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| Type | Label | Description |
|---|---|---|
| Statement | ||
| Theorem | elrelscnveq3 39001* | Two ways of saying a relation is symmetric. (Contributed by Peter Mazsa, 22-Aug-2021.) |
| ⊢ (𝑅 ∈ Rels → (𝑅 = ◡𝑅 ↔ ∀𝑥∀𝑦(𝑥𝑅𝑦 → 𝑦𝑅𝑥))) | ||
| Theorem | elrelscnveq 39002 | Two ways of saying a relation is symmetric. (Contributed by Peter Mazsa, 22-Aug-2021.) |
| ⊢ (𝑅 ∈ Rels → (◡𝑅 ⊆ 𝑅 ↔ ◡𝑅 = 𝑅)) | ||
| Theorem | elrelscnveq2 39003* | Two ways of saying a relation is symmetric. (Contributed by Peter Mazsa, 22-Aug-2021.) |
| ⊢ (𝑅 ∈ Rels → (◡𝑅 = 𝑅 ↔ ∀𝑥∀𝑦(𝑥𝑅𝑦 ↔ 𝑦𝑅𝑥))) | ||
| Theorem | elrelscnveq4 39004* | Two ways of saying a relation is symmetric. (Contributed by Peter Mazsa, 22-Aug-2021.) |
| ⊢ (𝑅 ∈ Rels → (◡𝑅 ⊆ 𝑅 ↔ ∀𝑥∀𝑦(𝑥𝑅𝑦 ↔ 𝑦𝑅𝑥))) | ||
| Theorem | dfsymrels4 39005 | Alternate definition of the class of symmetric relations. (Contributed by Peter Mazsa, 20-Jul-2019.) |
| ⊢ SymRels = {𝑟 ∈ Rels ∣ ◡𝑟 = 𝑟} | ||
| Theorem | dfsymrels5 39006* | Alternate definition of the class of symmetric relations. (Contributed by Peter Mazsa, 22-Jul-2021.) |
| ⊢ SymRels = {𝑟 ∈ Rels ∣ ∀𝑥∀𝑦(𝑥𝑟𝑦 ↔ 𝑦𝑟𝑥)} | ||
| Theorem | dfsymrel2 39007 | Alternate definition of the symmetric relation predicate. (Contributed by Peter Mazsa, 19-Apr-2019.) (Revised by Peter Mazsa, 17-Aug-2021.) |
| ⊢ ( SymRel 𝑅 ↔ (◡𝑅 ⊆ 𝑅 ∧ Rel 𝑅)) | ||
| Theorem | dfsymrel3 39008* | Alternate definition of the symmetric relation predicate. (Contributed by Peter Mazsa, 21-Apr-2019.) (Revised by Peter Mazsa, 17-Aug-2021.) |
| ⊢ ( SymRel 𝑅 ↔ (∀𝑥∀𝑦(𝑥𝑅𝑦 → 𝑦𝑅𝑥) ∧ Rel 𝑅)) | ||
| Theorem | dfsymrel4 39009 | Alternate definition of the symmetric relation predicate. (Contributed by Peter Mazsa, 17-Aug-2021.) |
| ⊢ ( SymRel 𝑅 ↔ (◡𝑅 = 𝑅 ∧ Rel 𝑅)) | ||
| Theorem | dfsymrel5 39010* | Alternate definition of the symmetric relation predicate. (Contributed by Peter Mazsa, 17-Aug-2021.) |
| ⊢ ( SymRel 𝑅 ↔ (∀𝑥∀𝑦(𝑥𝑅𝑦 ↔ 𝑦𝑅𝑥) ∧ Rel 𝑅)) | ||
| Theorem | elsymrels2 39011 | Element of the class of symmetric relations. (Contributed by Peter Mazsa, 17-Aug-2021.) |
| ⊢ (𝑅 ∈ SymRels ↔ (◡𝑅 ⊆ 𝑅 ∧ 𝑅 ∈ Rels )) | ||
| Theorem | elsymrels3 39012* | Element of the class of symmetric relations. (Contributed by Peter Mazsa, 17-Aug-2021.) |
| ⊢ (𝑅 ∈ SymRels ↔ (∀𝑥∀𝑦(𝑥𝑅𝑦 → 𝑦𝑅𝑥) ∧ 𝑅 ∈ Rels )) | ||
| Theorem | elsymrels4 39013 | Element of the class of symmetric relations. (Contributed by Peter Mazsa, 17-Aug-2021.) |
| ⊢ (𝑅 ∈ SymRels ↔ (◡𝑅 = 𝑅 ∧ 𝑅 ∈ Rels )) | ||
| Theorem | elsymrels5 39014* | Element of the class of symmetric relations. (Contributed by Peter Mazsa, 17-Aug-2021.) |
| ⊢ (𝑅 ∈ SymRels ↔ (∀𝑥∀𝑦(𝑥𝑅𝑦 ↔ 𝑦𝑅𝑥) ∧ 𝑅 ∈ Rels )) | ||
| Theorem | elsymrelsrel 39015 | For sets, being an element of the class of symmetric relations (df-symrels 38997) is equivalent to satisfying the symmetric relation predicate. (Contributed by Peter Mazsa, 17-Aug-2021.) |
| ⊢ (𝑅 ∈ 𝑉 → (𝑅 ∈ SymRels ↔ SymRel 𝑅)) | ||
| Theorem | symreleq 39016 | Equality theorem for symmetric relation. (Contributed by Peter Mazsa, 15-Apr-2019.) (Revised by Peter Mazsa, 23-Sep-2021.) |
| ⊢ (𝑅 = 𝑆 → ( SymRel 𝑅 ↔ SymRel 𝑆)) | ||
| Theorem | symrelim 39017 | Symmetric relation implies that the domain and the range are equal. (Contributed by Peter Mazsa, 29-Dec-2021.) |
| ⊢ ( SymRel 𝑅 → dom 𝑅 = ran 𝑅) | ||
| Theorem | symrelcoss 39018 | The class of cosets by 𝑅 is symmetric. (Contributed by Peter Mazsa, 20-Dec-2021.) |
| ⊢ SymRel ≀ 𝑅 | ||
| Theorem | idsymrel 39019 | The identity relation is symmetric. (Contributed by AV, 19-Jun-2022.) |
| ⊢ SymRel I | ||
| Theorem | epnsymrel 39020 | The membership (epsilon) relation is not symmetric. (Contributed by AV, 18-Jun-2022.) |
| ⊢ ¬ SymRel E | ||
| Theorem | symrefref2 39021 | Symmetry is a sufficient condition for the equivalence of two versions of the reflexive relation, see also symrefref3 39022. (Contributed by Peter Mazsa, 19-Jul-2018.) |
| ⊢ (◡𝑅 ⊆ 𝑅 → (( I ∩ (dom 𝑅 × ran 𝑅)) ⊆ 𝑅 ↔ ( I ↾ dom 𝑅) ⊆ 𝑅)) | ||
| Theorem | symrefref3 39022* | Symmetry is a sufficient condition for the equivalence of two versions of the reflexive relation, see also symrefref2 39021. (Contributed by Peter Mazsa, 23-Aug-2021.) (Proof modification is discouraged.) |
| ⊢ (∀𝑥∀𝑦(𝑥𝑅𝑦 → 𝑦𝑅𝑥) → (∀𝑥 ∈ dom 𝑅∀𝑦 ∈ ran 𝑅(𝑥 = 𝑦 → 𝑥𝑅𝑦) ↔ ∀𝑥 ∈ dom 𝑅 𝑥𝑅𝑥)) | ||
| Theorem | refsymrels2 39023 | Elements of the class of reflexive relations which are elements of the class of symmetric relations as well (like the elements of the class of equivalence relations dfeqvrels2 39046) can use the restricted version for their reflexive part (see below), not just the ( I ∩ (dom 𝑟 × ran 𝑟)) ⊆ 𝑟 version of dfrefrels2 38967, cf. the comment of dfrefrels2 38967. (Contributed by Peter Mazsa, 20-Jul-2019.) |
| ⊢ ( RefRels ∩ SymRels ) = {𝑟 ∈ Rels ∣ (( I ↾ dom 𝑟) ⊆ 𝑟 ∧ ◡𝑟 ⊆ 𝑟)} | ||
| Theorem | refsymrels3 39024* | Elements of the class of reflexive relations which are elements of the class of symmetric relations as well (like the elements of the class of equivalence relations dfeqvrels3 39047) can use the ∀𝑥 ∈ dom 𝑟𝑥𝑟𝑥 version for their reflexive part, not just the ∀𝑥 ∈ dom 𝑟∀𝑦 ∈ ran 𝑟(𝑥 = 𝑦 → 𝑥𝑟𝑦) version of dfrefrels3 38968, cf. the comment of dfrefrel3 38970. (Contributed by Peter Mazsa, 22-Jul-2019.) (Proof modification is discouraged.) |
| ⊢ ( RefRels ∩ SymRels ) = {𝑟 ∈ Rels ∣ (∀𝑥 ∈ dom 𝑟 𝑥𝑟𝑥 ∧ ∀𝑥∀𝑦(𝑥𝑟𝑦 → 𝑦𝑟𝑥))} | ||
| Theorem | refsymrel2 39025 | A relation which is reflexive and symmetric (like an equivalence relation) can use the restricted version for their reflexive part (see below), not just the ( I ∩ (dom 𝑅 × ran 𝑅)) ⊆ 𝑅 version of dfrefrel2 38969, cf. the comment of dfrefrels2 38967. (Contributed by Peter Mazsa, 23-Aug-2021.) |
| ⊢ (( RefRel 𝑅 ∧ SymRel 𝑅) ↔ ((( I ↾ dom 𝑅) ⊆ 𝑅 ∧ ◡𝑅 ⊆ 𝑅) ∧ Rel 𝑅)) | ||
| Theorem | refsymrel3 39026* | A relation which is reflexive and symmetric (like an equivalence relation) can use the ∀𝑥 ∈ dom 𝑅𝑥𝑅𝑥 version for its reflexive part, not just the ∀𝑥 ∈ dom 𝑅∀𝑦 ∈ ran 𝑅(𝑥 = 𝑦 → 𝑥𝑅𝑦) version of dfrefrel3 38970, cf. the comment of dfrefrel3 38970. (Contributed by Peter Mazsa, 23-Aug-2021.) |
| ⊢ (( RefRel 𝑅 ∧ SymRel 𝑅) ↔ ((∀𝑥 ∈ dom 𝑅 𝑥𝑅𝑥 ∧ ∀𝑥∀𝑦(𝑥𝑅𝑦 → 𝑦𝑅𝑥)) ∧ Rel 𝑅)) | ||
| Theorem | elrefsymrels2 39027 | Elements of the class of reflexive relations which are elements of the class of symmetric relations as well (like the elements of the class of equivalence relations dfeqvrels2 39046) can use the restricted version for their reflexive part (see below), not just the ( I ∩ (dom 𝑅 × ran 𝑅)) ⊆ 𝑅 version of dfrefrels2 38967, cf. the comment of dfrefrels2 38967. (Contributed by Peter Mazsa, 22-Jul-2019.) |
| ⊢ (𝑅 ∈ ( RefRels ∩ SymRels ) ↔ ((( I ↾ dom 𝑅) ⊆ 𝑅 ∧ ◡𝑅 ⊆ 𝑅) ∧ 𝑅 ∈ Rels )) | ||
| Theorem | elrefsymrels3 39028* | Elements of the class of reflexive relations which are elements of the class of symmetric relations as well (like the elements of the class of equivalence relations dfeqvrels3 39047) can use the ∀𝑥 ∈ dom 𝑅𝑥𝑅𝑥 version for their reflexive part, not just the ∀𝑥 ∈ dom 𝑅∀𝑦 ∈ ran 𝑅(𝑥 = 𝑦 → 𝑥𝑅𝑦) version of dfrefrels3 38968, cf. the comment of dfrefrel3 38970. (Contributed by Peter Mazsa, 22-Jul-2019.) (Proof modification is discouraged.) |
| ⊢ (𝑅 ∈ ( RefRels ∩ SymRels ) ↔ ((∀𝑥 ∈ dom 𝑅 𝑥𝑅𝑥 ∧ ∀𝑥∀𝑦(𝑥𝑅𝑦 → 𝑦𝑅𝑥)) ∧ 𝑅 ∈ Rels )) | ||
| Theorem | elrefsymrelsrel 39029 | For sets, being an element of the class of reflexive and symmetric relations is equivalent to satisfying the reflexive and symmetric relation predicates. (Contributed by Peter Mazsa, 23-Aug-2021.) |
| ⊢ (𝑅 ∈ 𝑉 → (𝑅 ∈ ( RefRels ∩ SymRels ) ↔ ( RefRel 𝑅 ∧ SymRel 𝑅))) | ||
| Definition | df-trs 39030 |
Define the class of all transitive sets (versus the transitive class
defined in df-tr 5187). It is used only by df-trrels 39031.
Note the similarity of the definitions of df-refs 38964, df-syms 38996 and df-trs 39030. (Contributed by Peter Mazsa, 17-Jul-2021.) |
| ⊢ Trs = {𝑥 ∣ ((𝑥 ∩ (dom 𝑥 × ran 𝑥)) ∘ (𝑥 ∩ (dom 𝑥 × ran 𝑥))) S (𝑥 ∩ (dom 𝑥 × ran 𝑥))} | ||
| Definition | df-trrels 39031 |
Define the class of transitive relations. For sets, being an element of
the class of transitive relations is equivalent to satisfying the
transitive relation predicate, see eltrrelsrel 39039. Alternate definitions
are dftrrels2 39033 and dftrrels3 39034.
This definition is similar to the definitions of the classes of reflexive (df-refrels 38965) and symmetric (df-symrels 38997) relations. (Contributed by Peter Mazsa, 7-Jul-2019.) |
| ⊢ TrRels = ( Trs ∩ Rels ) | ||
| Definition | df-trrel 39032 | Define the transitive relation predicate. (Read: 𝑅 is a transitive relation.) For sets, being an element of the class of transitive relations (df-trrels 39031) is equivalent to satisfying the transitive relation predicate, see eltrrelsrel 39039. Alternate definitions are dftrrel2 39035 and dftrrel3 39036. (Contributed by Peter Mazsa, 17-Jul-2021.) |
| ⊢ ( TrRel 𝑅 ↔ (((𝑅 ∩ (dom 𝑅 × ran 𝑅)) ∘ (𝑅 ∩ (dom 𝑅 × ran 𝑅))) ⊆ (𝑅 ∩ (dom 𝑅 × ran 𝑅)) ∧ Rel 𝑅)) | ||
| Theorem | dftrrels2 39033 |
Alternate definition of the class of transitive relations.
I'd prefer to define the class of transitive relations by using the definition of composition by [Suppes] p. 63. df-coSUP (𝐴 ∘ 𝐵) = {〈𝑥, 𝑦〉 ∣ ∃𝑢(𝑥𝐴𝑢 ∧ 𝑢𝐵𝑦)} as opposed to the present definition of composition df-co 5634 (𝐴 ∘ 𝐵) = {〈𝑥, 𝑦〉 ∣ ∃𝑢(𝑥𝐵𝑢 ∧ 𝑢𝐴𝑦)} because the Suppes definition keeps the order of 𝐴, 𝐵, 𝐶, 𝑅, 𝑆, 𝑇 by default in trsinxpSUP (((𝑅 ∩ (𝐴 × 𝐵)) ∘ (𝑆 ∩ (𝐵 × 𝐶))) ⊆ (𝑇 ∩ (𝐴 × 𝐶)) ↔ ∀𝑥 ∈ 𝐴∀𝑦 ∈ 𝐵∀ 𝑧 ∈ 𝐶((𝑥𝑅𝑦 ∧ 𝑦𝑆𝑧) → 𝑥𝑇𝑧)) while the present definition of composition disarranges them: trsinxp (((𝑆 ∩ (𝐵 × 𝐶)) ∘ (𝑅 ∩ (𝐴 × 𝐵))) ⊆ (𝑇 ∩ (𝐴 × 𝐶 )) ↔ ∀𝑥 ∈ 𝐴∀𝑦 ∈ 𝐵∀𝑧 ∈ 𝐶((𝑥𝑅𝑦 ∧ 𝑦𝑆𝑧) → 𝑥𝑇𝑧) ). This is not mission critical to me, the implication of the Suppes definition is just more aesthetic, at least in the above case. If we swap to the Suppes definition of class composition, I would define the present class of all transitive sets as df-trsSUP and I would consider to switch the definition of the class of cosets by 𝑅 from the present df-coss 38875 to a df-cossSUP. But perhaps there is a mathematical reason to keep the present definition of composition. (Contributed by Peter Mazsa, 21-Jul-2021.) |
| ⊢ TrRels = {𝑟 ∈ Rels ∣ (𝑟 ∘ 𝑟) ⊆ 𝑟} | ||
| Theorem | dftrrels3 39034* | Alternate definition of the class of transitive relations. (Contributed by Peter Mazsa, 22-Jul-2021.) |
| ⊢ TrRels = {𝑟 ∈ Rels ∣ ∀𝑥∀𝑦∀𝑧((𝑥𝑟𝑦 ∧ 𝑦𝑟𝑧) → 𝑥𝑟𝑧)} | ||
| Theorem | dftrrel2 39035 | Alternate definition of the transitive relation predicate. (Contributed by Peter Mazsa, 22-Aug-2021.) |
| ⊢ ( TrRel 𝑅 ↔ ((𝑅 ∘ 𝑅) ⊆ 𝑅 ∧ Rel 𝑅)) | ||
| Theorem | dftrrel3 39036* | Alternate definition of the transitive relation predicate. (Contributed by Peter Mazsa, 22-Aug-2021.) |
| ⊢ ( TrRel 𝑅 ↔ (∀𝑥∀𝑦∀𝑧((𝑥𝑅𝑦 ∧ 𝑦𝑅𝑧) → 𝑥𝑅𝑧) ∧ Rel 𝑅)) | ||
| Theorem | eltrrels2 39037 | Element of the class of transitive relations. (Contributed by Peter Mazsa, 22-Aug-2021.) |
| ⊢ (𝑅 ∈ TrRels ↔ ((𝑅 ∘ 𝑅) ⊆ 𝑅 ∧ 𝑅 ∈ Rels )) | ||
| Theorem | eltrrels3 39038* | Element of the class of transitive relations. (Contributed by Peter Mazsa, 22-Aug-2021.) |
| ⊢ (𝑅 ∈ TrRels ↔ (∀𝑥∀𝑦∀𝑧((𝑥𝑅𝑦 ∧ 𝑦𝑅𝑧) → 𝑥𝑅𝑧) ∧ 𝑅 ∈ Rels )) | ||
| Theorem | eltrrelsrel 39039 | For sets, being an element of the class of transitive relations is equivalent to satisfying the transitive relation predicate. (Contributed by Peter Mazsa, 22-Aug-2021.) |
| ⊢ (𝑅 ∈ 𝑉 → (𝑅 ∈ TrRels ↔ TrRel 𝑅)) | ||
| Theorem | trreleq 39040 | Equality theorem for the transitive relation predicate. (Contributed by Peter Mazsa, 15-Apr-2019.) (Revised by Peter Mazsa, 23-Sep-2021.) |
| ⊢ (𝑅 = 𝑆 → ( TrRel 𝑅 ↔ TrRel 𝑆)) | ||
| Theorem | trrelressn 39041 | Any class ' R ' restricted to the singleton of the class ' A ' (see ressn2 38906) is transitive. (Contributed by Peter Mazsa, 17-Jun-2024.) |
| ⊢ TrRel (𝑅 ↾ {𝐴}) | ||
| Definition | df-eqvrels 39042 | Define the class of equivalence relations. For sets, being an element of the class of equivalence relations is equivalent to satisfying the equivalence relation predicate, see eleqvrelsrel 39052. Alternate definitions are dfeqvrels2 39046 and dfeqvrels3 39047. (Contributed by Peter Mazsa, 7-Nov-2018.) |
| ⊢ EqvRels = (( RefRels ∩ SymRels ) ∩ TrRels ) | ||
| Definition | df-eqvrel 39043 | Define the equivalence relation predicate. (Read: 𝑅 is an equivalence relation.) For sets, being an element of the class of equivalence relations (df-eqvrels 39042) is equivalent to satisfying the equivalence relation predicate, see eleqvrelsrel 39052. Alternate definitions are dfeqvrel2 39048 and dfeqvrel3 39049. (Contributed by Peter Mazsa, 17-Apr-2019.) |
| ⊢ ( EqvRel 𝑅 ↔ ( RefRel 𝑅 ∧ SymRel 𝑅 ∧ TrRel 𝑅)) | ||
| Definition | df-coeleqvrels 39044 | Define the coelement equivalence relations class, the class of sets with coelement equivalence relations. For sets, being an element of the class of coelement equivalence relations is equivalent to satisfying the coelement equivalence relation predicate, see elcoeleqvrelsrel 39054. Alternate definition is dfcoeleqvrels 39079. (Contributed by Peter Mazsa, 28-Nov-2022.) |
| ⊢ CoElEqvRels = {𝑎 ∣ ≀ (◡ E ↾ 𝑎) ∈ EqvRels } | ||
| Definition | df-coeleqvrel 39045 | Define the coelement equivalence relation predicate. (Read: the coelement equivalence relation on 𝐴.) Alternate definition is dfcoeleqvrel 39080. For sets, being an element of the class of coelement equivalence relations is equivalent to satisfying the coelement equivalence relation predicate, see elcoeleqvrelsrel 39054. (Contributed by Peter Mazsa, 11-Dec-2021.) |
| ⊢ ( CoElEqvRel 𝐴 ↔ EqvRel ≀ (◡ E ↾ 𝐴)) | ||
| Theorem | dfeqvrels2 39046 | Alternate definition of the class of equivalence relations. (Contributed by Peter Mazsa, 2-Dec-2019.) |
| ⊢ EqvRels = {𝑟 ∈ Rels ∣ (( I ↾ dom 𝑟) ⊆ 𝑟 ∧ ◡𝑟 ⊆ 𝑟 ∧ (𝑟 ∘ 𝑟) ⊆ 𝑟)} | ||
| Theorem | dfeqvrels3 39047* | Alternate definition of the class of equivalence relations. (Contributed by Peter Mazsa, 2-Dec-2019.) |
| ⊢ EqvRels = {𝑟 ∈ Rels ∣ (∀𝑥 ∈ dom 𝑟 𝑥𝑟𝑥 ∧ ∀𝑥∀𝑦(𝑥𝑟𝑦 → 𝑦𝑟𝑥) ∧ ∀𝑥∀𝑦∀𝑧((𝑥𝑟𝑦 ∧ 𝑦𝑟𝑧) → 𝑥𝑟𝑧))} | ||
| Theorem | dfeqvrel2 39048 | Alternate definition of the equivalence relation predicate. (Contributed by Peter Mazsa, 22-Apr-2019.) |
| ⊢ ( EqvRel 𝑅 ↔ ((( I ↾ dom 𝑅) ⊆ 𝑅 ∧ ◡𝑅 ⊆ 𝑅 ∧ (𝑅 ∘ 𝑅) ⊆ 𝑅) ∧ Rel 𝑅)) | ||
| Theorem | dfeqvrel3 39049* | Alternate definition of the equivalence relation predicate. (Contributed by Peter Mazsa, 22-Apr-2019.) |
| ⊢ ( EqvRel 𝑅 ↔ ((∀𝑥 ∈ dom 𝑅 𝑥𝑅𝑥 ∧ ∀𝑥∀𝑦(𝑥𝑅𝑦 → 𝑦𝑅𝑥) ∧ ∀𝑥∀𝑦∀𝑧((𝑥𝑅𝑦 ∧ 𝑦𝑅𝑧) → 𝑥𝑅𝑧)) ∧ Rel 𝑅)) | ||
| Theorem | eleqvrels2 39050 | Element of the class of equivalence relations. (Contributed by Peter Mazsa, 24-Aug-2021.) |
| ⊢ (𝑅 ∈ EqvRels ↔ ((( I ↾ dom 𝑅) ⊆ 𝑅 ∧ ◡𝑅 ⊆ 𝑅 ∧ (𝑅 ∘ 𝑅) ⊆ 𝑅) ∧ 𝑅 ∈ Rels )) | ||
| Theorem | eleqvrels3 39051* | Element of the class of equivalence relations. (Contributed by Peter Mazsa, 24-Aug-2021.) |
| ⊢ (𝑅 ∈ EqvRels ↔ ((∀𝑥 ∈ dom 𝑅 𝑥𝑅𝑥 ∧ ∀𝑥∀𝑦(𝑥𝑅𝑦 → 𝑦𝑅𝑥) ∧ ∀𝑥∀𝑦∀𝑧((𝑥𝑅𝑦 ∧ 𝑦𝑅𝑧) → 𝑥𝑅𝑧)) ∧ 𝑅 ∈ Rels )) | ||
| Theorem | eleqvrelsrel 39052 | For sets, being an element of the class of equivalence relations is equivalent to satisfying the equivalence relation predicate. (Contributed by Peter Mazsa, 24-Aug-2021.) |
| ⊢ (𝑅 ∈ 𝑉 → (𝑅 ∈ EqvRels ↔ EqvRel 𝑅)) | ||
| Theorem | elcoeleqvrels 39053 | Elementhood in the coelement equivalence relations class. (Contributed by Peter Mazsa, 24-Jul-2023.) |
| ⊢ (𝐴 ∈ 𝑉 → (𝐴 ∈ CoElEqvRels ↔ ≀ (◡ E ↾ 𝐴) ∈ EqvRels )) | ||
| Theorem | elcoeleqvrelsrel 39054 | For sets, being an element of the class of coelement equivalence relations is equivalent to satisfying the coelement equivalence relation predicate. (Contributed by Peter Mazsa, 24-Jul-2023.) |
| ⊢ (𝐴 ∈ 𝑉 → (𝐴 ∈ CoElEqvRels ↔ CoElEqvRel 𝐴)) | ||
| Theorem | eqvrelrel 39055 | An equivalence relation is a relation. (Contributed by Peter Mazsa, 2-Jun-2019.) |
| ⊢ ( EqvRel 𝑅 → Rel 𝑅) | ||
| Theorem | eqvrelrefrel 39056 | An equivalence relation is reflexive. (Contributed by Peter Mazsa, 29-Dec-2021.) |
| ⊢ ( EqvRel 𝑅 → RefRel 𝑅) | ||
| Theorem | eqvrelsymrel 39057 | An equivalence relation is symmetric. (Contributed by Peter Mazsa, 29-Dec-2021.) |
| ⊢ ( EqvRel 𝑅 → SymRel 𝑅) | ||
| Theorem | eqvreltrrel 39058 | An equivalence relation is transitive. (Contributed by Peter Mazsa, 29-Dec-2021.) |
| ⊢ ( EqvRel 𝑅 → TrRel 𝑅) | ||
| Theorem | eqvrelim 39059 | Equivalence relation implies that the domain and the range are equal. (Contributed by Peter Mazsa, 29-Dec-2021.) |
| ⊢ ( EqvRel 𝑅 → dom 𝑅 = ran 𝑅) | ||
| Theorem | eqvreleq 39060 | Equality theorem for equivalence relation. (Contributed by Peter Mazsa, 19-Apr-2020.) (Revised by Peter Mazsa, 23-Sep-2021.) |
| ⊢ (𝑅 = 𝑆 → ( EqvRel 𝑅 ↔ EqvRel 𝑆)) | ||
| Theorem | eqvreleqi 39061 | Equality theorem for equivalence relation, inference version. (Contributed by Peter Mazsa, 23-Sep-2021.) |
| ⊢ 𝑅 = 𝑆 ⇒ ⊢ ( EqvRel 𝑅 ↔ EqvRel 𝑆) | ||
| Theorem | eqvreleqd 39062 | Equality theorem for equivalence relation, deduction version. (Contributed by Peter Mazsa, 23-Sep-2021.) |
| ⊢ (𝜑 → 𝑅 = 𝑆) ⇒ ⊢ (𝜑 → ( EqvRel 𝑅 ↔ EqvRel 𝑆)) | ||
| Theorem | eqvrelsym 39063 | An equivalence relation is symmetric. (Contributed by NM, 4-Jun-1995.) (Revised by Mario Carneiro, 12-Aug-2015.) (Revised by Peter Mazsa, 2-Jun-2019.) |
| ⊢ (𝜑 → EqvRel 𝑅) & ⊢ (𝜑 → 𝐴𝑅𝐵) ⇒ ⊢ (𝜑 → 𝐵𝑅𝐴) | ||
| Theorem | eqvrelsymb 39064 | An equivalence relation is symmetric. (Contributed by NM, 30-Jul-1995.) (Revised by Mario Carneiro, 12-Aug-2015.) (Revised and distinct variable conditions removed by Peter Mazsa, 2-Jun-2019.) |
| ⊢ (𝜑 → EqvRel 𝑅) ⇒ ⊢ (𝜑 → (𝐴𝑅𝐵 ↔ 𝐵𝑅𝐴)) | ||
| Theorem | eqvreltr 39065 | An equivalence relation is transitive. (Contributed by NM, 4-Jun-1995.) (Revised by Mario Carneiro, 12-Aug-2015.) (Revised by Peter Mazsa, 2-Jun-2019.) |
| ⊢ (𝜑 → EqvRel 𝑅) ⇒ ⊢ (𝜑 → ((𝐴𝑅𝐵 ∧ 𝐵𝑅𝐶) → 𝐴𝑅𝐶)) | ||
| Theorem | eqvreltrd 39066 | A transitivity relation for equivalences. (Contributed by Mario Carneiro, 9-Jul-2014.) (Revised by Peter Mazsa, 2-Jun-2019.) |
| ⊢ (𝜑 → EqvRel 𝑅) & ⊢ (𝜑 → 𝐴𝑅𝐵) & ⊢ (𝜑 → 𝐵𝑅𝐶) ⇒ ⊢ (𝜑 → 𝐴𝑅𝐶) | ||
| Theorem | eqvreltr4d 39067 | A transitivity relation for equivalences. (Contributed by Mario Carneiro, 9-Jul-2014.) (Revised by Peter Mazsa, 2-Jun-2019.) |
| ⊢ (𝜑 → EqvRel 𝑅) & ⊢ (𝜑 → 𝐴𝑅𝐵) & ⊢ (𝜑 → 𝐶𝑅𝐵) ⇒ ⊢ (𝜑 → 𝐴𝑅𝐶) | ||
| Theorem | eqvrelref 39068 | An equivalence relation is reflexive on its field. Compare Theorem 3M of [Enderton] p. 56. (Contributed by Mario Carneiro, 6-May-2013.) (Revised by Mario Carneiro, 12-Aug-2015.) (Revised by Peter Mazsa, 2-Jun-2019.) |
| ⊢ (𝜑 → EqvRel 𝑅) & ⊢ (𝜑 → 𝐴 ∈ dom 𝑅) ⇒ ⊢ (𝜑 → 𝐴𝑅𝐴) | ||
| Theorem | eqvrelth 39069 | Basic property of equivalence relations. Theorem 73 of [Suppes] p. 82. (Contributed by NM, 23-Jul-1995.) (Revised by Mario Carneiro, 6-Jul-2015.) (Revised by Peter Mazsa, 2-Jun-2019.) |
| ⊢ (𝜑 → EqvRel 𝑅) & ⊢ (𝜑 → 𝐴 ∈ dom 𝑅) ⇒ ⊢ (𝜑 → (𝐴𝑅𝐵 ↔ [𝐴]𝑅 = [𝐵]𝑅)) | ||
| Theorem | eqvrelcl 39070 | Elementhood in the field of an equivalence relation. (Contributed by Mario Carneiro, 12-Aug-2015.) (Revised by Peter Mazsa, 2-Jun-2019.) |
| ⊢ (𝜑 → EqvRel 𝑅) & ⊢ (𝜑 → 𝐴𝑅𝐵) ⇒ ⊢ (𝜑 → 𝐴 ∈ dom 𝑅) | ||
| Theorem | eqvrelthi 39071 | Basic property of equivalence relations. Part of Lemma 3N of [Enderton] p. 57. (Contributed by NM, 30-Jul-1995.) (Revised by Mario Carneiro, 9-Jul-2014.) (Revised by Peter Mazsa, 2-Jun-2019.) |
| ⊢ (𝜑 → EqvRel 𝑅) & ⊢ (𝜑 → 𝐴𝑅𝐵) ⇒ ⊢ (𝜑 → [𝐴]𝑅 = [𝐵]𝑅) | ||
| Theorem | eqvreldisj 39072 | Equivalence classes do not overlap. In other words, two equivalence classes are either equal or disjoint. Theorem 74 of [Suppes] p. 83. (Contributed by NM, 15-Jun-2004.) (Revised by Mario Carneiro, 9-Jul-2014.) (Revised by Peter Mazsa, 2-Jun-2019.) |
| ⊢ ( EqvRel 𝑅 → ([𝐴]𝑅 = [𝐵]𝑅 ∨ ([𝐴]𝑅 ∩ [𝐵]𝑅) = ∅)) | ||
| Theorem | qsdisjALTV 39073 | Elements of a quotient set do not overlap. (Contributed by Rodolfo Medina, 12-Oct-2010.) (Revised by Mario Carneiro, 11-Jul-2014.) (Revised by Peter Mazsa, 3-Jun-2019.) |
| ⊢ (𝜑 → EqvRel 𝑅) & ⊢ (𝜑 → 𝐵 ∈ (𝐴 / 𝑅)) & ⊢ (𝜑 → 𝐶 ∈ (𝐴 / 𝑅)) ⇒ ⊢ (𝜑 → (𝐵 = 𝐶 ∨ (𝐵 ∩ 𝐶) = ∅)) | ||
| Theorem | eqvrelqsel 39074 | If an element of a quotient set contains a given element, it is equal to the equivalence class of the element. (Contributed by Mario Carneiro, 12-Aug-2015.) (Revised by Peter Mazsa, 28-Dec-2019.) |
| ⊢ (( EqvRel 𝑅 ∧ 𝐵 ∈ (𝐴 / 𝑅) ∧ 𝐶 ∈ 𝐵) → 𝐵 = [𝐶]𝑅) | ||
| Theorem | eqvrelcoss 39075 | Two ways to express equivalent cosets. (Contributed by Peter Mazsa, 4-Jul-2020.) (Revised by Peter Mazsa, 20-Dec-2021.) |
| ⊢ ( EqvRel ≀ 𝑅 ↔ TrRel ≀ 𝑅) | ||
| Theorem | eqvrelcoss3 39076* | Two ways to express equivalent cosets. (Contributed by Peter Mazsa, 28-Apr-2019.) |
| ⊢ ( EqvRel ≀ 𝑅 ↔ ∀𝑥∀𝑦∀𝑧((𝑥 ≀ 𝑅𝑦 ∧ 𝑦 ≀ 𝑅𝑧) → 𝑥 ≀ 𝑅𝑧)) | ||
| Theorem | eqvrelcoss2 39077 | Two ways to express equivalent cosets. (Contributed by Peter Mazsa, 3-May-2019.) |
| ⊢ ( EqvRel ≀ 𝑅 ↔ ≀ ≀ 𝑅 ⊆ ≀ 𝑅) | ||
| Theorem | eqvrelcoss4 39078* | Two ways to express equivalent cosets. (Contributed by Peter Mazsa, 3-May-2019.) (Revised by Peter Mazsa, 30-Sep-2021.) |
| ⊢ ( EqvRel ≀ 𝑅 ↔ ∀𝑥∀𝑧(([𝑥] ≀ 𝑅 ∩ [𝑧] ≀ 𝑅) ≠ ∅ → ([𝑥]◡𝑅 ∩ [𝑧]◡𝑅) ≠ ∅)) | ||
| Theorem | dfcoeleqvrels 39079 | Alternate definition of the coelement equivalence relations class. Other alternate definitions should be based on eqvrelcoss2 39077, eqvrelcoss3 39076 and eqvrelcoss4 39078 when needed. (Contributed by Peter Mazsa, 28-Nov-2022.) |
| ⊢ CoElEqvRels = {𝑎 ∣ ∼ 𝑎 ∈ EqvRels } | ||
| Theorem | dfcoeleqvrel 39080 | Alternate definition of the coelement equivalence relation predicate: a coelement equivalence relation is an equivalence relation on coelements. Other alternate definitions should be based on eqvrelcoss2 39077, eqvrelcoss3 39076 and eqvrelcoss4 39078 when needed. (Contributed by Peter Mazsa, 28-Nov-2022.) |
| ⊢ ( CoElEqvRel 𝐴 ↔ EqvRel ∼ 𝐴) | ||
| Definition | df-redunds 39081* | Define the class of all redundant sets 𝑥 with respect to 𝑦 in 𝑧. For sets, binary relation on the class of all redundant sets (brredunds 39084) is equivalent to satisfying the redundancy predicate (df-redund 39082). (Contributed by Peter Mazsa, 23-Oct-2022.) |
| ⊢ Redunds = ◡{〈〈𝑦, 𝑧〉, 𝑥〉 ∣ (𝑥 ⊆ 𝑦 ∧ (𝑥 ∩ 𝑧) = (𝑦 ∩ 𝑧))} | ||
| Definition | df-redund 39082 | Define the redundancy predicate. Read: 𝐴 is redundant with respect to 𝐵 in 𝐶. For sets, binary relation on the class of all redundant sets (brredunds 39084) is equivalent to satisfying the redundancy predicate. (Contributed by Peter Mazsa, 23-Oct-2022.) |
| ⊢ (𝐴 Redund 〈𝐵, 𝐶〉 ↔ (𝐴 ⊆ 𝐵 ∧ (𝐴 ∩ 𝐶) = (𝐵 ∩ 𝐶))) | ||
| Definition | df-redundp 39083 | Define the redundancy operator for propositions, cf. df-redund 39082. (Contributed by Peter Mazsa, 23-Oct-2022.) |
| ⊢ ( redund (𝜑, 𝜓, 𝜒) ↔ ((𝜑 → 𝜓) ∧ ((𝜑 ∧ 𝜒) ↔ (𝜓 ∧ 𝜒)))) | ||
| Theorem | brredunds 39084 | Binary relation on the class of all redundant sets. (Contributed by Peter Mazsa, 25-Oct-2022.) |
| ⊢ ((𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊 ∧ 𝐶 ∈ 𝑋) → (𝐴 Redunds 〈𝐵, 𝐶〉 ↔ (𝐴 ⊆ 𝐵 ∧ (𝐴 ∩ 𝐶) = (𝐵 ∩ 𝐶)))) | ||
| Theorem | brredundsredund 39085 | For sets, binary relation on the class of all redundant sets (brredunds 39084) is equivalent to satisfying the redundancy predicate (df-redund 39082). (Contributed by Peter Mazsa, 25-Oct-2022.) |
| ⊢ ((𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊 ∧ 𝐶 ∈ 𝑋) → (𝐴 Redunds 〈𝐵, 𝐶〉 ↔ 𝐴 Redund 〈𝐵, 𝐶〉)) | ||
| Theorem | redundss3 39086 | Implication of redundancy predicate. (Contributed by Peter Mazsa, 26-Oct-2022.) |
| ⊢ 𝐷 ⊆ 𝐶 ⇒ ⊢ (𝐴 Redund 〈𝐵, 𝐶〉 → 𝐴 Redund 〈𝐵, 𝐷〉) | ||
| Theorem | redundeq1 39087 | Equivalence of redundancy predicates. (Contributed by Peter Mazsa, 26-Oct-2022.) |
| ⊢ 𝐴 = 𝐷 ⇒ ⊢ (𝐴 Redund 〈𝐵, 𝐶〉 ↔ 𝐷 Redund 〈𝐵, 𝐶〉) | ||
| Theorem | redundpim3 39088 | Implication of redundancy of proposition. (Contributed by Peter Mazsa, 26-Oct-2022.) |
| ⊢ (𝜃 → 𝜒) ⇒ ⊢ ( redund (𝜑, 𝜓, 𝜒) → redund (𝜑, 𝜓, 𝜃)) | ||
| Theorem | redundpbi1 39089 | Equivalence of redundancy of propositions. (Contributed by Peter Mazsa, 25-Oct-2022.) |
| ⊢ (𝜑 ↔ 𝜃) ⇒ ⊢ ( redund (𝜑, 𝜓, 𝜒) ↔ redund (𝜃, 𝜓, 𝜒)) | ||
| Theorem | refrelsredund4 39090 | The naive version of the class of reflexive relations is redundant with respect to the class of reflexive relations (see dfrefrels2 38967) if the relations are symmetric as well. (Contributed by Peter Mazsa, 26-Oct-2022.) |
| ⊢ {𝑟 ∈ Rels ∣ ( I ↾ dom 𝑟) ⊆ 𝑟} Redund 〈 RefRels , ( RefRels ∩ SymRels )〉 | ||
| Theorem | refrelsredund2 39091 | The naive version of the class of reflexive relations is redundant with respect to the class of reflexive relations (see dfrefrels2 38967) in the class of equivalence relations. (Contributed by Peter Mazsa, 26-Oct-2022.) |
| ⊢ {𝑟 ∈ Rels ∣ ( I ↾ dom 𝑟) ⊆ 𝑟} Redund 〈 RefRels , EqvRels 〉 | ||
| Theorem | refrelsredund3 39092* | The naive version of the class of reflexive relations {𝑟 ∈ Rels ∣ ∀𝑥 ∈ dom 𝑟𝑥𝑟𝑥} is redundant with respect to the class of reflexive relations (see dfrefrels3 38968) in the class of equivalence relations. (Contributed by Peter Mazsa, 26-Oct-2022.) |
| ⊢ {𝑟 ∈ Rels ∣ ∀𝑥 ∈ dom 𝑟 𝑥𝑟𝑥} Redund 〈 RefRels , EqvRels 〉 | ||
| Theorem | refrelredund4 39093 | The naive version of the definition of reflexive relation is redundant with respect to reflexive relation (see dfrefrel2 38969) if the relation is symmetric as well. (Contributed by Peter Mazsa, 26-Oct-2022.) |
| ⊢ redund ((( I ↾ dom 𝑅) ⊆ 𝑅 ∧ Rel 𝑅), RefRel 𝑅, ( RefRel 𝑅 ∧ SymRel 𝑅)) | ||
| Theorem | refrelredund2 39094 | The naive version of the definition of reflexive relation is redundant with respect to reflexive relation (see dfrefrel2 38969) in equivalence relation. (Contributed by Peter Mazsa, 25-Oct-2022.) |
| ⊢ redund ((( I ↾ dom 𝑅) ⊆ 𝑅 ∧ Rel 𝑅), RefRel 𝑅, EqvRel 𝑅) | ||
| Theorem | refrelredund3 39095* | The naive version of the definition of reflexive relation (∀𝑥 ∈ dom 𝑅𝑥𝑅𝑥 ∧ Rel 𝑅) is redundant with respect to reflexive relation (see dfrefrel3 38970) in equivalence relation. (Contributed by Peter Mazsa, 25-Oct-2022.) |
| ⊢ redund ((∀𝑥 ∈ dom 𝑅 𝑥𝑅𝑥 ∧ Rel 𝑅), RefRel 𝑅, EqvRel 𝑅) | ||
| Definition | df-dmqss 39096* | Define the class of domain quotients. Domain quotients are pairs of sets, typically a relation and a set, where the quotient (see df-qs 8646) of the relation on its domain is equal to the set. See comments of df-ers 39122 for the motivation for this definition. (Contributed by Peter Mazsa, 16-Apr-2019.) |
| ⊢ DomainQss = {〈𝑥, 𝑦〉 ∣ (dom 𝑥 / 𝑥) = 𝑦} | ||
| Definition | df-dmqs 39097 | Define the domain quotient predicate. (Read: the domain quotient of 𝑅 is 𝐴.) If 𝐴 and 𝑅 are sets, the domain quotient binary relation and the domain quotient predicate are the same, see brdmqssqs 39105. (Contributed by Peter Mazsa, 9-Aug-2021.) |
| ⊢ (𝑅 DomainQs 𝐴 ↔ (dom 𝑅 / 𝑅) = 𝐴) | ||
| Theorem | dmqseq 39098 | Equality theorem for domain quotient. (Contributed by Peter Mazsa, 17-Apr-2019.) |
| ⊢ (𝑅 = 𝑆 → (dom 𝑅 / 𝑅) = (dom 𝑆 / 𝑆)) | ||
| Theorem | dmqseqi 39099 | Equality theorem for domain quotient, inference version. (Contributed by Peter Mazsa, 26-Sep-2021.) |
| ⊢ 𝑅 = 𝑆 ⇒ ⊢ (dom 𝑅 / 𝑅) = (dom 𝑆 / 𝑆) | ||
| Theorem | dmqseqd 39100 | Equality theorem for domain quotient set, deduction version. (Contributed by Peter Mazsa, 23-Apr-2021.) |
| ⊢ (𝜑 → 𝑅 = 𝑆) ⇒ ⊢ (𝜑 → (dom 𝑅 / 𝑅) = (dom 𝑆 / 𝑆)) | ||
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