Arnoux, 29-Jul-2023.)
⊢ (𝐸/FldExt𝐹 → 𝐹 = (𝐸 ↾s (Base‘𝐹)))
Theorem	brfinext 33959	The finite field extension relation explicited. (Contributed by Thierry Arnoux, 29-Jul-2023.)
⊢ (𝐸/FldExt𝐹 → (𝐸/FinExt𝐹 ↔ (𝐸[:]𝐹) ∈ ℕ0))
Theorem	extdgval 33960	Value of the field extension degree operation. (Contributed by Thierry Arnoux, 29-Jul-2023.)
⊢ (𝐸/FldExt𝐹 → (𝐸[:]𝐹) = (dim‘((subringAlg ‘𝐸)‘(Base‘𝐹))))
Theorem	fldextsdrg 33961	Deduce sub-division-ring from field extension. (Contributed by Thierry Arnoux, 26-Oct-2025.)
⊢ 𝐵 = (Base‘𝐹)    &   ⊢ (𝜑 → 𝐸/FldExt𝐹)    ⇒   ⊢ (𝜑 → 𝐵 ∈ (SubDRing‘𝐸))
Theorem	fldextsralvec 33962	The subring algebra associated with a field extension is a vector space. (Contributed by Thierry Arnoux, 3-Aug-2023.)
⊢ (𝐸/FldExt𝐹 → ((subringAlg ‘𝐸)‘(Base‘𝐹)) ∈ LVec)
Theorem	extdgcl 33963	Closure of the field extension degree operation. (Contributed by Thierry Arnoux, 29-Jul-2023.)
⊢ (𝐸/FldExt𝐹 → (𝐸[:]𝐹) ∈ ℕ0*)
Theorem	extdggt0 33964	Degrees of field extension are greater than zero. (Contributed by Thierry Arnoux, 30-Jul-2023.)
⊢ (𝐸/FldExt𝐹 → 0 < (𝐸[:]𝐹))
Theorem	fldexttr 33965	Field extension is a transitive relation. (Contributed by Thierry Arnoux, 29-Jul-2023.)
⊢ ((𝐸/FldExt𝐹 ∧ 𝐹/FldExt𝐾) → 𝐸/FldExt𝐾)
Theorem	fldextid 33966	The field extension relation is reflexive. (Contributed by Thierry Arnoux, 30-Jul-2023.)
⊢ (𝐹 ∈ Field → 𝐹/FldExt𝐹)
Theorem	extdgid 33967	A trivial field extension has degree one. (Contributed by Thierry Arnoux, 4-Aug-2023.)
⊢ (𝐸 ∈ Field → (𝐸[:]𝐸) = 1)
Theorem	fldsdrgfldext 33968	A sub-division-ring of a field forms a field extension. (Contributed by Thierry Arnoux, 19-Oct-2025.)
⊢ 𝐺 = (𝐹 ↾s 𝐴)    &   ⊢ (𝜑 → 𝐹 ∈ Field)    &   ⊢ (𝜑 → 𝐴 ∈ (SubDRing‘𝐹))    ⇒   ⊢ (𝜑 → 𝐹/FldExt𝐺)
Theorem	fldsdrgfldext2 33969	A sub-sub-division-ring of a field forms a field extension. (Contributed by Thierry Arnoux, 19-Oct-2025.)
⊢ 𝐺 = (𝐹 ↾s 𝐴)    &   ⊢ (𝜑 → 𝐹 ∈ Field)    &   ⊢ (𝜑 → 𝐴 ∈ (SubDRing‘𝐹))    &   ⊢ (𝜑 → 𝐵 ∈ (SubDRing‘𝐺))    &   ⊢ 𝐻 = (𝐹 ↾s 𝐵)    ⇒   ⊢ (𝜑 → 𝐺/FldExt𝐻)
Theorem	extdgmul 33970	The multiplicativity formula for degrees of field extensions. Given 𝐸 a field extension of 𝐹, itself a field extension of 𝐾, the degree of the extension 𝐸/FldExt𝐾 is the product of the degrees of the extensions 𝐸/FldExt𝐹 and 𝐹/FldExt𝐾. Proposition 1.2 of [Lang], p. 224. (Contributed by Thierry Arnoux, 30-Jul-2023.)
⊢ ((𝐸/FldExt𝐹 ∧ 𝐹/FldExt𝐾) → (𝐸[:]𝐾) = ((𝐸[:]𝐹) ·e (𝐹[:]𝐾)))
Theorem	finextfldext 33971	A finite field extension is a field extension. (Contributed by Thierry Arnoux, 10-Jan-2026.)
⊢ (𝜑 → 𝐸/FinExt𝐹)    ⇒   ⊢ (𝜑 → 𝐸/FldExt𝐹)
Theorem	finexttrb 33972	The extension 𝐸 of 𝐾 is finite if and only if 𝐸 is finite over 𝐹 and 𝐹 is finite over 𝐾. Corollary 1.3 of [Lang] , p. 225. (Contributed by Thierry Arnoux, 30-Jul-2023.)
⊢ ((𝐸/FldExt𝐹 ∧ 𝐹/FldExt𝐾) → (𝐸/FinExt𝐾 ↔ (𝐸/FinExt𝐹 ∧ 𝐹/FinExt𝐾)))
Theorem	extdg1id 33973	If the degree of the extension 𝐸/FldExt𝐹 is 1, then 𝐸 and 𝐹 are identical. (Contributed by Thierry Arnoux, 6-Aug-2023.)
⊢ ((𝐸/FldExt𝐹 ∧ (𝐸[:]𝐹) = 1) → 𝐸 = 𝐹)
Theorem	extdg1b 33974	The degree of the extension 𝐸/FldExt𝐹 is 1 iff 𝐸 and 𝐹 are the same structure. (Contributed by Thierry Arnoux, 6-Aug-2023.)
⊢ (𝐸/FldExt𝐹 → ((𝐸[:]𝐹) = 1 ↔ 𝐸 = 𝐹))
Theorem	fldgenfldext 33975	A subfield 𝐹 extended with a set 𝐴 forms a field extension. (Contributed by Thierry Arnoux, 22-Jun-2025.)
⊢ 𝐵 = (Base‘𝐸)    &   ⊢ 𝐾 = (𝐸 ↾s 𝐹)    &   ⊢ 𝐿 = (𝐸 ↾s (𝐸 fldGen (𝐹 ∪ 𝐴)))    &   ⊢ (𝜑 → 𝐸 ∈ Field)    &   ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐸))    &   ⊢ (𝜑 → 𝐴 ⊆ 𝐵)    ⇒   ⊢ (𝜑 → 𝐿/FldExt𝐾)
Theorem	fldextchr 33976	The characteristic of a subfield is the same as the characteristic of the larger field. (Contributed by Thierry Arnoux, 20-Aug-2023.)
⊢ (𝐸/FldExt𝐹 → (chr‘𝐹) = (chr‘𝐸))
Theorem	evls1fldgencl 33977	Closure of the subring polynomial evaluation in the field extention. (Contributed by Thierry Arnoux, 2-Apr-2025.)
⊢ 𝐵 = (Base‘𝐸)    &   ⊢ 𝑂 = (𝐸 evalSub1 𝐹)    &   ⊢ 𝑃 = (Poly1‘(𝐸 ↾s 𝐹))    &   ⊢ 𝑈 = (Base‘𝑃)    &   ⊢ (𝜑 → 𝐸 ∈ Field)    &   ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐸))    &   ⊢ (𝜑 → 𝐴 ∈ 𝐵)    &   ⊢ (𝜑 → 𝐺 ∈ 𝑈)    ⇒   ⊢ (𝜑 → ((𝑂‘𝐺)‘𝐴) ∈ (𝐸 fldGen (𝐹 ∪ {𝐴})))
Theorem	ccfldsrarelvec 33978	The subring algebra of the complex numbers over the real numbers is a left vector space. (Contributed by Thierry Arnoux, 20-Aug-2023.)
⊢ ((subringAlg ‘ℂfld)‘ℝ) ∈ LVec
Theorem	ccfldextdgrr 33979	The degree of the field extension of the complex numbers over the real numbers is 2. (Suggested by GL, 4-Aug-2023.) (Contributed by Thierry Arnoux, 20-Aug-2023.)
⊢ (ℂfld[:]ℝfld) = 2
Theorem	fldextrspunlsplem 33980*	Lemma for fldextrspunlsp 33981: First direction. Part of the proof of Proposition 5, Chapter 5, of [BourbakiAlg2] p. 116. (Contributed by Thierry Arnoux, 13-Oct-2025.)
⊢ 𝐾 = (𝐿 ↾s 𝐹)    &   ⊢ 𝐼 = (𝐿 ↾s 𝐺)    &   ⊢ 𝐽 = (𝐿 ↾s 𝐻)    &   ⊢ (𝜑 → 𝐿 ∈ Field)    &   ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐼))    &   ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐽))    &   ⊢ (𝜑 → 𝐺 ∈ (SubDRing‘𝐿))    &   ⊢ (𝜑 → 𝐻 ∈ (SubDRing‘𝐿))    &   ⊢ 𝑁 = (RingSpan‘𝐿)    &   ⊢ 𝐶 = (𝑁‘(𝐺 ∪ 𝐻))    &   ⊢ 𝐸 = (𝐿 ↾s 𝐶)    &   ⊢ (𝜑 → 𝐵 ∈ (LBasis‘((subringAlg ‘𝐽)‘𝐹)))    &   ⊢ (𝜑 → 𝐵 ∈ Fin)    &   ⊢ (𝜑 → 𝑃:𝐻⟶𝐺)    &   ⊢ (𝜑 → 𝑃 finSupp (0g‘𝐿))    &   ⊢ (𝜑 → 𝑋 = (𝐿 Σg (𝑓 ∈ 𝐻 ↦ ((𝑃‘𝑓)(.r‘𝐿)𝑓))))    ⇒   ⊢ (𝜑 → ∃𝑎 ∈ (𝐺 ↑m 𝐵)(𝑎 finSupp (0g‘𝐿) ∧ 𝑋 = (𝐿 Σg (𝑏 ∈ 𝐵 ↦ ((𝑎‘𝑏)(.r‘𝐿)𝑏)))))
Theorem	fldextrspunlsp 33981	Lemma for fldextrspunfld 33983. The subring generated by the union of two field extensions 𝐺 and 𝐻 is the vector sub- 𝐺 space generated by a basis 𝐵 of 𝐻. Part of the proof of Proposition 5, Chapter 5, of [BourbakiAlg2] p. 116. (Contributed by Thierry Arnoux, 13-Oct-2025.)
⊢ 𝐾 = (𝐿 ↾s 𝐹)    &   ⊢ 𝐼 = (𝐿 ↾s 𝐺)    &   ⊢ 𝐽 = (𝐿 ↾s 𝐻)    &   ⊢ (𝜑 → 𝐿 ∈ Field)    &   ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐼))    &   ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐽))    &   ⊢ (𝜑 → 𝐺 ∈ (SubDRing‘𝐿))    &   ⊢ (𝜑 → 𝐻 ∈ (SubDRing‘𝐿))    &   ⊢ 𝑁 = (RingSpan‘𝐿)    &   ⊢ 𝐶 = (𝑁‘(𝐺 ∪ 𝐻))    &   ⊢ 𝐸 = (𝐿 ↾s 𝐶)    &   ⊢ (𝜑 → 𝐵 ∈ (LBasis‘((subringAlg ‘𝐽)‘𝐹)))    &   ⊢ (𝜑 → 𝐵 ∈ Fin)    ⇒   ⊢ (𝜑 → 𝐶 = ((LSpan‘((subringAlg ‘𝐿)‘𝐺))‘𝐵))
Theorem	fldextrspunlem1 33982	Lemma for fldextrspunfld 33983. Part of the proof of Proposition 5, Chapter 5, of [BourbakiAlg2] p. 116. (Contributed by Thierry Arnoux, 13-Oct-2025.)
⊢ 𝐾 = (𝐿 ↾s 𝐹)    &   ⊢ 𝐼 = (𝐿 ↾s 𝐺)    &   ⊢ 𝐽 = (𝐿 ↾s 𝐻)    &   ⊢ (𝜑 → 𝐿 ∈ Field)    &   ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐼))    &   ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐽))    &   ⊢ (𝜑 → 𝐺 ∈ (SubDRing‘𝐿))    &   ⊢ (𝜑 → 𝐻 ∈ (SubDRing‘𝐿))    &   ⊢ (𝜑 → (𝐽[:]𝐾) ∈ ℕ0)    &   ⊢ 𝑁 = (RingSpan‘𝐿)    &   ⊢ 𝐶 = (𝑁‘(𝐺 ∪ 𝐻))    &   ⊢ 𝐸 = (𝐿 ↾s 𝐶)    ⇒   ⊢ (𝜑 → (dim‘((subringAlg ‘𝐸)‘𝐺)) ≤ (𝐽[:]𝐾))
Theorem	fldextrspunfld 33983	The ring generated by the union of two field extensions is a field. Part of the proof of Proposition 5, Chapter 5, of [BourbakiAlg2] p. 116. (Contributed by Thierry Arnoux, 13-Oct-2025.)
⊢ 𝐾 = (𝐿 ↾s 𝐹)    &   ⊢ 𝐼 = (𝐿 ↾s 𝐺)    &   ⊢ 𝐽 = (𝐿 ↾s 𝐻)    &   ⊢ (𝜑 → 𝐿 ∈ Field)    &   ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐼))    &   ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐽))    &   ⊢ (𝜑 → 𝐺 ∈ (SubDRing‘𝐿))    &   ⊢ (𝜑 → 𝐻 ∈ (SubDRing‘𝐿))    &   ⊢ (𝜑 → (𝐽[:]𝐾) ∈ ℕ0)    &   ⊢ 𝑁 = (RingSpan‘𝐿)    &   ⊢ 𝐶 = (𝑁‘(𝐺 ∪ 𝐻))    &   ⊢ 𝐸 = (𝐿 ↾s 𝐶)    ⇒   ⊢ (𝜑 → 𝐸 ∈ Field)
Theorem	fldextrspunlem2 33984	Part of the proof of Proposition 5, Chapter 5, of [BourbakiAlg2] p. 116. (Contributed by Thierry Arnoux, 13-Oct-2025.)
⊢ 𝐾 = (𝐿 ↾s 𝐹)    &   ⊢ 𝐼 = (𝐿 ↾s 𝐺)    &   ⊢ 𝐽 = (𝐿 ↾s 𝐻)    &   ⊢ (𝜑 → 𝐿 ∈ Field)    &   ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐼))    &   ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐽))    &   ⊢ (𝜑 → 𝐺 ∈ (SubDRing‘𝐿))    &   ⊢ (𝜑 → 𝐻 ∈ (SubDRing‘𝐿))    &   ⊢ (𝜑 → (𝐽[:]𝐾) ∈ ℕ0)    &   ⊢ 𝑁 = (RingSpan‘𝐿)    &   ⊢ 𝐶 = (𝑁‘(𝐺 ∪ 𝐻))    &   ⊢ 𝐸 = (𝐿 ↾s 𝐶)    ⇒   ⊢ (𝜑 → 𝐶 = (𝐿 fldGen (𝐺 ∪ 𝐻)))
Theorem	fldextrspundgle 33985	Inequality involving the degree of two different field extensions 𝐼 and 𝐽 of a same field 𝐹. Part of the proof of Proposition 5, Chapter 5, of [BourbakiAlg2] p. 116. (Contributed by Thierry Arnoux, 13-Oct-2025.)
⊢ 𝐾 = (𝐿 ↾s 𝐹)    &   ⊢ 𝐼 = (𝐿 ↾s 𝐺)    &   ⊢ 𝐽 = (𝐿 ↾s 𝐻)    &   ⊢ (𝜑 → 𝐿 ∈ Field)    &   ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐼))    &   ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐽))    &   ⊢ (𝜑 → 𝐺 ∈ (SubDRing‘𝐿))    &   ⊢ (𝜑 → 𝐻 ∈ (SubDRing‘𝐿))    &   ⊢ (𝜑 → (𝐽[:]𝐾) ∈ ℕ0)    &   ⊢ 𝐸 = (𝐿 ↾s (𝐿 fldGen (𝐺 ∪ 𝐻)))    ⇒   ⊢ (𝜑 → (𝐸[:]𝐼) ≤ (𝐽[:]𝐾))
Theorem	fldextrspundglemul 33986	Given two field extensions 𝐼 / 𝐾 and 𝐽 / 𝐾 of the same field 𝐾, 𝐽 / 𝐾 being finite, and the composiste field 𝐸 = 𝐼𝐽, the degree of the extension of the composite field 𝐸 / 𝐾 is at most the product of the field extension degrees of 𝐼 / 𝐾 and 𝐽 / 𝐾. (Contributed by Thierry Arnoux, 19-Oct-2025.)
⊢ 𝐾 = (𝐿 ↾s 𝐹)    &   ⊢ 𝐼 = (𝐿 ↾s 𝐺)    &   ⊢ 𝐽 = (𝐿 ↾s 𝐻)    &   ⊢ (𝜑 → 𝐿 ∈ Field)    &   ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐼))    &   ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐽))    &   ⊢ (𝜑 → 𝐺 ∈ (SubDRing‘𝐿))    &   ⊢ (𝜑 → 𝐻 ∈ (SubDRing‘𝐿))    &   ⊢ (𝜑 → (𝐽[:]𝐾) ∈ ℕ0)    &   ⊢ 𝐸 = (𝐿 ↾s (𝐿 fldGen (𝐺 ∪ 𝐻)))    ⇒   ⊢ (𝜑 → (𝐸[:]𝐾) ≤ ((𝐼[:]𝐾) ·e (𝐽[:]𝐾)))
Theorem	fldextrspundgdvdslem 33987	Lemma for fldextrspundgdvds 33988. (Contributed by Thierry Arnoux, 19-Oct-2025.)
⊢ 𝐾 = (𝐿 ↾s 𝐹)    &   ⊢ 𝐼 = (𝐿 ↾s 𝐺)    &   ⊢ 𝐽 = (𝐿 ↾s 𝐻)    &   ⊢ (𝜑 → 𝐿 ∈ Field)    &   ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐼))    &   ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐽))    &   ⊢ (𝜑 → 𝐺 ∈ (SubDRing‘𝐿))    &   ⊢ (𝜑 → 𝐻 ∈ (SubDRing‘𝐿))    &   ⊢ (𝜑 → (𝐽[:]𝐾) ∈ ℕ0)    &   ⊢ 𝐸 = (𝐿 ↾s (𝐿 fldGen (𝐺 ∪ 𝐻)))    &   ⊢ (𝜑 → (𝐼[:]𝐾) ∈ ℕ)    ⇒   ⊢ (𝜑 → (𝐸[:]𝐼) ∈ ℕ0)
Theorem	fldextrspundgdvds 33988	Given two finite extensions 𝐼 / 𝐾 and 𝐽 / 𝐾 of the same field 𝐾, the degree of the extension 𝐼 / 𝐾 divides the degree of the extension 𝐸 / 𝐾, 𝐸 being the composite field 𝐼𝐽. (Contributed by Thierry Arnoux, 19-Oct-2025.)
⊢ 𝐾 = (𝐿 ↾s 𝐹)    &   ⊢ 𝐼 = (𝐿 ↾s 𝐺)    &   ⊢ 𝐽 = (𝐿 ↾s 𝐻)    &   ⊢ (𝜑 → 𝐿 ∈ Field)    &   ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐼))    &   ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐽))    &   ⊢ (𝜑 → 𝐺 ∈ (SubDRing‘𝐿))    &   ⊢ (𝜑 → 𝐻 ∈ (SubDRing‘𝐿))    &   ⊢ (𝜑 → (𝐽[:]𝐾) ∈ ℕ0)    &   ⊢ 𝐸 = (𝐿 ↾s (𝐿 fldGen (𝐺 ∪ 𝐻)))    &   ⊢ (𝜑 → (𝐼[:]𝐾) ∈ ℕ)    ⇒   ⊢ (𝜑 → (𝐼[:]𝐾) ∥ (𝐸[:]𝐾))
Theorem	fldext2rspun 33989*	Given two field extensions 𝐼 / 𝐾 and 𝐽 / 𝐾, 𝐼 / 𝐾 being a quadratic extension, and the degree of 𝐽 / 𝐾 being a power of 2, the degree of the extension 𝐸 / 𝐾 is a power of 2 , 𝐸 being the composite field 𝐼𝐽. (Contributed by Thierry Arnoux, 19-Oct-2025.)
⊢ 𝐾 = (𝐿 ↾s 𝐹)    &   ⊢ 𝐼 = (𝐿 ↾s 𝐺)    &   ⊢ 𝐽 = (𝐿 ↾s 𝐻)    &   ⊢ (𝜑 → 𝐿 ∈ Field)    &   ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐼))    &   ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐽))    &   ⊢ (𝜑 → 𝐺 ∈ (SubDRing‘𝐿))    &   ⊢ (𝜑 → 𝐻 ∈ (SubDRing‘𝐿))    &   ⊢ (𝜑 → 𝑁 ∈ ℕ0)    &   ⊢ (𝜑 → (𝐼[:]𝐾) = 2)    &   ⊢ (𝜑 → (𝐽[:]𝐾) = (2↑𝑁))    &   ⊢ 𝐸 = (𝐿 ↾s (𝐿 fldGen (𝐺 ∪ 𝐻)))    ⇒   ⊢ (𝜑 → ∃𝑛 ∈ ℕ0 (𝐸[:]𝐾) = (2↑𝑛))
21.3.11.1  Algebraic numbers
Syntax	cirng 33990	Integral subring of a ring.
class IntgRing
Definition	df-irng 33991*	Define the subring of elements of a ring 𝑟 integral over a subset 𝑠. (Contributed by Mario Carneiro, 2-Dec-2014.) (Revised by Thierry Arnoux, 28-Jan-2025.)
⊢ IntgRing = (𝑟 ∈ V, 𝑠 ∈ V ↦ ∪ 𝑓 ∈ (Monic1p‘(𝑟 ↾s 𝑠))(◡((𝑟 evalSub1 𝑠)‘𝑓) “ {(0g‘𝑟)}))
Theorem	irngval 33992*	The elements of a field 𝑅 integral over a subset 𝑆. In the case of a subfield, those are the algebraic numbers over the field 𝑆 within the field 𝑅. That is, the numbers 𝑋 which are roots of monic polynomials 𝑃(𝑋) with coefficients in 𝑆. (Contributed by Thierry Arnoux, 28-Jan-2025.)
⊢ 𝑂 = (𝑅 evalSub1 𝑆)    &   ⊢ 𝑈 = (𝑅 ↾s 𝑆)    &   ⊢ 𝐵 = (Base‘𝑅)    &   ⊢ 0 = (0g‘𝑅)    &   ⊢ (𝜑 → 𝑅 ∈ Ring)    &   ⊢ (𝜑 → 𝑆 ⊆ 𝐵)    ⇒   ⊢ (𝜑 → (𝑅 IntgRing 𝑆) = ∪ 𝑓 ∈ (Monic1p‘𝑈)(◡(𝑂‘𝑓) “ { 0 }))
Theorem	elirng 33993*	Property for an element 𝑋 of a field 𝑅 to be integral over a subring 𝑆. (Contributed by Thierry Arnoux, 28-Jan-2025.)
⊢ 𝑂 = (𝑅 evalSub1 𝑆)    &   ⊢ 𝑈 = (𝑅 ↾s 𝑆)    &   ⊢ 𝐵 = (Base‘𝑅)    &   ⊢ 0 = (0g‘𝑅)    &   ⊢ (𝜑 → 𝑅 ∈ CRing)    &   ⊢ (𝜑 → 𝑆 ∈ (SubRing‘𝑅))    ⇒   ⊢ (𝜑 → (𝑋 ∈ (𝑅 IntgRing 𝑆) ↔ (𝑋 ∈ 𝐵 ∧ ∃𝑓 ∈ (Monic1p‘𝑈)((𝑂‘𝑓)‘𝑋) = 0 )))
Theorem	irngss 33994	All elements of a subring 𝑆 are integral over 𝑆. This is only true in the case of a nonzero ring, since there are no integral elements in a zero ring (see 0ringirng 33996). (Contributed by Thierry Arnoux, 28-Jan-2025.)
⊢ 𝑂 = (𝑅 evalSub1 𝑆)    &   ⊢ 𝑈 = (𝑅 ↾s 𝑆)    &   ⊢ 𝐵 = (Base‘𝑅)    &   ⊢ 0 = (0g‘𝑅)    &   ⊢ (𝜑 → 𝑅 ∈ CRing)    &   ⊢ (𝜑 → 𝑆 ∈ (SubRing‘𝑅))    &   ⊢ (𝜑 → 𝑅 ∈ NzRing)    ⇒   ⊢ (𝜑 → 𝑆 ⊆ (𝑅 IntgRing 𝑆))
Theorem	irngssv 33995	An integral element is an element of the base set. (Contributed by Thierry Arnoux, 28-Jan-2025.)
⊢ 𝑂 = (𝑅 evalSub1 𝑆)    &   ⊢ 𝑈 = (𝑅 ↾s 𝑆)    &   ⊢ 𝐵 = (Base‘𝑅)    &   ⊢ 0 = (0g‘𝑅)    &   ⊢ (𝜑 → 𝑅 ∈ CRing)    &   ⊢ (𝜑 → 𝑆 ∈ (SubRing‘𝑅))    ⇒   ⊢ (𝜑 → (𝑅 IntgRing 𝑆) ⊆ 𝐵)
Theorem	0ringirng 33996	A zero ring 𝑅 has no integral elements. (Contributed by Thierry Arnoux, 5-Feb-2025.)
⊢ 𝑂 = (𝑅 evalSub1 𝑆)    &   ⊢ 𝑈 = (𝑅 ↾s 𝑆)    &   ⊢ 𝐵 = (Base‘𝑅)    &   ⊢ 0 = (0g‘𝑅)    &   ⊢ (𝜑 → 𝑅 ∈ CRing)    &   ⊢ (𝜑 → 𝑆 ∈ (SubRing‘𝑅))    &   ⊢ (𝜑 → ¬ 𝑅 ∈ NzRing)    ⇒   ⊢ (𝜑 → (𝑅 IntgRing 𝑆) = ∅)
Theorem	irngnzply1lem 33997	In the case of a field 𝐸, a root 𝑋 of some nonzero polynomial 𝑃 with coefficients in a subfield 𝐹 is integral over 𝐹. (Contributed by Thierry Arnoux, 5-Feb-2025.)
⊢ 𝑂 = (𝐸 evalSub1 𝐹)    &   ⊢ 𝑍 = (0g‘(Poly1‘𝐸))    &   ⊢ 0 = (0g‘𝐸)    &   ⊢ (𝜑 → 𝐸 ∈ Field)    &   ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐸))    &   ⊢ 𝐵 = (Base‘𝐸)    &   ⊢ (𝜑 → 𝑃 ∈ dom 𝑂)    &   ⊢ (𝜑 → 𝑃 ≠ 𝑍)    &   ⊢ (𝜑 → ((𝑂‘𝑃)‘𝑋) = 0 )    &   ⊢ (𝜑 → 𝑋 ∈ 𝐵)    ⇒   ⊢ (𝜑 → 𝑋 ∈ (𝐸 IntgRing 𝐹))
Theorem	irngnzply1 33998*	In the case of a field 𝐸, the roots of nonzero polynomials 𝑝 with coefficients in a subfield 𝐹 are exactly the integral elements over 𝐹. Roots of nonzero polynomials are called algebraic numbers, so this shows that in the case of a field, elements integral over 𝐹 are exactly the algebraic numbers. In this formula, dom 𝑂 represents the polynomials, and 𝑍 the zero polynomial. (Contributed by Thierry Arnoux, 5-Feb-2025.)
⊢ 𝑂 = (𝐸 evalSub1 𝐹)    &   ⊢ 𝑍 = (0g‘(Poly1‘𝐸))    &   ⊢ 0 = (0g‘𝐸)    &   ⊢ (𝜑 → 𝐸 ∈ Field)    &   ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐸))    ⇒   ⊢ (𝜑 → (𝐸 IntgRing 𝐹) = ∪ 𝑝 ∈ (dom 𝑂 ∖ {𝑍})(◡(𝑂‘𝑝) “ { 0 }))
Theorem	extdgfialglem1 33999*	Lemma for extdgfialg 34001. (Contributed by Thierry Arnoux, 10-Jan-2026.)
⊢ 𝐵 = (Base‘𝐸)    &   ⊢ 𝐷 = (dim‘((subringAlg ‘𝐸)‘𝐹))    &   ⊢ (𝜑 → 𝐸 ∈ Field)    &   ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐸))    &   ⊢ (𝜑 → 𝐷 ∈ ℕ0)    &   ⊢ 𝑍 = (0g‘𝐸)    &   ⊢ · = (.r‘𝐸)    &   ⊢ 𝐺 = (𝑛 ∈ (0...𝐷) ↦ (𝑛(.g‘(mulGrp‘((subringAlg ‘𝐸)‘𝐹)))𝑋))    &   ⊢ (𝜑 → 𝑋 ∈ 𝐵)    ⇒   ⊢ (𝜑 → ∃𝑎 ∈ (𝐹 ↑m (0...𝐷))(𝑎 finSupp 𝑍 ∧ ((𝐸 Σg (𝑎 ∘f · 𝐺)) = 𝑍 ∧ 𝑎 ≠ ((0...𝐷) × {𝑍}))))
Theorem	extdgfialglem2 34000*	Lemma for extdgfialg 34001. (Contributed by Thierry Arnoux, 10-Jan-2026.)
⊢ 𝐵 = (Base‘𝐸)    &   ⊢ 𝐷 = (dim‘((subringAlg ‘𝐸)‘𝐹))    &   ⊢ (𝜑 → 𝐸 ∈ Field)    &   ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐸))    &   ⊢ (𝜑 → 𝐷 ∈ ℕ0)    &   ⊢ 𝑍 = (0g‘𝐸)    &   ⊢ · = (.r‘𝐸)    &   ⊢ 𝐺 = (𝑛 ∈ (0...𝐷) ↦ (𝑛(.g‘(mulGrp‘((subringAlg ‘𝐸)‘𝐹)))𝑋))    &   ⊢ (𝜑 → 𝑋 ∈ 𝐵)    &   ⊢ (𝜑 → 𝐴:(0...𝐷)⟶𝐹)    &   ⊢ (𝜑 → 𝐴 finSupp 𝑍)    &   ⊢ (𝜑 → (𝐸 Σg (𝐴 ∘f · 𝐺)) = 𝑍)    &   ⊢ (𝜑 → 𝐴 ≠ ((0...𝐷) × {𝑍}))    ⇒   ⊢ (𝜑 → 𝑋 ∈ (𝐸 IntgRing 𝐹))