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| Type | Label | Description |
|---|---|---|
| Statement | ||
| Theorem | trreleq 39001 | Equality theorem for the transitive relation predicate. (Contributed by Peter Mazsa, 15-Apr-2019.) (Revised by Peter Mazsa, 23-Sep-2021.) |
| ⊢ (𝑅 = 𝑆 → ( TrRel 𝑅 ↔ TrRel 𝑆)) | ||
| Theorem | trrelressn 39002 | Any class ' R ' restricted to the singleton of the class ' A ' (see ressn2 38867) is transitive. (Contributed by Peter Mazsa, 17-Jun-2024.) |
| ⊢ TrRel (𝑅 ↾ {𝐴}) | ||
| Definition | df-eqvrels 39003 | Define the class of equivalence relations. For sets, being an element of the class of equivalence relations is equivalent to satisfying the equivalence relation predicate, see eleqvrelsrel 39013. Alternate definitions are dfeqvrels2 39007 and dfeqvrels3 39008. (Contributed by Peter Mazsa, 7-Nov-2018.) |
| ⊢ EqvRels = (( RefRels ∩ SymRels ) ∩ TrRels ) | ||
| Definition | df-eqvrel 39004 | Define the equivalence relation predicate. (Read: 𝑅 is an equivalence relation.) For sets, being an element of the class of equivalence relations (df-eqvrels 39003) is equivalent to satisfying the equivalence relation predicate, see eleqvrelsrel 39013. Alternate definitions are dfeqvrel2 39009 and dfeqvrel3 39010. (Contributed by Peter Mazsa, 17-Apr-2019.) |
| ⊢ ( EqvRel 𝑅 ↔ ( RefRel 𝑅 ∧ SymRel 𝑅 ∧ TrRel 𝑅)) | ||
| Definition | df-coeleqvrels 39005 | Define the coelement equivalence relations class, the class of sets with coelement equivalence relations. For sets, being an element of the class of coelement equivalence relations is equivalent to satisfying the coelement equivalence relation predicate, see elcoeleqvrelsrel 39015. Alternate definition is dfcoeleqvrels 39040. (Contributed by Peter Mazsa, 28-Nov-2022.) |
| ⊢ CoElEqvRels = {𝑎 ∣ ≀ (◡ E ↾ 𝑎) ∈ EqvRels } | ||
| Definition | df-coeleqvrel 39006 | Define the coelement equivalence relation predicate. (Read: the coelement equivalence relation on 𝐴.) Alternate definition is dfcoeleqvrel 39041. For sets, being an element of the class of coelement equivalence relations is equivalent to satisfying the coelement equivalence relation predicate, see elcoeleqvrelsrel 39015. (Contributed by Peter Mazsa, 11-Dec-2021.) |
| ⊢ ( CoElEqvRel 𝐴 ↔ EqvRel ≀ (◡ E ↾ 𝐴)) | ||
| Theorem | dfeqvrels2 39007 | Alternate definition of the class of equivalence relations. (Contributed by Peter Mazsa, 2-Dec-2019.) |
| ⊢ EqvRels = {𝑟 ∈ Rels ∣ (( I ↾ dom 𝑟) ⊆ 𝑟 ∧ ◡𝑟 ⊆ 𝑟 ∧ (𝑟 ∘ 𝑟) ⊆ 𝑟)} | ||
| Theorem | dfeqvrels3 39008* | Alternate definition of the class of equivalence relations. (Contributed by Peter Mazsa, 2-Dec-2019.) |
| ⊢ EqvRels = {𝑟 ∈ Rels ∣ (∀𝑥 ∈ dom 𝑟 𝑥𝑟𝑥 ∧ ∀𝑥∀𝑦(𝑥𝑟𝑦 → 𝑦𝑟𝑥) ∧ ∀𝑥∀𝑦∀𝑧((𝑥𝑟𝑦 ∧ 𝑦𝑟𝑧) → 𝑥𝑟𝑧))} | ||
| Theorem | dfeqvrel2 39009 | Alternate definition of the equivalence relation predicate. (Contributed by Peter Mazsa, 22-Apr-2019.) |
| ⊢ ( EqvRel 𝑅 ↔ ((( I ↾ dom 𝑅) ⊆ 𝑅 ∧ ◡𝑅 ⊆ 𝑅 ∧ (𝑅 ∘ 𝑅) ⊆ 𝑅) ∧ Rel 𝑅)) | ||
| Theorem | dfeqvrel3 39010* | Alternate definition of the equivalence relation predicate. (Contributed by Peter Mazsa, 22-Apr-2019.) |
| ⊢ ( EqvRel 𝑅 ↔ ((∀𝑥 ∈ dom 𝑅 𝑥𝑅𝑥 ∧ ∀𝑥∀𝑦(𝑥𝑅𝑦 → 𝑦𝑅𝑥) ∧ ∀𝑥∀𝑦∀𝑧((𝑥𝑅𝑦 ∧ 𝑦𝑅𝑧) → 𝑥𝑅𝑧)) ∧ Rel 𝑅)) | ||
| Theorem | eleqvrels2 39011 | Element of the class of equivalence relations. (Contributed by Peter Mazsa, 24-Aug-2021.) |
| ⊢ (𝑅 ∈ EqvRels ↔ ((( I ↾ dom 𝑅) ⊆ 𝑅 ∧ ◡𝑅 ⊆ 𝑅 ∧ (𝑅 ∘ 𝑅) ⊆ 𝑅) ∧ 𝑅 ∈ Rels )) | ||
| Theorem | eleqvrels3 39012* | Element of the class of equivalence relations. (Contributed by Peter Mazsa, 24-Aug-2021.) |
| ⊢ (𝑅 ∈ EqvRels ↔ ((∀𝑥 ∈ dom 𝑅 𝑥𝑅𝑥 ∧ ∀𝑥∀𝑦(𝑥𝑅𝑦 → 𝑦𝑅𝑥) ∧ ∀𝑥∀𝑦∀𝑧((𝑥𝑅𝑦 ∧ 𝑦𝑅𝑧) → 𝑥𝑅𝑧)) ∧ 𝑅 ∈ Rels )) | ||
| Theorem | eleqvrelsrel 39013 | For sets, being an element of the class of equivalence relations is equivalent to satisfying the equivalence relation predicate. (Contributed by Peter Mazsa, 24-Aug-2021.) |
| ⊢ (𝑅 ∈ 𝑉 → (𝑅 ∈ EqvRels ↔ EqvRel 𝑅)) | ||
| Theorem | elcoeleqvrels 39014 | Elementhood in the coelement equivalence relations class. (Contributed by Peter Mazsa, 24-Jul-2023.) |
| ⊢ (𝐴 ∈ 𝑉 → (𝐴 ∈ CoElEqvRels ↔ ≀ (◡ E ↾ 𝐴) ∈ EqvRels )) | ||
| Theorem | elcoeleqvrelsrel 39015 | For sets, being an element of the class of coelement equivalence relations is equivalent to satisfying the coelement equivalence relation predicate. (Contributed by Peter Mazsa, 24-Jul-2023.) |
| ⊢ (𝐴 ∈ 𝑉 → (𝐴 ∈ CoElEqvRels ↔ CoElEqvRel 𝐴)) | ||
| Theorem | eqvrelrel 39016 | An equivalence relation is a relation. (Contributed by Peter Mazsa, 2-Jun-2019.) |
| ⊢ ( EqvRel 𝑅 → Rel 𝑅) | ||
| Theorem | eqvrelrefrel 39017 | An equivalence relation is reflexive. (Contributed by Peter Mazsa, 29-Dec-2021.) |
| ⊢ ( EqvRel 𝑅 → RefRel 𝑅) | ||
| Theorem | eqvrelsymrel 39018 | An equivalence relation is symmetric. (Contributed by Peter Mazsa, 29-Dec-2021.) |
| ⊢ ( EqvRel 𝑅 → SymRel 𝑅) | ||
| Theorem | eqvreltrrel 39019 | An equivalence relation is transitive. (Contributed by Peter Mazsa, 29-Dec-2021.) |
| ⊢ ( EqvRel 𝑅 → TrRel 𝑅) | ||
| Theorem | eqvrelim 39020 | Equivalence relation implies that the domain and the range are equal. (Contributed by Peter Mazsa, 29-Dec-2021.) |
| ⊢ ( EqvRel 𝑅 → dom 𝑅 = ran 𝑅) | ||
| Theorem | eqvreleq 39021 | Equality theorem for equivalence relation. (Contributed by Peter Mazsa, 19-Apr-2020.) (Revised by Peter Mazsa, 23-Sep-2021.) |
| ⊢ (𝑅 = 𝑆 → ( EqvRel 𝑅 ↔ EqvRel 𝑆)) | ||
| Theorem | eqvreleqi 39022 | Equality theorem for equivalence relation, inference version. (Contributed by Peter Mazsa, 23-Sep-2021.) |
| ⊢ 𝑅 = 𝑆 ⇒ ⊢ ( EqvRel 𝑅 ↔ EqvRel 𝑆) | ||
| Theorem | eqvreleqd 39023 | Equality theorem for equivalence relation, deduction version. (Contributed by Peter Mazsa, 23-Sep-2021.) |
| ⊢ (𝜑 → 𝑅 = 𝑆) ⇒ ⊢ (𝜑 → ( EqvRel 𝑅 ↔ EqvRel 𝑆)) | ||
| Theorem | eqvrelsym 39024 | An equivalence relation is symmetric. (Contributed by NM, 4-Jun-1995.) (Revised by Mario Carneiro, 12-Aug-2015.) (Revised by Peter Mazsa, 2-Jun-2019.) |
| ⊢ (𝜑 → EqvRel 𝑅) & ⊢ (𝜑 → 𝐴𝑅𝐵) ⇒ ⊢ (𝜑 → 𝐵𝑅𝐴) | ||
| Theorem | eqvrelsymb 39025 | An equivalence relation is symmetric. (Contributed by NM, 30-Jul-1995.) (Revised by Mario Carneiro, 12-Aug-2015.) (Revised and distinct variable conditions removed by Peter Mazsa, 2-Jun-2019.) |
| ⊢ (𝜑 → EqvRel 𝑅) ⇒ ⊢ (𝜑 → (𝐴𝑅𝐵 ↔ 𝐵𝑅𝐴)) | ||
| Theorem | eqvreltr 39026 | An equivalence relation is transitive. (Contributed by NM, 4-Jun-1995.) (Revised by Mario Carneiro, 12-Aug-2015.) (Revised by Peter Mazsa, 2-Jun-2019.) |
| ⊢ (𝜑 → EqvRel 𝑅) ⇒ ⊢ (𝜑 → ((𝐴𝑅𝐵 ∧ 𝐵𝑅𝐶) → 𝐴𝑅𝐶)) | ||
| Theorem | eqvreltrd 39027 | A transitivity relation for equivalences. (Contributed by Mario Carneiro, 9-Jul-2014.) (Revised by Peter Mazsa, 2-Jun-2019.) |
| ⊢ (𝜑 → EqvRel 𝑅) & ⊢ (𝜑 → 𝐴𝑅𝐵) & ⊢ (𝜑 → 𝐵𝑅𝐶) ⇒ ⊢ (𝜑 → 𝐴𝑅𝐶) | ||
| Theorem | eqvreltr4d 39028 | A transitivity relation for equivalences. (Contributed by Mario Carneiro, 9-Jul-2014.) (Revised by Peter Mazsa, 2-Jun-2019.) |
| ⊢ (𝜑 → EqvRel 𝑅) & ⊢ (𝜑 → 𝐴𝑅𝐵) & ⊢ (𝜑 → 𝐶𝑅𝐵) ⇒ ⊢ (𝜑 → 𝐴𝑅𝐶) | ||
| Theorem | eqvrelref 39029 | An equivalence relation is reflexive on its field. Compare Theorem 3M of [Enderton] p. 56. (Contributed by Mario Carneiro, 6-May-2013.) (Revised by Mario Carneiro, 12-Aug-2015.) (Revised by Peter Mazsa, 2-Jun-2019.) |
| ⊢ (𝜑 → EqvRel 𝑅) & ⊢ (𝜑 → 𝐴 ∈ dom 𝑅) ⇒ ⊢ (𝜑 → 𝐴𝑅𝐴) | ||
| Theorem | eqvrelth 39030 | Basic property of equivalence relations. Theorem 73 of [Suppes] p. 82. (Contributed by NM, 23-Jul-1995.) (Revised by Mario Carneiro, 6-Jul-2015.) (Revised by Peter Mazsa, 2-Jun-2019.) |
| ⊢ (𝜑 → EqvRel 𝑅) & ⊢ (𝜑 → 𝐴 ∈ dom 𝑅) ⇒ ⊢ (𝜑 → (𝐴𝑅𝐵 ↔ [𝐴]𝑅 = [𝐵]𝑅)) | ||
| Theorem | eqvrelcl 39031 | Elementhood in the field of an equivalence relation. (Contributed by Mario Carneiro, 12-Aug-2015.) (Revised by Peter Mazsa, 2-Jun-2019.) |
| ⊢ (𝜑 → EqvRel 𝑅) & ⊢ (𝜑 → 𝐴𝑅𝐵) ⇒ ⊢ (𝜑 → 𝐴 ∈ dom 𝑅) | ||
| Theorem | eqvrelthi 39032 | Basic property of equivalence relations. Part of Lemma 3N of [Enderton] p. 57. (Contributed by NM, 30-Jul-1995.) (Revised by Mario Carneiro, 9-Jul-2014.) (Revised by Peter Mazsa, 2-Jun-2019.) |
| ⊢ (𝜑 → EqvRel 𝑅) & ⊢ (𝜑 → 𝐴𝑅𝐵) ⇒ ⊢ (𝜑 → [𝐴]𝑅 = [𝐵]𝑅) | ||
| Theorem | eqvreldisj 39033 | Equivalence classes do not overlap. In other words, two equivalence classes are either equal or disjoint. Theorem 74 of [Suppes] p. 83. (Contributed by NM, 15-Jun-2004.) (Revised by Mario Carneiro, 9-Jul-2014.) (Revised by Peter Mazsa, 2-Jun-2019.) |
| ⊢ ( EqvRel 𝑅 → ([𝐴]𝑅 = [𝐵]𝑅 ∨ ([𝐴]𝑅 ∩ [𝐵]𝑅) = ∅)) | ||
| Theorem | qsdisjALTV 39034 | Elements of a quotient set do not overlap. (Contributed by Rodolfo Medina, 12-Oct-2010.) (Revised by Mario Carneiro, 11-Jul-2014.) (Revised by Peter Mazsa, 3-Jun-2019.) |
| ⊢ (𝜑 → EqvRel 𝑅) & ⊢ (𝜑 → 𝐵 ∈ (𝐴 / 𝑅)) & ⊢ (𝜑 → 𝐶 ∈ (𝐴 / 𝑅)) ⇒ ⊢ (𝜑 → (𝐵 = 𝐶 ∨ (𝐵 ∩ 𝐶) = ∅)) | ||
| Theorem | eqvrelqsel 39035 | If an element of a quotient set contains a given element, it is equal to the equivalence class of the element. (Contributed by Mario Carneiro, 12-Aug-2015.) (Revised by Peter Mazsa, 28-Dec-2019.) |
| ⊢ (( EqvRel 𝑅 ∧ 𝐵 ∈ (𝐴 / 𝑅) ∧ 𝐶 ∈ 𝐵) → 𝐵 = [𝐶]𝑅) | ||
| Theorem | eqvrelcoss 39036 | Two ways to express equivalent cosets. (Contributed by Peter Mazsa, 4-Jul-2020.) (Revised by Peter Mazsa, 20-Dec-2021.) |
| ⊢ ( EqvRel ≀ 𝑅 ↔ TrRel ≀ 𝑅) | ||
| Theorem | eqvrelcoss3 39037* | Two ways to express equivalent cosets. (Contributed by Peter Mazsa, 28-Apr-2019.) |
| ⊢ ( EqvRel ≀ 𝑅 ↔ ∀𝑥∀𝑦∀𝑧((𝑥 ≀ 𝑅𝑦 ∧ 𝑦 ≀ 𝑅𝑧) → 𝑥 ≀ 𝑅𝑧)) | ||
| Theorem | eqvrelcoss2 39038 | Two ways to express equivalent cosets. (Contributed by Peter Mazsa, 3-May-2019.) |
| ⊢ ( EqvRel ≀ 𝑅 ↔ ≀ ≀ 𝑅 ⊆ ≀ 𝑅) | ||
| Theorem | eqvrelcoss4 39039* | Two ways to express equivalent cosets. (Contributed by Peter Mazsa, 3-May-2019.) (Revised by Peter Mazsa, 30-Sep-2021.) |
| ⊢ ( EqvRel ≀ 𝑅 ↔ ∀𝑥∀𝑧(([𝑥] ≀ 𝑅 ∩ [𝑧] ≀ 𝑅) ≠ ∅ → ([𝑥]◡𝑅 ∩ [𝑧]◡𝑅) ≠ ∅)) | ||
| Theorem | dfcoeleqvrels 39040 | Alternate definition of the coelement equivalence relations class. Other alternate definitions should be based on eqvrelcoss2 39038, eqvrelcoss3 39037 and eqvrelcoss4 39039 when needed. (Contributed by Peter Mazsa, 28-Nov-2022.) |
| ⊢ CoElEqvRels = {𝑎 ∣ ∼ 𝑎 ∈ EqvRels } | ||
| Theorem | dfcoeleqvrel 39041 | Alternate definition of the coelement equivalence relation predicate: a coelement equivalence relation is an equivalence relation on coelements. Other alternate definitions should be based on eqvrelcoss2 39038, eqvrelcoss3 39037 and eqvrelcoss4 39039 when needed. (Contributed by Peter Mazsa, 28-Nov-2022.) |
| ⊢ ( CoElEqvRel 𝐴 ↔ EqvRel ∼ 𝐴) | ||
| Definition | df-redunds 39042* | Define the class of all redundant sets 𝑥 with respect to 𝑦 in 𝑧. For sets, binary relation on the class of all redundant sets (brredunds 39045) is equivalent to satisfying the redundancy predicate (df-redund 39043). (Contributed by Peter Mazsa, 23-Oct-2022.) |
| ⊢ Redunds = ◡{〈〈𝑦, 𝑧〉, 𝑥〉 ∣ (𝑥 ⊆ 𝑦 ∧ (𝑥 ∩ 𝑧) = (𝑦 ∩ 𝑧))} | ||
| Definition | df-redund 39043 | Define the redundancy predicate. Read: 𝐴 is redundant with respect to 𝐵 in 𝐶. For sets, binary relation on the class of all redundant sets (brredunds 39045) is equivalent to satisfying the redundancy predicate. (Contributed by Peter Mazsa, 23-Oct-2022.) |
| ⊢ (𝐴 Redund 〈𝐵, 𝐶〉 ↔ (𝐴 ⊆ 𝐵 ∧ (𝐴 ∩ 𝐶) = (𝐵 ∩ 𝐶))) | ||
| Definition | df-redundp 39044 | Define the redundancy operator for propositions, cf. df-redund 39043. (Contributed by Peter Mazsa, 23-Oct-2022.) |
| ⊢ ( redund (𝜑, 𝜓, 𝜒) ↔ ((𝜑 → 𝜓) ∧ ((𝜑 ∧ 𝜒) ↔ (𝜓 ∧ 𝜒)))) | ||
| Theorem | brredunds 39045 | Binary relation on the class of all redundant sets. (Contributed by Peter Mazsa, 25-Oct-2022.) |
| ⊢ ((𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊 ∧ 𝐶 ∈ 𝑋) → (𝐴 Redunds 〈𝐵, 𝐶〉 ↔ (𝐴 ⊆ 𝐵 ∧ (𝐴 ∩ 𝐶) = (𝐵 ∩ 𝐶)))) | ||
| Theorem | brredundsredund 39046 | For sets, binary relation on the class of all redundant sets (brredunds 39045) is equivalent to satisfying the redundancy predicate (df-redund 39043). (Contributed by Peter Mazsa, 25-Oct-2022.) |
| ⊢ ((𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊 ∧ 𝐶 ∈ 𝑋) → (𝐴 Redunds 〈𝐵, 𝐶〉 ↔ 𝐴 Redund 〈𝐵, 𝐶〉)) | ||
| Theorem | redundss3 39047 | Implication of redundancy predicate. (Contributed by Peter Mazsa, 26-Oct-2022.) |
| ⊢ 𝐷 ⊆ 𝐶 ⇒ ⊢ (𝐴 Redund 〈𝐵, 𝐶〉 → 𝐴 Redund 〈𝐵, 𝐷〉) | ||
| Theorem | redundeq1 39048 | Equivalence of redundancy predicates. (Contributed by Peter Mazsa, 26-Oct-2022.) |
| ⊢ 𝐴 = 𝐷 ⇒ ⊢ (𝐴 Redund 〈𝐵, 𝐶〉 ↔ 𝐷 Redund 〈𝐵, 𝐶〉) | ||
| Theorem | redundpim3 39049 | Implication of redundancy of proposition. (Contributed by Peter Mazsa, 26-Oct-2022.) |
| ⊢ (𝜃 → 𝜒) ⇒ ⊢ ( redund (𝜑, 𝜓, 𝜒) → redund (𝜑, 𝜓, 𝜃)) | ||
| Theorem | redundpbi1 39050 | Equivalence of redundancy of propositions. (Contributed by Peter Mazsa, 25-Oct-2022.) |
| ⊢ (𝜑 ↔ 𝜃) ⇒ ⊢ ( redund (𝜑, 𝜓, 𝜒) ↔ redund (𝜃, 𝜓, 𝜒)) | ||
| Theorem | refrelsredund4 39051 | The naive version of the class of reflexive relations is redundant with respect to the class of reflexive relations (see dfrefrels2 38928) if the relations are symmetric as well. (Contributed by Peter Mazsa, 26-Oct-2022.) |
| ⊢ {𝑟 ∈ Rels ∣ ( I ↾ dom 𝑟) ⊆ 𝑟} Redund 〈 RefRels , ( RefRels ∩ SymRels )〉 | ||
| Theorem | refrelsredund2 39052 | The naive version of the class of reflexive relations is redundant with respect to the class of reflexive relations (see dfrefrels2 38928) in the class of equivalence relations. (Contributed by Peter Mazsa, 26-Oct-2022.) |
| ⊢ {𝑟 ∈ Rels ∣ ( I ↾ dom 𝑟) ⊆ 𝑟} Redund 〈 RefRels , EqvRels 〉 | ||
| Theorem | refrelsredund3 39053* | The naive version of the class of reflexive relations {𝑟 ∈ Rels ∣ ∀𝑥 ∈ dom 𝑟𝑥𝑟𝑥} is redundant with respect to the class of reflexive relations (see dfrefrels3 38929) in the class of equivalence relations. (Contributed by Peter Mazsa, 26-Oct-2022.) |
| ⊢ {𝑟 ∈ Rels ∣ ∀𝑥 ∈ dom 𝑟 𝑥𝑟𝑥} Redund 〈 RefRels , EqvRels 〉 | ||
| Theorem | refrelredund4 39054 | The naive version of the definition of reflexive relation is redundant with respect to reflexive relation (see dfrefrel2 38930) if the relation is symmetric as well. (Contributed by Peter Mazsa, 26-Oct-2022.) |
| ⊢ redund ((( I ↾ dom 𝑅) ⊆ 𝑅 ∧ Rel 𝑅), RefRel 𝑅, ( RefRel 𝑅 ∧ SymRel 𝑅)) | ||
| Theorem | refrelredund2 39055 | The naive version of the definition of reflexive relation is redundant with respect to reflexive relation (see dfrefrel2 38930) in equivalence relation. (Contributed by Peter Mazsa, 25-Oct-2022.) |
| ⊢ redund ((( I ↾ dom 𝑅) ⊆ 𝑅 ∧ Rel 𝑅), RefRel 𝑅, EqvRel 𝑅) | ||
| Theorem | refrelredund3 39056* | The naive version of the definition of reflexive relation (∀𝑥 ∈ dom 𝑅𝑥𝑅𝑥 ∧ Rel 𝑅) is redundant with respect to reflexive relation (see dfrefrel3 38931) in equivalence relation. (Contributed by Peter Mazsa, 25-Oct-2022.) |
| ⊢ redund ((∀𝑥 ∈ dom 𝑅 𝑥𝑅𝑥 ∧ Rel 𝑅), RefRel 𝑅, EqvRel 𝑅) | ||
| Definition | df-dmqss 39057* | Define the class of domain quotients. Domain quotients are pairs of sets, typically a relation and a set, where the quotient (see df-qs 8642) of the relation on its domain is equal to the set. See comments of df-ers 39083 for the motivation for this definition. (Contributed by Peter Mazsa, 16-Apr-2019.) |
| ⊢ DomainQss = {〈𝑥, 𝑦〉 ∣ (dom 𝑥 / 𝑥) = 𝑦} | ||
| Definition | df-dmqs 39058 | Define the domain quotient predicate. (Read: the domain quotient of 𝑅 is 𝐴.) If 𝐴 and 𝑅 are sets, the domain quotient binary relation and the domain quotient predicate are the same, see brdmqssqs 39066. (Contributed by Peter Mazsa, 9-Aug-2021.) |
| ⊢ (𝑅 DomainQs 𝐴 ↔ (dom 𝑅 / 𝑅) = 𝐴) | ||
| Theorem | dmqseq 39059 | Equality theorem for domain quotient. (Contributed by Peter Mazsa, 17-Apr-2019.) |
| ⊢ (𝑅 = 𝑆 → (dom 𝑅 / 𝑅) = (dom 𝑆 / 𝑆)) | ||
| Theorem | dmqseqi 39060 | Equality theorem for domain quotient, inference version. (Contributed by Peter Mazsa, 26-Sep-2021.) |
| ⊢ 𝑅 = 𝑆 ⇒ ⊢ (dom 𝑅 / 𝑅) = (dom 𝑆 / 𝑆) | ||
| Theorem | dmqseqd 39061 | Equality theorem for domain quotient set, deduction version. (Contributed by Peter Mazsa, 23-Apr-2021.) |
| ⊢ (𝜑 → 𝑅 = 𝑆) ⇒ ⊢ (𝜑 → (dom 𝑅 / 𝑅) = (dom 𝑆 / 𝑆)) | ||
| Theorem | dmqseqeq1 39062 | Equality theorem for domain quotient. (Contributed by Peter Mazsa, 17-Apr-2019.) |
| ⊢ (𝑅 = 𝑆 → ((dom 𝑅 / 𝑅) = 𝐴 ↔ (dom 𝑆 / 𝑆) = 𝐴)) | ||
| Theorem | dmqseqeq1i 39063 | Equality theorem for domain quotient, inference version. (Contributed by Peter Mazsa, 26-Sep-2021.) |
| ⊢ 𝑅 = 𝑆 ⇒ ⊢ ((dom 𝑅 / 𝑅) = 𝐴 ↔ (dom 𝑆 / 𝑆) = 𝐴) | ||
| Theorem | dmqseqeq1d 39064 | Equality theorem for domain quotient set, deduction version. (Contributed by Peter Mazsa, 26-Sep-2021.) |
| ⊢ (𝜑 → 𝑅 = 𝑆) ⇒ ⊢ (𝜑 → ((dom 𝑅 / 𝑅) = 𝐴 ↔ (dom 𝑆 / 𝑆) = 𝐴)) | ||
| Theorem | brdmqss 39065 | The domain quotient binary relation. (Contributed by Peter Mazsa, 17-Apr-2019.) |
| ⊢ ((𝐴 ∈ 𝑉 ∧ 𝑅 ∈ 𝑊) → (𝑅 DomainQss 𝐴 ↔ (dom 𝑅 / 𝑅) = 𝐴)) | ||
| Theorem | brdmqssqs 39066 | If 𝐴 and 𝑅 are sets, the domain quotient binary relation and the domain quotient predicate are the same. (Contributed by Peter Mazsa, 14-Aug-2021.) |
| ⊢ ((𝐴 ∈ 𝑉 ∧ 𝑅 ∈ 𝑊) → (𝑅 DomainQss 𝐴 ↔ 𝑅 DomainQs 𝐴)) | ||
| Theorem | n0eldmqs 39067 | The empty set is not an element of a domain quotient. (Contributed by Peter Mazsa, 2-Mar-2018.) |
| ⊢ ¬ ∅ ∈ (dom 𝑅 / 𝑅) | ||
| Theorem | qseq 39068* |
The quotient set equal to a class.
This theorem is used when a class 𝐴 is identified with a quotient (dom 𝑅 / 𝑅). In such a situation, every element 𝑢 ∈ 𝐴 is an 𝑅-coset [𝑣]𝑅 for some 𝑣 ∈ dom 𝑅, but there is no requirement that the "witness" 𝑣 be equal to its own block [𝑣]𝑅. 𝐴 is a set of blocks (equivalence classes), not a set of raw witnesses. In particular, when (dom 𝑅 / 𝑅) = 𝐴 is read together with a partition hypothesis 𝑅 Part 𝐴 (defined as dfpart2 39207), 𝐴 is being treated as the set of blocks [𝑣]𝑅; it does not assert any fixed-point condition 𝑣 = [𝑣]𝑅 such as would arise from the mistaken reading 𝑢 ∈ 𝐴 ↔ 𝑢 = [𝑢]𝑅. Cf. dmqsblocks 39302. (Contributed by Peter Mazsa, 19-Oct-2018.) |
| ⊢ ((𝐵 / 𝑅) = 𝐴 ↔ ∀𝑢(𝑢 ∈ 𝐴 ↔ ∃𝑣 ∈ 𝐵 𝑢 = [𝑣]𝑅)) | ||
| Theorem | n0eldmqseq 39069 | The empty set is not an element of a domain quotient. (Contributed by Peter Mazsa, 3-Nov-2018.) |
| ⊢ ((dom 𝑅 / 𝑅) = 𝐴 → ¬ ∅ ∈ 𝐴) | ||
| Theorem | n0elim 39070 | Implication of that the empty set is not an element of a class. (Contributed by Peter Mazsa, 30-Dec-2024.) |
| ⊢ (¬ ∅ ∈ 𝐴 → (dom (◡ E ↾ 𝐴) / (◡ E ↾ 𝐴)) = 𝐴) | ||
| Theorem | n0el3 39071 | Two ways of expressing that the empty set is not an element of a class. (Contributed by Peter Mazsa, 27-May-2021.) |
| ⊢ (¬ ∅ ∈ 𝐴 ↔ (dom (◡ E ↾ 𝐴) / (◡ E ↾ 𝐴)) = 𝐴) | ||
| Theorem | cnvepresdmqss 39072 | The domain quotient binary relation of the restricted converse epsilon relation is equivalent to the negated elementhood of the empty set in the restriction. (Contributed by Peter Mazsa, 14-Aug-2021.) |
| ⊢ (𝐴 ∈ 𝑉 → ((◡ E ↾ 𝐴) DomainQss 𝐴 ↔ ¬ ∅ ∈ 𝐴)) | ||
| Theorem | cnvepresdmqs 39073 | The domain quotient predicate for the restricted converse epsilon relation is equivalent to the negated elementhood of the empty set in the restriction. (Contributed by Peter Mazsa, 14-Aug-2021.) |
| ⊢ ((◡ E ↾ 𝐴) DomainQs 𝐴 ↔ ¬ ∅ ∈ 𝐴) | ||
| Theorem | unidmqs 39074 | The range of a relation is equal to the union of the domain quotient. (Contributed by Peter Mazsa, 13-Oct-2018.) |
| ⊢ (𝑅 ∈ 𝑉 → (Rel 𝑅 → ∪ (dom 𝑅 / 𝑅) = ran 𝑅)) | ||
| Theorem | unidmqseq 39075 | The union of the domain quotient of a relation is equal to the class 𝐴 if and only if the range is equal to it as well. (Contributed by Peter Mazsa, 21-Apr-2019.) (Revised by Peter Mazsa, 28-Dec-2021.) |
| ⊢ (𝑅 ∈ 𝑉 → (Rel 𝑅 → (∪ (dom 𝑅 / 𝑅) = 𝐴 ↔ ran 𝑅 = 𝐴))) | ||
| Theorem | dmqseqim 39076 | If the domain quotient of a relation is equal to the class 𝐴, then the range of the relation is the union of the class. (Contributed by Peter Mazsa, 29-Dec-2021.) |
| ⊢ (𝑅 ∈ 𝑉 → (Rel 𝑅 → ((dom 𝑅 / 𝑅) = 𝐴 → ran 𝑅 = ∪ 𝐴))) | ||
| Theorem | dmqseqim2 39077 | Lemma for erimeq2 39098. (Contributed by Peter Mazsa, 29-Dec-2021.) |
| ⊢ (𝑅 ∈ 𝑉 → (Rel 𝑅 → ((dom 𝑅 / 𝑅) = 𝐴 → (𝐵 ∈ ran 𝑅 ↔ 𝐵 ∈ ∪ 𝐴)))) | ||
| Theorem | releldmqs 39078* | Elementhood in the domain quotient of a relation. (Contributed by Peter Mazsa, 24-Apr-2021.) |
| ⊢ (𝐴 ∈ 𝑉 → (Rel 𝑅 → (𝐴 ∈ (dom 𝑅 / 𝑅) ↔ ∃𝑢 ∈ dom 𝑅∃𝑥 ∈ [ 𝑢]𝑅𝐴 = [𝑢]𝑅))) | ||
| Theorem | eldmqs1cossres 39079* | Elementhood in the domain quotient of the class of cosets by a restriction. (Contributed by Peter Mazsa, 4-May-2019.) |
| ⊢ (𝐵 ∈ 𝑉 → (𝐵 ∈ (dom ≀ (𝑅 ↾ 𝐴) / ≀ (𝑅 ↾ 𝐴)) ↔ ∃𝑢 ∈ 𝐴 ∃𝑥 ∈ [ 𝑢]𝑅𝐵 = [𝑥] ≀ (𝑅 ↾ 𝐴))) | ||
| Theorem | releldmqscoss 39080* | Elementhood in the domain quotient of the class of cosets by a relation. (Contributed by Peter Mazsa, 23-Apr-2021.) |
| ⊢ (𝐴 ∈ 𝑉 → (Rel 𝑅 → (𝐴 ∈ (dom ≀ 𝑅 / ≀ 𝑅) ↔ ∃𝑢 ∈ dom 𝑅∃𝑥 ∈ [ 𝑢]𝑅𝐴 = [𝑥] ≀ 𝑅))) | ||
| Theorem | dmqscoelseq 39081 | Two ways to express the equality of the domain quotient of the coelements on the class 𝐴 with the class 𝐴. (Contributed by Peter Mazsa, 26-Sep-2021.) |
| ⊢ ((dom ∼ 𝐴 / ∼ 𝐴) = 𝐴 ↔ (∪ 𝐴 / ∼ 𝐴) = 𝐴) | ||
| Theorem | dmqs1cosscnvepreseq 39082 | Two ways to express the equality of the domain quotient of the coelements on the class 𝐴 with the class 𝐴. (Contributed by Peter Mazsa, 26-Sep-2021.) |
| ⊢ ((dom ≀ (◡ E ↾ 𝐴) / ≀ (◡ E ↾ 𝐴)) = 𝐴 ↔ (∪ 𝐴 / ∼ 𝐴) = 𝐴) | ||
| Definition | df-ers 39083 |
Define the class of equivalence relations on domain quotients (or: domain
quotients restricted to equivalence relations).
The present definition of equivalence relation in set.mm df-er 8636 "is not standard", "somewhat cryptic", has no constant 0-ary class and does not follow the traditional transparent reflexive-symmetric-transitive relation way of definition of equivalence. Definitions df-eqvrels 39003, dfeqvrels2 39007, dfeqvrels3 39008 and df-eqvrel 39004, dfeqvrel2 39009, dfeqvrel3 39010 are fully transparent in this regard. However, they lack the domain component (dom 𝑅 = 𝐴) of the present df-er 8636. While we acknowledge the need of a domain component, the present df-er 8636 definition does not utilize the results revealed by the new theorems in the Partition-Equivalence Theorem part below (like pets 39301 and pet 39300). From those theorems follows that the natural domain of equivalence relations is not 𝑅Domain𝐴 (i.e. dom 𝑅 = 𝐴 see brdomaing 36131), but 𝑅 DomainQss 𝐴 (i.e. (dom 𝑅 / 𝑅) = 𝐴, see brdmqss 39065), see erimeq 39099 vs. prter3 39342. While I'm sure we need both equivalence relation df-eqvrels 39003 and equivalence relation on domain quotient df-ers 39083, I'm not sure whether we need a third equivalence relation concept with the present dom 𝑅 = 𝐴 component as well: this needs further investigation. As a default I suppose that these two concepts df-eqvrels 39003 and df-ers 39083 are enough and named the predicate version of the one on domain quotient as the alternate version df-erALTV 39084 of the present df-er 8636. (Contributed by Peter Mazsa, 26-Jun-2021.) |
| ⊢ Ers = ( DomainQss ↾ EqvRels ) | ||
| Definition | df-erALTV 39084 | Equivalence relation with natural domain predicate, see also the comment of df-ers 39083. Alternate definition is dferALTV2 39088. Binary equivalence relation with natural domain and the equivalence relation with natural domain predicate are the same when 𝐴 and 𝑅 are sets, see brerser 39097. (Contributed by Peter Mazsa, 12-Aug-2021.) |
| ⊢ (𝑅 ErALTV 𝐴 ↔ ( EqvRel 𝑅 ∧ 𝑅 DomainQs 𝐴)) | ||
| Definition | df-comembers 39085 | Define the class of comember equivalence relations on their domain quotients. (Contributed by Peter Mazsa, 28-Nov-2022.) (Revised by Peter Mazsa, 24-Jul-2023.) |
| ⊢ CoMembErs = {𝑎 ∣ ≀ (◡ E ↾ 𝑎) Ers 𝑎} | ||
| Definition | df-comember 39086 |
Define the comember equivalence relation on the class 𝐴 (or, the
restricted coelement equivalence relation on its domain quotient 𝐴.)
Alternate definitions are dfcomember2 39093 and dfcomember3 39094.
Later on, in an application of set theory I make a distinction between the default elementhood concept and a special membership concept: membership equivalence relation will be an integral part of that membership concept. (Contributed by Peter Mazsa, 26-Jun-2021.) (Revised by Peter Mazsa, 28-Nov-2022.) |
| ⊢ ( CoMembEr 𝐴 ↔ ≀ (◡ E ↾ 𝐴) ErALTV 𝐴) | ||
| Theorem | brers 39087 | Binary equivalence relation with natural domain, see the comment of df-ers 39083. (Contributed by Peter Mazsa, 23-Jul-2021.) |
| ⊢ (𝐴 ∈ 𝑉 → (𝑅 Ers 𝐴 ↔ (𝑅 ∈ EqvRels ∧ 𝑅 DomainQss 𝐴))) | ||
| Theorem | dferALTV2 39088 | Equivalence relation with natural domain predicate, see the comment of df-ers 39083. (Contributed by Peter Mazsa, 26-Jun-2021.) (Revised by Peter Mazsa, 30-Aug-2021.) |
| ⊢ (𝑅 ErALTV 𝐴 ↔ ( EqvRel 𝑅 ∧ (dom 𝑅 / 𝑅) = 𝐴)) | ||
| Theorem | erALTVeq1 39089 | Equality theorem for equivalence relation on domain quotient. (Contributed by Peter Mazsa, 25-Sep-2021.) |
| ⊢ (𝑅 = 𝑆 → (𝑅 ErALTV 𝐴 ↔ 𝑆 ErALTV 𝐴)) | ||
| Theorem | erALTVeq1i 39090 | Equality theorem for equivalence relation on domain quotient, inference version. (Contributed by Peter Mazsa, 25-Sep-2021.) |
| ⊢ 𝑅 = 𝑆 ⇒ ⊢ (𝑅 ErALTV 𝐴 ↔ 𝑆 ErALTV 𝐴) | ||
| Theorem | erALTVeq1d 39091 | Equality theorem for equivalence relation on domain quotient, deduction version. (Contributed by Peter Mazsa, 25-Sep-2021.) |
| ⊢ (𝜑 → 𝑅 = 𝑆) ⇒ ⊢ (𝜑 → (𝑅 ErALTV 𝐴 ↔ 𝑆 ErALTV 𝐴)) | ||
| Theorem | dfcomember 39092 | Alternate definition of the comember equivalence relation. (Contributed by Peter Mazsa, 28-Nov-2022.) |
| ⊢ ( CoMembEr 𝐴 ↔ ∼ 𝐴 ErALTV 𝐴) | ||
| Theorem | dfcomember2 39093 | Alternate definition of the comember equivalence relation. (Contributed by Peter Mazsa, 25-Sep-2021.) |
| ⊢ ( CoMembEr 𝐴 ↔ ( EqvRel ∼ 𝐴 ∧ (dom ∼ 𝐴 / ∼ 𝐴) = 𝐴)) | ||
| Theorem | dfcomember3 39094 | Alternate definition of the comember equivalence relation. (Contributed by Peter Mazsa, 26-Sep-2021.) (Revised by Peter Mazsa, 17-Jul-2023.) |
| ⊢ ( CoMembEr 𝐴 ↔ ( CoElEqvRel 𝐴 ∧ (∪ 𝐴 / ∼ 𝐴) = 𝐴)) | ||
| Theorem | eqvreldmqs 39095 | Two ways to express comember equivalence relation on its domain quotient. (Contributed by Peter Mazsa, 26-Sep-2021.) (Revised by Peter Mazsa, 17-Jul-2023.) |
| ⊢ (( EqvRel ≀ (◡ E ↾ 𝐴) ∧ (dom ≀ (◡ E ↾ 𝐴) / ≀ (◡ E ↾ 𝐴)) = 𝐴) ↔ ( CoElEqvRel 𝐴 ∧ (∪ 𝐴 / ∼ 𝐴) = 𝐴)) | ||
| Theorem | eqvreldmqs2 39096 | Two ways to express comember equivalence relation on its domain quotient. (Contributed by Peter Mazsa, 30-Dec-2024.) |
| ⊢ (( EqvRel ≀ (◡ E ↾ 𝐴) ∧ (dom ≀ (◡ E ↾ 𝐴) / ≀ (◡ E ↾ 𝐴)) = 𝐴) ↔ ( EqvRel ∼ 𝐴 ∧ (∪ 𝐴 / ∼ 𝐴) = 𝐴)) | ||
| Theorem | brerser 39097 | Binary equivalence relation with natural domain and the equivalence relation with natural domain predicate are the same when 𝐴 and 𝑅 are sets. (Contributed by Peter Mazsa, 25-Aug-2021.) |
| ⊢ ((𝐴 ∈ 𝑉 ∧ 𝑅 ∈ 𝑊) → (𝑅 Ers 𝐴 ↔ 𝑅 ErALTV 𝐴)) | ||
| Theorem | erimeq2 39098 | Equivalence relation on its natural domain implies that the class of coelements on the domain is equal to the relation (this is prter3 39342 in a more convenient form , see also erimeq 39099). (Contributed by Rodolfo Medina, 19-Oct-2010.) (Proof shortened by Mario Carneiro, 12-Aug-2015.) (Revised by Peter Mazsa, 29-Dec-2021.) |
| ⊢ (𝑅 ∈ 𝑉 → (( EqvRel 𝑅 ∧ (dom 𝑅 / 𝑅) = 𝐴) → ∼ 𝐴 = 𝑅)) | ||
| Theorem | erimeq 39099 | Equivalence relation on its natural domain implies that the class of coelements on the domain is equal to the relation (this is the most convenient form of prter3 39342 and erimeq2 39098). (Contributed by Peter Mazsa, 7-Oct-2021.) (Revised by Peter Mazsa, 29-Dec-2021.) |
| ⊢ (𝑅 ∈ 𝑉 → (𝑅 ErALTV 𝐴 → ∼ 𝐴 = 𝑅)) | ||
| Definition | df-funss 39100 | Define the class of all function sets (but not necessarily function relations, cf. df-funsALTV 39101). It is used only by df-funsALTV 39101. (Contributed by Peter Mazsa, 17-Jul-2021.) |
| ⊢ Funss = {𝑥 ∣ ≀ 𝑥 ∈ CnvRefRels } | ||
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