| Metamath
Proof Explorer Theorem List (p. 337 of 497) | < Previous Next > | |
| Bad symbols? Try the
GIF version. |
||
|
Mirrors > Metamath Home Page > MPE Home Page > Theorem List Contents > Recent Proofs This page: Page List |
||
| Color key: | (1-30845) |
(30846-32368) |
(32369-49617) |
| Type | Label | Description |
|---|---|---|
| Statement | ||
| Theorem | matdim 33601 | Dimension of the space of square matrices. (Contributed by Thierry Arnoux, 20-May-2023.) |
| ⊢ 𝐴 = (𝐼 Mat 𝑅) & ⊢ 𝑁 = (♯‘𝐼) ⇒ ⊢ ((𝐼 ∈ Fin ∧ 𝑅 ∈ DivRing) → (dim‘𝐴) = (𝑁 · 𝑁)) | ||
| Theorem | lbslsat 33602 | A nonzero vector 𝑋 is a basis of a line spanned by the singleton 𝑋. Spans of nonzero singletons are sometimes called "atoms", see df-lsatoms 38940 and for example lsatlspsn 38957. (Contributed by Thierry Arnoux, 20-May-2023.) |
| ⊢ 𝑉 = (Base‘𝑊) & ⊢ 𝑁 = (LSpan‘𝑊) & ⊢ 0 = (0g‘𝑊) & ⊢ 𝑌 = (𝑊 ↾s (𝑁‘{𝑋})) ⇒ ⊢ ((𝑊 ∈ LVec ∧ 𝑋 ∈ 𝑉 ∧ 𝑋 ≠ 0 ) → {𝑋} ∈ (LBasis‘𝑌)) | ||
| Theorem | lsatdim 33603 | A line, spanned by a nonzero singleton, has dimension 1. (Contributed by Thierry Arnoux, 20-May-2023.) |
| ⊢ 𝑉 = (Base‘𝑊) & ⊢ 𝑁 = (LSpan‘𝑊) & ⊢ 0 = (0g‘𝑊) & ⊢ 𝑌 = (𝑊 ↾s (𝑁‘{𝑋})) ⇒ ⊢ ((𝑊 ∈ LVec ∧ 𝑋 ∈ 𝑉 ∧ 𝑋 ≠ 0 ) → (dim‘𝑌) = 1) | ||
| Theorem | drngdimgt0 33604 | The dimension of a vector space that is also a division ring is greater than zero. (Contributed by Thierry Arnoux, 29-Jul-2023.) |
| ⊢ ((𝐹 ∈ LVec ∧ 𝐹 ∈ DivRing) → 0 < (dim‘𝐹)) | ||
| Theorem | lmhmlvec2 33605 | A homomorphism of left vector spaces has a left vector space as codomain. (Contributed by Thierry Arnoux, 7-May-2023.) |
| ⊢ ((𝑉 ∈ LVec ∧ 𝐹 ∈ (𝑉 LMHom 𝑈)) → 𝑈 ∈ LVec) | ||
| Theorem | kerlmhm 33606 | The kernel of a vector space homomorphism is a vector space itself. (Contributed by Thierry Arnoux, 7-May-2023.) |
| ⊢ 0 = (0g‘𝑈) & ⊢ 𝐾 = (𝑉 ↾s (◡𝐹 “ { 0 })) ⇒ ⊢ ((𝑉 ∈ LVec ∧ 𝐹 ∈ (𝑉 LMHom 𝑈)) → 𝐾 ∈ LVec) | ||
| Theorem | imlmhm 33607 | The image of a vector space homomorphism is a vector space itself. (Contributed by Thierry Arnoux, 7-May-2023.) |
| ⊢ 𝐼 = (𝑈 ↾s ran 𝐹) ⇒ ⊢ ((𝑉 ∈ LVec ∧ 𝐹 ∈ (𝑉 LMHom 𝑈)) → 𝐼 ∈ LVec) | ||
| Theorem | ply1degltdimlem 33608* | Lemma for ply1degltdim 33609. (Contributed by Thierry Arnoux, 20-Feb-2025.) |
| ⊢ 𝑃 = (Poly1‘𝑅) & ⊢ 𝐷 = (deg1‘𝑅) & ⊢ 𝑆 = (◡𝐷 “ (-∞[,)𝑁)) & ⊢ (𝜑 → 𝑁 ∈ ℕ0) & ⊢ (𝜑 → 𝑅 ∈ DivRing) & ⊢ 𝐸 = (𝑃 ↾s 𝑆) & ⊢ 𝐹 = (𝑛 ∈ (0..^𝑁) ↦ (𝑛(.g‘(mulGrp‘𝑃))(var1‘𝑅))) ⇒ ⊢ (𝜑 → ran 𝐹 ∈ (LBasis‘𝐸)) | ||
| Theorem | ply1degltdim 33609 | The space 𝑆 of the univariate polynomials of degree less than 𝑁 has dimension 𝑁. (Contributed by Thierry Arnoux, 20-Feb-2025.) |
| ⊢ 𝑃 = (Poly1‘𝑅) & ⊢ 𝐷 = (deg1‘𝑅) & ⊢ 𝑆 = (◡𝐷 “ (-∞[,)𝑁)) & ⊢ (𝜑 → 𝑁 ∈ ℕ0) & ⊢ (𝜑 → 𝑅 ∈ DivRing) & ⊢ 𝐸 = (𝑃 ↾s 𝑆) ⇒ ⊢ (𝜑 → (dim‘𝐸) = 𝑁) | ||
| Theorem | lindsunlem 33610 | Lemma for lindsun 33611. (Contributed by Thierry Arnoux, 9-May-2023.) |
| ⊢ 𝑁 = (LSpan‘𝑊) & ⊢ 0 = (0g‘𝑊) & ⊢ (𝜑 → 𝑊 ∈ LVec) & ⊢ (𝜑 → 𝑈 ∈ (LIndS‘𝑊)) & ⊢ (𝜑 → 𝑉 ∈ (LIndS‘𝑊)) & ⊢ (𝜑 → ((𝑁‘𝑈) ∩ (𝑁‘𝑉)) = { 0 }) & ⊢ 𝑂 = (0g‘(Scalar‘𝑊)) & ⊢ 𝐹 = (Base‘(Scalar‘𝑊)) & ⊢ (𝜑 → 𝐶 ∈ 𝑈) & ⊢ (𝜑 → 𝐾 ∈ (𝐹 ∖ {𝑂})) & ⊢ (𝜑 → (𝐾( ·𝑠 ‘𝑊)𝐶) ∈ (𝑁‘((𝑈 ∪ 𝑉) ∖ {𝐶}))) ⇒ ⊢ (𝜑 → ⊥) | ||
| Theorem | lindsun 33611 | Condition for the union of two independent sets to be an independent set. (Contributed by Thierry Arnoux, 9-May-2023.) |
| ⊢ 𝑁 = (LSpan‘𝑊) & ⊢ 0 = (0g‘𝑊) & ⊢ (𝜑 → 𝑊 ∈ LVec) & ⊢ (𝜑 → 𝑈 ∈ (LIndS‘𝑊)) & ⊢ (𝜑 → 𝑉 ∈ (LIndS‘𝑊)) & ⊢ (𝜑 → ((𝑁‘𝑈) ∩ (𝑁‘𝑉)) = { 0 }) ⇒ ⊢ (𝜑 → (𝑈 ∪ 𝑉) ∈ (LIndS‘𝑊)) | ||
| Theorem | lbsdiflsp0 33612 | The linear spans of two disjunct independent sets only have a trivial intersection. This can be seen as the opposite direction of lindsun 33611. (Contributed by Thierry Arnoux, 17-May-2023.) |
| ⊢ 𝐽 = (LBasis‘𝑊) & ⊢ 𝑁 = (LSpan‘𝑊) & ⊢ 0 = (0g‘𝑊) ⇒ ⊢ ((𝑊 ∈ LVec ∧ 𝐵 ∈ 𝐽 ∧ 𝑉 ⊆ 𝐵) → ((𝑁‘(𝐵 ∖ 𝑉)) ∩ (𝑁‘𝑉)) = { 0 }) | ||
| Theorem | dimkerim 33613 | Given a linear map 𝐹 between vector spaces 𝑉 and 𝑈, the dimension of the vector space 𝑉 is the sum of the dimension of 𝐹 's kernel and the dimension of 𝐹's image. Second part of theorem 5.3 in [Lang] p. 141 This can also be described as the Rank-nullity theorem, (dim‘𝐼) being the rank of 𝐹 (the dimension of its image), and (dim‘𝐾) its nullity (the dimension of its kernel). (Contributed by Thierry Arnoux, 17-May-2023.) |
| ⊢ 0 = (0g‘𝑈) & ⊢ 𝐾 = (𝑉 ↾s (◡𝐹 “ { 0 })) & ⊢ 𝐼 = (𝑈 ↾s ran 𝐹) ⇒ ⊢ ((𝑉 ∈ LVec ∧ 𝐹 ∈ (𝑉 LMHom 𝑈)) → (dim‘𝑉) = ((dim‘𝐾) +𝑒 (dim‘𝐼))) | ||
| Theorem | qusdimsum 33614 | Let 𝑊 be a vector space, and let 𝑋 be a subspace. Then the dimension of 𝑊 is the sum of the dimension of 𝑋 and the dimension of the quotient space of 𝑋. First part of theorem 5.3 in [Lang] p. 141. (Contributed by Thierry Arnoux, 20-May-2023.) |
| ⊢ 𝑋 = (𝑊 ↾s 𝑈) & ⊢ 𝑌 = (𝑊 /s (𝑊 ~QG 𝑈)) ⇒ ⊢ ((𝑊 ∈ LVec ∧ 𝑈 ∈ (LSubSp‘𝑊)) → (dim‘𝑊) = ((dim‘𝑋) +𝑒 (dim‘𝑌))) | ||
| Theorem | fedgmullem1 33615* | Lemma for fedgmul 33617. (Contributed by Thierry Arnoux, 20-Jul-2023.) |
| ⊢ 𝐴 = ((subringAlg ‘𝐸)‘𝑉) & ⊢ 𝐵 = ((subringAlg ‘𝐸)‘𝑈) & ⊢ 𝐶 = ((subringAlg ‘𝐹)‘𝑉) & ⊢ 𝐹 = (𝐸 ↾s 𝑈) & ⊢ 𝐾 = (𝐸 ↾s 𝑉) & ⊢ (𝜑 → 𝐸 ∈ DivRing) & ⊢ (𝜑 → 𝐹 ∈ DivRing) & ⊢ (𝜑 → 𝐾 ∈ DivRing) & ⊢ (𝜑 → 𝑈 ∈ (SubRing‘𝐸)) & ⊢ (𝜑 → 𝑉 ∈ (SubRing‘𝐹)) & ⊢ 𝐷 = (𝑗 ∈ 𝑌, 𝑖 ∈ 𝑋 ↦ (𝑖(.r‘𝐸)𝑗)) & ⊢ 𝐻 = (𝑗 ∈ 𝑌, 𝑖 ∈ 𝑋 ↦ ((𝐺‘𝑗)‘𝑖)) & ⊢ (𝜑 → 𝑋 ∈ (LBasis‘𝐶)) & ⊢ (𝜑 → 𝑌 ∈ (LBasis‘𝐵)) & ⊢ (𝜑 → 𝑍 ∈ (Base‘𝐴)) & ⊢ (𝜑 → 𝐿:𝑌⟶(Base‘(Scalar‘𝐵))) & ⊢ (𝜑 → 𝐿 finSupp (0g‘(Scalar‘𝐵))) & ⊢ (𝜑 → 𝑍 = (𝐵 Σg (𝑗 ∈ 𝑌 ↦ ((𝐿‘𝑗)( ·𝑠 ‘𝐵)𝑗)))) & ⊢ (𝜑 → 𝐺:𝑌⟶((Base‘(Scalar‘𝐶)) ↑m 𝑋)) & ⊢ ((𝜑 ∧ 𝑗 ∈ 𝑌) → (𝐺‘𝑗) finSupp (0g‘(Scalar‘𝐶))) & ⊢ ((𝜑 ∧ 𝑗 ∈ 𝑌) → (𝐿‘𝑗) = (𝐶 Σg (𝑖 ∈ 𝑋 ↦ (((𝐺‘𝑗)‘𝑖)( ·𝑠 ‘𝐶)𝑖)))) ⇒ ⊢ (𝜑 → (𝐻 finSupp (0g‘(Scalar‘𝐴)) ∧ 𝑍 = (𝐴 Σg (𝐻 ∘f ( ·𝑠 ‘𝐴)𝐷)))) | ||
| Theorem | fedgmullem2 33616* | Lemma for fedgmul 33617. (Contributed by Thierry Arnoux, 20-Jul-2023.) |
| ⊢ 𝐴 = ((subringAlg ‘𝐸)‘𝑉) & ⊢ 𝐵 = ((subringAlg ‘𝐸)‘𝑈) & ⊢ 𝐶 = ((subringAlg ‘𝐹)‘𝑉) & ⊢ 𝐹 = (𝐸 ↾s 𝑈) & ⊢ 𝐾 = (𝐸 ↾s 𝑉) & ⊢ (𝜑 → 𝐸 ∈ DivRing) & ⊢ (𝜑 → 𝐹 ∈ DivRing) & ⊢ (𝜑 → 𝐾 ∈ DivRing) & ⊢ (𝜑 → 𝑈 ∈ (SubRing‘𝐸)) & ⊢ (𝜑 → 𝑉 ∈ (SubRing‘𝐹)) & ⊢ 𝐷 = (𝑗 ∈ 𝑌, 𝑖 ∈ 𝑋 ↦ (𝑖(.r‘𝐸)𝑗)) & ⊢ 𝐻 = (𝑗 ∈ 𝑌, 𝑖 ∈ 𝑋 ↦ ((𝐺‘𝑗)‘𝑖)) & ⊢ (𝜑 → 𝑋 ∈ (LBasis‘𝐶)) & ⊢ (𝜑 → 𝑌 ∈ (LBasis‘𝐵)) & ⊢ (𝜑 → 𝑊 ∈ (Base‘((Scalar‘𝐴) freeLMod (𝑌 × 𝑋)))) & ⊢ (𝜑 → (𝐴 Σg (𝑊 ∘f ( ·𝑠 ‘𝐴)𝐷)) = (0g‘𝐴)) ⇒ ⊢ (𝜑 → 𝑊 = ((𝑌 × 𝑋) × {(0g‘(Scalar‘𝐴))})) | ||
| Theorem | fedgmul 33617 | The multiplicativity formula for degrees of field extensions. Given 𝐸 a field extension of 𝐹, itself a field extension of 𝐾, we have [𝐸:𝐾] = [𝐸:𝐹][𝐹:𝐾]. Proposition 1.2 of [Lang], p. 224. Here (dim‘𝐴) is the degree of the extension 𝐸 of 𝐾, (dim‘𝐵) is the degree of the extension 𝐸 of 𝐹, and (dim‘𝐶) is the degree of the extension 𝐹 of 𝐾. This proof is valid for infinite dimensions, and is actually valid for division ring extensions, not just field extensions. (Contributed by Thierry Arnoux, 25-Jul-2023.) |
| ⊢ 𝐴 = ((subringAlg ‘𝐸)‘𝑉) & ⊢ 𝐵 = ((subringAlg ‘𝐸)‘𝑈) & ⊢ 𝐶 = ((subringAlg ‘𝐹)‘𝑉) & ⊢ 𝐹 = (𝐸 ↾s 𝑈) & ⊢ 𝐾 = (𝐸 ↾s 𝑉) & ⊢ (𝜑 → 𝐸 ∈ DivRing) & ⊢ (𝜑 → 𝐹 ∈ DivRing) & ⊢ (𝜑 → 𝐾 ∈ DivRing) & ⊢ (𝜑 → 𝑈 ∈ (SubRing‘𝐸)) & ⊢ (𝜑 → 𝑉 ∈ (SubRing‘𝐹)) ⇒ ⊢ (𝜑 → (dim‘𝐴) = ((dim‘𝐵) ·e (dim‘𝐶))) | ||
| Theorem | dimlssid 33618 | If the dimension of a linear subspace 𝐿 is the dimension of the whole vector space 𝐸, then 𝐿 is the whole space. (Contributed by Thierry Arnoux, 3-Aug-2025.) |
| ⊢ 𝐵 = (Base‘𝐸) & ⊢ (𝜑 → 𝐸 ∈ LVec) & ⊢ (𝜑 → (dim‘𝐸) ∈ ℕ0) & ⊢ (𝜑 → 𝐿 ∈ (LSubSp‘𝐸)) & ⊢ (𝜑 → (dim‘(𝐸 ↾s 𝐿)) = (dim‘𝐸)) ⇒ ⊢ (𝜑 → 𝐿 = 𝐵) | ||
| Theorem | lvecendof1f1o 33619 | If an endomorphism 𝑈 of a vector space 𝐸 of finite dimension is injective, then it is bijective. Item (b) of Corollary of Proposition 9 in [BourbakiAlg1] p. 298 . (Contributed by Thierry Arnoux, 3-Aug-2025.) |
| ⊢ 𝐵 = (Base‘𝐸) & ⊢ (𝜑 → 𝐸 ∈ LVec) & ⊢ (𝜑 → (dim‘𝐸) ∈ ℕ0) & ⊢ (𝜑 → 𝑈 ∈ (𝐸 LMHom 𝐸)) & ⊢ (𝜑 → 𝑈:𝐵–1-1→𝐵) ⇒ ⊢ (𝜑 → 𝑈:𝐵–1-1-onto→𝐵) | ||
| Theorem | lactlmhm 33620* | In an associative algebra 𝐴, left-multiplication by a fixed element of the algebra is a module homomorphism, analogous to ringlghm 20270. (Contributed by Thierry Arnoux, 3-Aug-2025.) |
| ⊢ 𝐵 = (Base‘𝐴) & ⊢ · = (.r‘𝐴) & ⊢ 𝐹 = (𝑥 ∈ 𝐵 ↦ (𝐶 · 𝑥)) & ⊢ (𝜑 → 𝐴 ∈ AssAlg) & ⊢ (𝜑 → 𝐶 ∈ 𝐵) ⇒ ⊢ (𝜑 → 𝐹 ∈ (𝐴 LMHom 𝐴)) | ||
| Theorem | assalactf1o 33621* | In an associative algebra 𝐴, left-multiplication by a fixed element of the algebra is bijective. See also lactlmhm 33620. (Contributed by Thierry Arnoux, 3-Aug-2025.) |
| ⊢ 𝐵 = (Base‘𝐴) & ⊢ · = (.r‘𝐴) & ⊢ 𝐹 = (𝑥 ∈ 𝐵 ↦ (𝐶 · 𝑥)) & ⊢ (𝜑 → 𝐴 ∈ AssAlg) & ⊢ 𝐸 = (RLReg‘𝐴) & ⊢ 𝐾 = (Scalar‘𝐴) & ⊢ (𝜑 → 𝐾 ∈ DivRing) & ⊢ (𝜑 → (dim‘𝐴) ∈ ℕ0) & ⊢ (𝜑 → 𝐶 ∈ 𝐸) ⇒ ⊢ (𝜑 → 𝐹:𝐵–1-1-onto→𝐵) | ||
| Theorem | assarrginv 33622 | If an element 𝑋 of an associative algebra 𝐴 over a division ring 𝐾 is regular, then it is a unit. Proposition 2. in Chapter 5. of [BourbakiAlg2] p. 113. (Contributed by Thierry Arnoux, 3-Aug-2025.) |
| ⊢ 𝐸 = (RLReg‘𝐴) & ⊢ 𝑈 = (Unit‘𝐴) & ⊢ 𝐾 = (Scalar‘𝐴) & ⊢ (𝜑 → 𝐴 ∈ AssAlg) & ⊢ (𝜑 → 𝐾 ∈ DivRing) & ⊢ (𝜑 → (dim‘𝐴) ∈ ℕ0) & ⊢ (𝜑 → 𝑋 ∈ 𝐸) ⇒ ⊢ (𝜑 → 𝑋 ∈ 𝑈) | ||
| Theorem | assafld 33623 | If an algebra 𝐴 of finite degree over a division ring 𝐾 is an integral domain, then it is a field. Corollary of Proposition 2. in Chapter 5. of [BourbakiAlg2] p. 113. (Contributed by Thierry Arnoux, 3-Aug-2025.) |
| ⊢ 𝐾 = (Scalar‘𝐴) & ⊢ (𝜑 → 𝐴 ∈ AssAlg) & ⊢ (𝜑 → 𝐴 ∈ IDomn) & ⊢ (𝜑 → 𝐾 ∈ DivRing) & ⊢ (𝜑 → (dim‘𝐴) ∈ ℕ0) ⇒ ⊢ (𝜑 → 𝐴 ∈ Field) | ||
| Syntax | cfldext 33624 | Syntax for the field extension relation. |
| class /FldExt | ||
| Syntax | cfinext 33625 | Syntax for the finite field extension relation. |
| class /FinExt | ||
| Syntax | calgext 33626 | Syntax for the algebraic field extension relation. |
| class /AlgExt | ||
| Syntax | cextdg 33627 | Syntax for the field extension degree operation. |
| class [:] | ||
| Definition | df-fldext 33628* | Definition of the field extension relation. (Contributed by Thierry Arnoux, 29-Jul-2023.) |
| ⊢ /FldExt = {〈𝑒, 𝑓〉 ∣ ((𝑒 ∈ Field ∧ 𝑓 ∈ Field) ∧ (𝑓 = (𝑒 ↾s (Base‘𝑓)) ∧ (Base‘𝑓) ∈ (SubRing‘𝑒)))} | ||
| Definition | df-extdg 33629* | Definition of the field extension degree operation. (Contributed by Thierry Arnoux, 29-Jul-2023.) |
| ⊢ [:] = (𝑒 ∈ V, 𝑓 ∈ (/FldExt “ {𝑒}) ↦ (dim‘((subringAlg ‘𝑒)‘(Base‘𝑓)))) | ||
| Definition | df-finext 33630* | Definition of the finite field extension relation. (Contributed by Thierry Arnoux, 29-Jul-2023.) |
| ⊢ /FinExt = {〈𝑒, 𝑓〉 ∣ (𝑒/FldExt𝑓 ∧ (𝑒[:]𝑓) ∈ ℕ0)} | ||
| Definition | df-algext 33631* | Definition of the algebraic extension relation. (Contributed by Thierry Arnoux, 29-Jul-2023.) |
| ⊢ /AlgExt = {〈𝑒, 𝑓〉 ∣ (𝑒/FldExt𝑓 ∧ ∀𝑥 ∈ (Base‘𝑒)∃𝑝 ∈ (Poly1‘𝑓)(((eval1‘𝑓)‘𝑝)‘𝑥) = (0g‘𝑒))} | ||
| Theorem | relfldext 33632 | The field extension is a relation. (Contributed by Thierry Arnoux, 29-Jul-2023.) |
| ⊢ Rel /FldExt | ||
| Theorem | brfldext 33633 | The field extension relation explicited. (Contributed by Thierry Arnoux, 29-Jul-2023.) |
| ⊢ ((𝐸 ∈ Field ∧ 𝐹 ∈ Field) → (𝐸/FldExt𝐹 ↔ (𝐹 = (𝐸 ↾s (Base‘𝐹)) ∧ (Base‘𝐹) ∈ (SubRing‘𝐸)))) | ||
| Theorem | ccfldextrr 33634 | The field of the complex numbers is an extension of the field of the real numbers. (Contributed by Thierry Arnoux, 20-Jul-2023.) |
| ⊢ ℂfld/FldExtℝfld | ||
| Theorem | fldextfld1 33635 | A field extension is only defined if the extension is a field. (Contributed by Thierry Arnoux, 29-Jul-2023.) |
| ⊢ (𝐸/FldExt𝐹 → 𝐸 ∈ Field) | ||
| Theorem | fldextfld2 33636 | A field extension is only defined if the subfield is a field. (Contributed by Thierry Arnoux, 29-Jul-2023.) |
| ⊢ (𝐸/FldExt𝐹 → 𝐹 ∈ Field) | ||
| Theorem | fldextsubrg 33637 | Field extension implies a subring relation. (Contributed by Thierry Arnoux, 29-Jul-2023.) |
| ⊢ 𝑈 = (Base‘𝐹) ⇒ ⊢ (𝐸/FldExt𝐹 → 𝑈 ∈ (SubRing‘𝐸)) | ||
| Theorem | sdrgfldext 33638 | A field 𝐸 and any sub-division-ring 𝐹 of 𝐸 form a field extension. (Contributed by Thierry Arnoux, 26-Oct-2025.) |
| ⊢ 𝐵 = (Base‘𝐸) & ⊢ (𝜑 → 𝐸 ∈ Field) & ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐸)) ⇒ ⊢ (𝜑 → 𝐸/FldExt(𝐸 ↾s 𝐹)) | ||
| Theorem | fldextress 33639 | Field extension implies a structure restriction relation. (Contributed by Thierry Arnoux, 29-Jul-2023.) |
| ⊢ (𝐸/FldExt𝐹 → 𝐹 = (𝐸 ↾s (Base‘𝐹))) | ||
| Theorem | brfinext 33640 | The finite field extension relation explicited. (Contributed by Thierry Arnoux, 29-Jul-2023.) |
| ⊢ (𝐸/FldExt𝐹 → (𝐸/FinExt𝐹 ↔ (𝐸[:]𝐹) ∈ ℕ0)) | ||
| Theorem | extdgval 33641 | Value of the field extension degree operation. (Contributed by Thierry Arnoux, 29-Jul-2023.) |
| ⊢ (𝐸/FldExt𝐹 → (𝐸[:]𝐹) = (dim‘((subringAlg ‘𝐸)‘(Base‘𝐹)))) | ||
| Theorem | fldextsdrg 33642 | Deduce sub-division-ring from field extension. (Contributed by Thierry Arnoux, 26-Oct-2025.) |
| ⊢ 𝐵 = (Base‘𝐹) & ⊢ (𝜑 → 𝐸/FldExt𝐹) ⇒ ⊢ (𝜑 → 𝐵 ∈ (SubDRing‘𝐸)) | ||
| Theorem | fldextsralvec 33643 | The subring algebra associated with a field extension is a vector space. (Contributed by Thierry Arnoux, 3-Aug-2023.) |
| ⊢ (𝐸/FldExt𝐹 → ((subringAlg ‘𝐸)‘(Base‘𝐹)) ∈ LVec) | ||
| Theorem | extdgcl 33644 | Closure of the field extension degree operation. (Contributed by Thierry Arnoux, 29-Jul-2023.) |
| ⊢ (𝐸/FldExt𝐹 → (𝐸[:]𝐹) ∈ ℕ0*) | ||
| Theorem | extdggt0 33645 | Degrees of field extension are greater than zero. (Contributed by Thierry Arnoux, 30-Jul-2023.) |
| ⊢ (𝐸/FldExt𝐹 → 0 < (𝐸[:]𝐹)) | ||
| Theorem | fldexttr 33646 | Field extension is a transitive relation. (Contributed by Thierry Arnoux, 29-Jul-2023.) |
| ⊢ ((𝐸/FldExt𝐹 ∧ 𝐹/FldExt𝐾) → 𝐸/FldExt𝐾) | ||
| Theorem | fldextid 33647 | The field extension relation is reflexive. (Contributed by Thierry Arnoux, 30-Jul-2023.) |
| ⊢ (𝐹 ∈ Field → 𝐹/FldExt𝐹) | ||
| Theorem | extdgid 33648 | A trivial field extension has degree one. (Contributed by Thierry Arnoux, 4-Aug-2023.) |
| ⊢ (𝐸 ∈ Field → (𝐸[:]𝐸) = 1) | ||
| Theorem | fldsdrgfldext 33649 | A sub-division-ring of a field forms a field extension. (Contributed by Thierry Arnoux, 19-Oct-2025.) |
| ⊢ 𝐺 = (𝐹 ↾s 𝐴) & ⊢ (𝜑 → 𝐹 ∈ Field) & ⊢ (𝜑 → 𝐴 ∈ (SubDRing‘𝐹)) ⇒ ⊢ (𝜑 → 𝐹/FldExt𝐺) | ||
| Theorem | fldsdrgfldext2 33650 | A sub-sub-division-ring of a field forms a field extension. (Contributed by Thierry Arnoux, 19-Oct-2025.) |
| ⊢ 𝐺 = (𝐹 ↾s 𝐴) & ⊢ (𝜑 → 𝐹 ∈ Field) & ⊢ (𝜑 → 𝐴 ∈ (SubDRing‘𝐹)) & ⊢ (𝜑 → 𝐵 ∈ (SubDRing‘𝐺)) & ⊢ 𝐻 = (𝐹 ↾s 𝐵) ⇒ ⊢ (𝜑 → 𝐺/FldExt𝐻) | ||
| Theorem | extdgmul 33651 | The multiplicativity formula for degrees of field extensions. Given 𝐸 a field extension of 𝐹, itself a field extension of 𝐾, the degree of the extension 𝐸/FldExt𝐾 is the product of the degrees of the extensions 𝐸/FldExt𝐹 and 𝐹/FldExt𝐾. Proposition 1.2 of [Lang], p. 224. (Contributed by Thierry Arnoux, 30-Jul-2023.) |
| ⊢ ((𝐸/FldExt𝐹 ∧ 𝐹/FldExt𝐾) → (𝐸[:]𝐾) = ((𝐸[:]𝐹) ·e (𝐹[:]𝐾))) | ||
| Theorem | finexttrb 33652 | The extension 𝐸 of 𝐾 is finite if and only if 𝐸 is finite over 𝐹 and 𝐹 is finite over 𝐾. Corollary 1.3 of [Lang] , p. 225. (Contributed by Thierry Arnoux, 30-Jul-2023.) |
| ⊢ ((𝐸/FldExt𝐹 ∧ 𝐹/FldExt𝐾) → (𝐸/FinExt𝐾 ↔ (𝐸/FinExt𝐹 ∧ 𝐹/FinExt𝐾))) | ||
| Theorem | extdg1id 33653 | If the degree of the extension 𝐸/FldExt𝐹 is 1, then 𝐸 and 𝐹 are identical. (Contributed by Thierry Arnoux, 6-Aug-2023.) |
| ⊢ ((𝐸/FldExt𝐹 ∧ (𝐸[:]𝐹) = 1) → 𝐸 = 𝐹) | ||
| Theorem | extdg1b 33654 | The degree of the extension 𝐸/FldExt𝐹 is 1 iff 𝐸 and 𝐹 are the same structure. (Contributed by Thierry Arnoux, 6-Aug-2023.) |
| ⊢ (𝐸/FldExt𝐹 → ((𝐸[:]𝐹) = 1 ↔ 𝐸 = 𝐹)) | ||
| Theorem | fldgenfldext 33655 | A subfield 𝐹 extended with a set 𝐴 forms a field extension. (Contributed by Thierry Arnoux, 22-Jun-2025.) |
| ⊢ 𝐵 = (Base‘𝐸) & ⊢ 𝐾 = (𝐸 ↾s 𝐹) & ⊢ 𝐿 = (𝐸 ↾s (𝐸 fldGen (𝐹 ∪ 𝐴))) & ⊢ (𝜑 → 𝐸 ∈ Field) & ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐸)) & ⊢ (𝜑 → 𝐴 ⊆ 𝐵) ⇒ ⊢ (𝜑 → 𝐿/FldExt𝐾) | ||
| Theorem | fldextchr 33656 | The characteristic of a subfield is the same as the characteristic of the larger field. (Contributed by Thierry Arnoux, 20-Aug-2023.) |
| ⊢ (𝐸/FldExt𝐹 → (chr‘𝐹) = (chr‘𝐸)) | ||
| Theorem | evls1fldgencl 33657 | Closure of the subring polynomial evaluation in the field extention. (Contributed by Thierry Arnoux, 2-Apr-2025.) |
| ⊢ 𝐵 = (Base‘𝐸) & ⊢ 𝑂 = (𝐸 evalSub1 𝐹) & ⊢ 𝑃 = (Poly1‘(𝐸 ↾s 𝐹)) & ⊢ 𝑈 = (Base‘𝑃) & ⊢ (𝜑 → 𝐸 ∈ Field) & ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐸)) & ⊢ (𝜑 → 𝐴 ∈ 𝐵) & ⊢ (𝜑 → 𝐺 ∈ 𝑈) ⇒ ⊢ (𝜑 → ((𝑂‘𝐺)‘𝐴) ∈ (𝐸 fldGen (𝐹 ∪ {𝐴}))) | ||
| Theorem | ccfldsrarelvec 33658 | The subring algebra of the complex numbers over the real numbers is a left vector space. (Contributed by Thierry Arnoux, 20-Aug-2023.) |
| ⊢ ((subringAlg ‘ℂfld)‘ℝ) ∈ LVec | ||
| Theorem | ccfldextdgrr 33659 | The degree of the field extension of the complex numbers over the real numbers is 2. (Suggested by GL, 4-Aug-2023.) (Contributed by Thierry Arnoux, 20-Aug-2023.) |
| ⊢ (ℂfld[:]ℝfld) = 2 | ||
| Theorem | fldextrspunlsplem 33660* | Lemma for fldextrspunlsp 33661: First direction. Part of the proof of Proposition 5, Chapter 5, of [BourbakiAlg2] p. 116. (Contributed by Thierry Arnoux, 13-Oct-2025.) |
| ⊢ 𝐾 = (𝐿 ↾s 𝐹) & ⊢ 𝐼 = (𝐿 ↾s 𝐺) & ⊢ 𝐽 = (𝐿 ↾s 𝐻) & ⊢ (𝜑 → 𝐿 ∈ Field) & ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐼)) & ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐽)) & ⊢ (𝜑 → 𝐺 ∈ (SubDRing‘𝐿)) & ⊢ (𝜑 → 𝐻 ∈ (SubDRing‘𝐿)) & ⊢ 𝑁 = (RingSpan‘𝐿) & ⊢ 𝐶 = (𝑁‘(𝐺 ∪ 𝐻)) & ⊢ 𝐸 = (𝐿 ↾s 𝐶) & ⊢ (𝜑 → 𝐵 ∈ (LBasis‘((subringAlg ‘𝐽)‘𝐹))) & ⊢ (𝜑 → 𝐵 ∈ Fin) & ⊢ (𝜑 → 𝑃:𝐻⟶𝐺) & ⊢ (𝜑 → 𝑃 finSupp (0g‘𝐿)) & ⊢ (𝜑 → 𝑋 = (𝐿 Σg (𝑓 ∈ 𝐻 ↦ ((𝑃‘𝑓)(.r‘𝐿)𝑓)))) ⇒ ⊢ (𝜑 → ∃𝑎 ∈ (𝐺 ↑m 𝐵)(𝑎 finSupp (0g‘𝐿) ∧ 𝑋 = (𝐿 Σg (𝑏 ∈ 𝐵 ↦ ((𝑎‘𝑏)(.r‘𝐿)𝑏))))) | ||
| Theorem | fldextrspunlsp 33661 | Lemma for fldextrspunfld 33663. The subring generated by the union of two field extensions 𝐺 and 𝐻 is the vector sub- 𝐺 space generated by a basis 𝐵 of 𝐻. Part of the proof of Proposition 5, Chapter 5, of [BourbakiAlg2] p. 116. (Contributed by Thierry Arnoux, 13-Oct-2025.) |
| ⊢ 𝐾 = (𝐿 ↾s 𝐹) & ⊢ 𝐼 = (𝐿 ↾s 𝐺) & ⊢ 𝐽 = (𝐿 ↾s 𝐻) & ⊢ (𝜑 → 𝐿 ∈ Field) & ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐼)) & ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐽)) & ⊢ (𝜑 → 𝐺 ∈ (SubDRing‘𝐿)) & ⊢ (𝜑 → 𝐻 ∈ (SubDRing‘𝐿)) & ⊢ 𝑁 = (RingSpan‘𝐿) & ⊢ 𝐶 = (𝑁‘(𝐺 ∪ 𝐻)) & ⊢ 𝐸 = (𝐿 ↾s 𝐶) & ⊢ (𝜑 → 𝐵 ∈ (LBasis‘((subringAlg ‘𝐽)‘𝐹))) & ⊢ (𝜑 → 𝐵 ∈ Fin) ⇒ ⊢ (𝜑 → 𝐶 = ((LSpan‘((subringAlg ‘𝐿)‘𝐺))‘𝐵)) | ||
| Theorem | fldextrspunlem1 33662 | Lemma for fldextrspunfld 33663. Part of the proof of Proposition 5, Chapter 5, of [BourbakiAlg2] p. 116. (Contributed by Thierry Arnoux, 13-Oct-2025.) |
| ⊢ 𝐾 = (𝐿 ↾s 𝐹) & ⊢ 𝐼 = (𝐿 ↾s 𝐺) & ⊢ 𝐽 = (𝐿 ↾s 𝐻) & ⊢ (𝜑 → 𝐿 ∈ Field) & ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐼)) & ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐽)) & ⊢ (𝜑 → 𝐺 ∈ (SubDRing‘𝐿)) & ⊢ (𝜑 → 𝐻 ∈ (SubDRing‘𝐿)) & ⊢ (𝜑 → (𝐽[:]𝐾) ∈ ℕ0) & ⊢ 𝑁 = (RingSpan‘𝐿) & ⊢ 𝐶 = (𝑁‘(𝐺 ∪ 𝐻)) & ⊢ 𝐸 = (𝐿 ↾s 𝐶) ⇒ ⊢ (𝜑 → (dim‘((subringAlg ‘𝐸)‘𝐺)) ≤ (𝐽[:]𝐾)) | ||
| Theorem | fldextrspunfld 33663 | The ring generated by the union of two field extensions is a field. Part of the proof of Proposition 5, Chapter 5, of [BourbakiAlg2] p. 116. (Contributed by Thierry Arnoux, 13-Oct-2025.) |
| ⊢ 𝐾 = (𝐿 ↾s 𝐹) & ⊢ 𝐼 = (𝐿 ↾s 𝐺) & ⊢ 𝐽 = (𝐿 ↾s 𝐻) & ⊢ (𝜑 → 𝐿 ∈ Field) & ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐼)) & ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐽)) & ⊢ (𝜑 → 𝐺 ∈ (SubDRing‘𝐿)) & ⊢ (𝜑 → 𝐻 ∈ (SubDRing‘𝐿)) & ⊢ (𝜑 → (𝐽[:]𝐾) ∈ ℕ0) & ⊢ 𝑁 = (RingSpan‘𝐿) & ⊢ 𝐶 = (𝑁‘(𝐺 ∪ 𝐻)) & ⊢ 𝐸 = (𝐿 ↾s 𝐶) ⇒ ⊢ (𝜑 → 𝐸 ∈ Field) | ||
| Theorem | fldextrspunlem2 33664 | Part of the proof of Proposition 5, Chapter 5, of [BourbakiAlg2] p. 116. (Contributed by Thierry Arnoux, 13-Oct-2025.) |
| ⊢ 𝐾 = (𝐿 ↾s 𝐹) & ⊢ 𝐼 = (𝐿 ↾s 𝐺) & ⊢ 𝐽 = (𝐿 ↾s 𝐻) & ⊢ (𝜑 → 𝐿 ∈ Field) & ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐼)) & ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐽)) & ⊢ (𝜑 → 𝐺 ∈ (SubDRing‘𝐿)) & ⊢ (𝜑 → 𝐻 ∈ (SubDRing‘𝐿)) & ⊢ (𝜑 → (𝐽[:]𝐾) ∈ ℕ0) & ⊢ 𝑁 = (RingSpan‘𝐿) & ⊢ 𝐶 = (𝑁‘(𝐺 ∪ 𝐻)) & ⊢ 𝐸 = (𝐿 ↾s 𝐶) ⇒ ⊢ (𝜑 → 𝐶 = (𝐿 fldGen (𝐺 ∪ 𝐻))) | ||
| Theorem | fldextrspundgle 33665 | Inequality involving the degree of two different field extensions 𝐼 and 𝐽 of a same field 𝐹. Part of the proof of Proposition 5, Chapter 5, of [BourbakiAlg2] p. 116. (Contributed by Thierry Arnoux, 13-Oct-2025.) |
| ⊢ 𝐾 = (𝐿 ↾s 𝐹) & ⊢ 𝐼 = (𝐿 ↾s 𝐺) & ⊢ 𝐽 = (𝐿 ↾s 𝐻) & ⊢ (𝜑 → 𝐿 ∈ Field) & ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐼)) & ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐽)) & ⊢ (𝜑 → 𝐺 ∈ (SubDRing‘𝐿)) & ⊢ (𝜑 → 𝐻 ∈ (SubDRing‘𝐿)) & ⊢ (𝜑 → (𝐽[:]𝐾) ∈ ℕ0) & ⊢ 𝐸 = (𝐿 ↾s (𝐿 fldGen (𝐺 ∪ 𝐻))) ⇒ ⊢ (𝜑 → (𝐸[:]𝐼) ≤ (𝐽[:]𝐾)) | ||
| Theorem | fldextrspundglemul 33666 | Given two field extensions 𝐼 / 𝐾 and 𝐽 / 𝐾 of the same field 𝐾, 𝐽 / 𝐾 being finite, and the composiste field 𝐸 = 𝐼𝐽, the degree of the extension of the composite field 𝐸 / 𝐾 is at most the product of the field extension degrees of 𝐼 / 𝐾 and 𝐽 / 𝐾. (Contributed by Thierry Arnoux, 19-Oct-2025.) |
| ⊢ 𝐾 = (𝐿 ↾s 𝐹) & ⊢ 𝐼 = (𝐿 ↾s 𝐺) & ⊢ 𝐽 = (𝐿 ↾s 𝐻) & ⊢ (𝜑 → 𝐿 ∈ Field) & ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐼)) & ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐽)) & ⊢ (𝜑 → 𝐺 ∈ (SubDRing‘𝐿)) & ⊢ (𝜑 → 𝐻 ∈ (SubDRing‘𝐿)) & ⊢ (𝜑 → (𝐽[:]𝐾) ∈ ℕ0) & ⊢ 𝐸 = (𝐿 ↾s (𝐿 fldGen (𝐺 ∪ 𝐻))) ⇒ ⊢ (𝜑 → (𝐸[:]𝐾) ≤ ((𝐼[:]𝐾) ·e (𝐽[:]𝐾))) | ||
| Theorem | fldextrspundgdvdslem 33667 | Lemma for fldextrspundgdvds 33668. (Contributed by Thierry Arnoux, 19-Oct-2025.) |
| ⊢ 𝐾 = (𝐿 ↾s 𝐹) & ⊢ 𝐼 = (𝐿 ↾s 𝐺) & ⊢ 𝐽 = (𝐿 ↾s 𝐻) & ⊢ (𝜑 → 𝐿 ∈ Field) & ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐼)) & ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐽)) & ⊢ (𝜑 → 𝐺 ∈ (SubDRing‘𝐿)) & ⊢ (𝜑 → 𝐻 ∈ (SubDRing‘𝐿)) & ⊢ (𝜑 → (𝐽[:]𝐾) ∈ ℕ0) & ⊢ 𝐸 = (𝐿 ↾s (𝐿 fldGen (𝐺 ∪ 𝐻))) & ⊢ (𝜑 → (𝐼[:]𝐾) ∈ ℕ) ⇒ ⊢ (𝜑 → (𝐸[:]𝐼) ∈ ℕ0) | ||
| Theorem | fldextrspundgdvds 33668 | Given two finite extensions 𝐼 / 𝐾 and 𝐽 / 𝐾 of the same field 𝐾, the degree of the extension 𝐼 / 𝐾 divides the degree of the extension 𝐸 / 𝐾, 𝐸 being the composite field 𝐼𝐽. (Contributed by Thierry Arnoux, 19-Oct-2025.) |
| ⊢ 𝐾 = (𝐿 ↾s 𝐹) & ⊢ 𝐼 = (𝐿 ↾s 𝐺) & ⊢ 𝐽 = (𝐿 ↾s 𝐻) & ⊢ (𝜑 → 𝐿 ∈ Field) & ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐼)) & ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐽)) & ⊢ (𝜑 → 𝐺 ∈ (SubDRing‘𝐿)) & ⊢ (𝜑 → 𝐻 ∈ (SubDRing‘𝐿)) & ⊢ (𝜑 → (𝐽[:]𝐾) ∈ ℕ0) & ⊢ 𝐸 = (𝐿 ↾s (𝐿 fldGen (𝐺 ∪ 𝐻))) & ⊢ (𝜑 → (𝐼[:]𝐾) ∈ ℕ) ⇒ ⊢ (𝜑 → (𝐼[:]𝐾) ∥ (𝐸[:]𝐾)) | ||
| Theorem | fldext2rspun 33669* | Given two field extensions 𝐼 / 𝐾 and 𝐽 / 𝐾, 𝐼 / 𝐾 being a quadratic extension, and the degree of 𝐽 / 𝐾 being a power of 2, the degree of the extension 𝐸 / 𝐾 is a power of 2 , 𝐸 being the composite field 𝐼𝐽. (Contributed by Thierry Arnoux, 19-Oct-2025.) |
| ⊢ 𝐾 = (𝐿 ↾s 𝐹) & ⊢ 𝐼 = (𝐿 ↾s 𝐺) & ⊢ 𝐽 = (𝐿 ↾s 𝐻) & ⊢ (𝜑 → 𝐿 ∈ Field) & ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐼)) & ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐽)) & ⊢ (𝜑 → 𝐺 ∈ (SubDRing‘𝐿)) & ⊢ (𝜑 → 𝐻 ∈ (SubDRing‘𝐿)) & ⊢ (𝜑 → 𝑁 ∈ ℕ0) & ⊢ (𝜑 → (𝐼[:]𝐾) = 2) & ⊢ (𝜑 → (𝐽[:]𝐾) = (2↑𝑁)) & ⊢ 𝐸 = (𝐿 ↾s (𝐿 fldGen (𝐺 ∪ 𝐻))) ⇒ ⊢ (𝜑 → ∃𝑛 ∈ ℕ0 (𝐸[:]𝐾) = (2↑𝑛)) | ||
| Syntax | cirng 33670 | Integral subring of a ring. |
| class IntgRing | ||
| Definition | df-irng 33671* | Define the subring of elements of a ring 𝑟 integral over a subset 𝑠. (Contributed by Mario Carneiro, 2-Dec-2014.) (Revised by Thierry Arnoux, 28-Jan-2025.) |
| ⊢ IntgRing = (𝑟 ∈ V, 𝑠 ∈ V ↦ ∪ 𝑓 ∈ (Monic1p‘(𝑟 ↾s 𝑠))(◡((𝑟 evalSub1 𝑠)‘𝑓) “ {(0g‘𝑟)})) | ||
| Theorem | irngval 33672* | The elements of a field 𝑅 integral over a subset 𝑆. In the case of a subfield, those are the algebraic numbers over the field 𝑆 within the field 𝑅. That is, the numbers 𝑋 which are roots of monic polynomials 𝑃(𝑋) with coefficients in 𝑆. (Contributed by Thierry Arnoux, 28-Jan-2025.) |
| ⊢ 𝑂 = (𝑅 evalSub1 𝑆) & ⊢ 𝑈 = (𝑅 ↾s 𝑆) & ⊢ 𝐵 = (Base‘𝑅) & ⊢ 0 = (0g‘𝑅) & ⊢ (𝜑 → 𝑅 ∈ Ring) & ⊢ (𝜑 → 𝑆 ⊆ 𝐵) ⇒ ⊢ (𝜑 → (𝑅 IntgRing 𝑆) = ∪ 𝑓 ∈ (Monic1p‘𝑈)(◡(𝑂‘𝑓) “ { 0 })) | ||
| Theorem | elirng 33673* | Property for an element 𝑋 of a field 𝑅 to be integral over a subring 𝑆. (Contributed by Thierry Arnoux, 28-Jan-2025.) |
| ⊢ 𝑂 = (𝑅 evalSub1 𝑆) & ⊢ 𝑈 = (𝑅 ↾s 𝑆) & ⊢ 𝐵 = (Base‘𝑅) & ⊢ 0 = (0g‘𝑅) & ⊢ (𝜑 → 𝑅 ∈ CRing) & ⊢ (𝜑 → 𝑆 ∈ (SubRing‘𝑅)) ⇒ ⊢ (𝜑 → (𝑋 ∈ (𝑅 IntgRing 𝑆) ↔ (𝑋 ∈ 𝐵 ∧ ∃𝑓 ∈ (Monic1p‘𝑈)((𝑂‘𝑓)‘𝑋) = 0 ))) | ||
| Theorem | irngss 33674 | All elements of a subring 𝑆 are integral over 𝑆. This is only true in the case of a nonzero ring, since there are no integral elements in a zero ring (see 0ringirng 33676). (Contributed by Thierry Arnoux, 28-Jan-2025.) |
| ⊢ 𝑂 = (𝑅 evalSub1 𝑆) & ⊢ 𝑈 = (𝑅 ↾s 𝑆) & ⊢ 𝐵 = (Base‘𝑅) & ⊢ 0 = (0g‘𝑅) & ⊢ (𝜑 → 𝑅 ∈ CRing) & ⊢ (𝜑 → 𝑆 ∈ (SubRing‘𝑅)) & ⊢ (𝜑 → 𝑅 ∈ NzRing) ⇒ ⊢ (𝜑 → 𝑆 ⊆ (𝑅 IntgRing 𝑆)) | ||
| Theorem | irngssv 33675 | An integral element is an element of the base set. (Contributed by Thierry Arnoux, 28-Jan-2025.) |
| ⊢ 𝑂 = (𝑅 evalSub1 𝑆) & ⊢ 𝑈 = (𝑅 ↾s 𝑆) & ⊢ 𝐵 = (Base‘𝑅) & ⊢ 0 = (0g‘𝑅) & ⊢ (𝜑 → 𝑅 ∈ CRing) & ⊢ (𝜑 → 𝑆 ∈ (SubRing‘𝑅)) ⇒ ⊢ (𝜑 → (𝑅 IntgRing 𝑆) ⊆ 𝐵) | ||
| Theorem | 0ringirng 33676 | A zero ring 𝑅 has no integral elements. (Contributed by Thierry Arnoux, 5-Feb-2025.) |
| ⊢ 𝑂 = (𝑅 evalSub1 𝑆) & ⊢ 𝑈 = (𝑅 ↾s 𝑆) & ⊢ 𝐵 = (Base‘𝑅) & ⊢ 0 = (0g‘𝑅) & ⊢ (𝜑 → 𝑅 ∈ CRing) & ⊢ (𝜑 → 𝑆 ∈ (SubRing‘𝑅)) & ⊢ (𝜑 → ¬ 𝑅 ∈ NzRing) ⇒ ⊢ (𝜑 → (𝑅 IntgRing 𝑆) = ∅) | ||
| Theorem | irngnzply1lem 33677 | In the case of a field 𝐸, a root 𝑋 of some nonzero polynomial 𝑃 with coefficients in a subfield 𝐹 is integral over 𝐹. (Contributed by Thierry Arnoux, 5-Feb-2025.) |
| ⊢ 𝑂 = (𝐸 evalSub1 𝐹) & ⊢ 𝑍 = (0g‘(Poly1‘𝐸)) & ⊢ 0 = (0g‘𝐸) & ⊢ (𝜑 → 𝐸 ∈ Field) & ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐸)) & ⊢ 𝐵 = (Base‘𝐸) & ⊢ (𝜑 → 𝑃 ∈ dom 𝑂) & ⊢ (𝜑 → 𝑃 ≠ 𝑍) & ⊢ (𝜑 → ((𝑂‘𝑃)‘𝑋) = 0 ) & ⊢ (𝜑 → 𝑋 ∈ 𝐵) ⇒ ⊢ (𝜑 → 𝑋 ∈ (𝐸 IntgRing 𝐹)) | ||
| Theorem | irngnzply1 33678* | In the case of a field 𝐸, the roots of nonzero polynomials 𝑝 with coefficients in a subfield 𝐹 are exactly the integral elements over 𝐹. Roots of nonzero polynomials are called algebraic numbers, so this shows that in the case of a field, elements integral over 𝐹 are exactly the algebraic numbers. In this formula, dom 𝑂 represents the polynomials, and 𝑍 the zero polynomial. (Contributed by Thierry Arnoux, 5-Feb-2025.) |
| ⊢ 𝑂 = (𝐸 evalSub1 𝐹) & ⊢ 𝑍 = (0g‘(Poly1‘𝐸)) & ⊢ 0 = (0g‘𝐸) & ⊢ (𝜑 → 𝐸 ∈ Field) & ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐸)) ⇒ ⊢ (𝜑 → (𝐸 IntgRing 𝐹) = ∪ 𝑝 ∈ (dom 𝑂 ∖ {𝑍})(◡(𝑂‘𝑝) “ { 0 })) | ||
| Syntax | cminply 33679 | Extend class notation with the minimal polynomial builder function. |
| class minPoly | ||
| Definition | df-minply 33680* | Define the minimal polynomial builder function. (Contributed by Thierry Arnoux, 19-Jan-2025.) |
| ⊢ minPoly = (𝑒 ∈ V, 𝑓 ∈ V ↦ (𝑥 ∈ (Base‘𝑒) ↦ ((idlGen1p‘(𝑒 ↾s 𝑓))‘{𝑝 ∈ dom (𝑒 evalSub1 𝑓) ∣ (((𝑒 evalSub1 𝑓)‘𝑝)‘𝑥) = (0g‘𝑒)}))) | ||
| Theorem | ply1annidllem 33681* | Write the set 𝑄 of polynomials annihilating an element 𝐴 as the kernel of the ring homomorphism 𝐹 mapping polynomials 𝑝 to their subring evaluation at a given point 𝐴. (Contributed by Thierry Arnoux, 9-Feb-2025.) |
| ⊢ 𝑂 = (𝑅 evalSub1 𝑆) & ⊢ 𝑃 = (Poly1‘(𝑅 ↾s 𝑆)) & ⊢ 𝐵 = (Base‘𝑅) & ⊢ (𝜑 → 𝑅 ∈ CRing) & ⊢ (𝜑 → 𝑆 ∈ (SubRing‘𝑅)) & ⊢ (𝜑 → 𝐴 ∈ 𝐵) & ⊢ 0 = (0g‘𝑅) & ⊢ 𝑄 = {𝑞 ∈ dom 𝑂 ∣ ((𝑂‘𝑞)‘𝐴) = 0 } & ⊢ 𝐹 = (𝑝 ∈ (Base‘𝑃) ↦ ((𝑂‘𝑝)‘𝐴)) ⇒ ⊢ (𝜑 → 𝑄 = (◡𝐹 “ { 0 })) | ||
| Theorem | ply1annidl 33682* | The set 𝑄 of polynomials annihilating an element 𝐴 forms an ideal. (Contributed by Thierry Arnoux, 9-Feb-2025.) |
| ⊢ 𝑂 = (𝑅 evalSub1 𝑆) & ⊢ 𝑃 = (Poly1‘(𝑅 ↾s 𝑆)) & ⊢ 𝐵 = (Base‘𝑅) & ⊢ (𝜑 → 𝑅 ∈ CRing) & ⊢ (𝜑 → 𝑆 ∈ (SubRing‘𝑅)) & ⊢ (𝜑 → 𝐴 ∈ 𝐵) & ⊢ 0 = (0g‘𝑅) & ⊢ 𝑄 = {𝑞 ∈ dom 𝑂 ∣ ((𝑂‘𝑞)‘𝐴) = 0 } ⇒ ⊢ (𝜑 → 𝑄 ∈ (LIdeal‘𝑃)) | ||
| Theorem | ply1annnr 33683* | The set 𝑄 of polynomials annihilating an element 𝐴 is not the whole polynomial ring. (Contributed by Thierry Arnoux, 22-Mar-2025.) |
| ⊢ 𝑂 = (𝑅 evalSub1 𝑆) & ⊢ 𝑃 = (Poly1‘(𝑅 ↾s 𝑆)) & ⊢ 𝐵 = (Base‘𝑅) & ⊢ (𝜑 → 𝑅 ∈ CRing) & ⊢ (𝜑 → 𝑆 ∈ (SubRing‘𝑅)) & ⊢ (𝜑 → 𝐴 ∈ 𝐵) & ⊢ 0 = (0g‘𝑅) & ⊢ 𝑄 = {𝑞 ∈ dom 𝑂 ∣ ((𝑂‘𝑞)‘𝐴) = 0 } & ⊢ 𝑈 = (Base‘𝑃) & ⊢ (𝜑 → 𝑅 ∈ NzRing) ⇒ ⊢ (𝜑 → 𝑄 ≠ 𝑈) | ||
| Theorem | ply1annig1p 33684* | The ideal 𝑄 of polynomials annihilating an element 𝐴 is generated by the ideal's canonical generator. (Contributed by Thierry Arnoux, 9-Feb-2025.) |
| ⊢ 𝑂 = (𝐸 evalSub1 𝐹) & ⊢ 𝑃 = (Poly1‘(𝐸 ↾s 𝐹)) & ⊢ 𝐵 = (Base‘𝐸) & ⊢ (𝜑 → 𝐸 ∈ Field) & ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐸)) & ⊢ (𝜑 → 𝐴 ∈ 𝐵) & ⊢ 0 = (0g‘𝐸) & ⊢ 𝑄 = {𝑞 ∈ dom 𝑂 ∣ ((𝑂‘𝑞)‘𝐴) = 0 } & ⊢ 𝐾 = (RSpan‘𝑃) & ⊢ 𝐺 = (idlGen1p‘(𝐸 ↾s 𝐹)) ⇒ ⊢ (𝜑 → 𝑄 = (𝐾‘{(𝐺‘𝑄)})) | ||
| Theorem | minplyval 33685* | Expand the value of the minimal polynomial (𝑀‘𝐴) for a given element 𝐴. It is defined as the unique monic polynomial of minimal degree which annihilates 𝐴. By ply1annig1p 33684, that polynomial generates the ideal of the annihilators of 𝐴. (Contributed by Thierry Arnoux, 9-Feb-2025.) |
| ⊢ 𝑂 = (𝐸 evalSub1 𝐹) & ⊢ 𝑃 = (Poly1‘(𝐸 ↾s 𝐹)) & ⊢ 𝐵 = (Base‘𝐸) & ⊢ (𝜑 → 𝐸 ∈ Field) & ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐸)) & ⊢ (𝜑 → 𝐴 ∈ 𝐵) & ⊢ 0 = (0g‘𝐸) & ⊢ 𝑄 = {𝑞 ∈ dom 𝑂 ∣ ((𝑂‘𝑞)‘𝐴) = 0 } & ⊢ 𝐾 = (RSpan‘𝑃) & ⊢ 𝐺 = (idlGen1p‘(𝐸 ↾s 𝐹)) & ⊢ 𝑀 = (𝐸 minPoly 𝐹) ⇒ ⊢ (𝜑 → (𝑀‘𝐴) = (𝐺‘𝑄)) | ||
| Theorem | minplycl 33686* | The minimal polynomial is a polynomial. (Contributed by Thierry Arnoux, 22-Mar-2025.) |
| ⊢ 𝑂 = (𝐸 evalSub1 𝐹) & ⊢ 𝑃 = (Poly1‘(𝐸 ↾s 𝐹)) & ⊢ 𝐵 = (Base‘𝐸) & ⊢ (𝜑 → 𝐸 ∈ Field) & ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐸)) & ⊢ (𝜑 → 𝐴 ∈ 𝐵) & ⊢ 0 = (0g‘𝐸) & ⊢ 𝑄 = {𝑞 ∈ dom 𝑂 ∣ ((𝑂‘𝑞)‘𝐴) = 0 } & ⊢ 𝐾 = (RSpan‘𝑃) & ⊢ 𝐺 = (idlGen1p‘(𝐸 ↾s 𝐹)) & ⊢ 𝑀 = (𝐸 minPoly 𝐹) ⇒ ⊢ (𝜑 → (𝑀‘𝐴) ∈ (Base‘𝑃)) | ||
| Theorem | ply1annprmidl 33687* | The set 𝑄 of polynomials annihilating an element 𝐴 is a prime ideal. (Contributed by Thierry Arnoux, 9-Feb-2025.) |
| ⊢ 𝑂 = (𝐸 evalSub1 𝐹) & ⊢ 𝑃 = (Poly1‘(𝐸 ↾s 𝐹)) & ⊢ 𝐵 = (Base‘𝐸) & ⊢ (𝜑 → 𝐸 ∈ Field) & ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐸)) & ⊢ (𝜑 → 𝐴 ∈ 𝐵) & ⊢ 0 = (0g‘𝐸) & ⊢ 𝑄 = {𝑞 ∈ dom 𝑂 ∣ ((𝑂‘𝑞)‘𝐴) = 0 } ⇒ ⊢ (𝜑 → 𝑄 ∈ (PrmIdeal‘𝑃)) | ||
| Theorem | minplymindeg 33688 | The minimal polynomial of 𝐴 is minimal among the nonzero annihilators of 𝐴 with regard to degree. (Contributed by Thierry Arnoux, 22-Jun-2025.) |
| ⊢ 𝑂 = (𝐸 evalSub1 𝐹) & ⊢ 𝑃 = (Poly1‘(𝐸 ↾s 𝐹)) & ⊢ 𝐵 = (Base‘𝐸) & ⊢ (𝜑 → 𝐸 ∈ Field) & ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐸)) & ⊢ (𝜑 → 𝐴 ∈ 𝐵) & ⊢ 0 = (0g‘𝐸) & ⊢ 𝑀 = (𝐸 minPoly 𝐹) & ⊢ 𝐷 = (deg1‘(𝐸 ↾s 𝐹)) & ⊢ 𝑍 = (0g‘𝑃) & ⊢ 𝑈 = (Base‘𝑃) & ⊢ (𝜑 → ((𝑂‘𝐻)‘𝐴) = 0 ) & ⊢ (𝜑 → 𝐻 ∈ 𝑈) & ⊢ (𝜑 → 𝐻 ≠ 𝑍) ⇒ ⊢ (𝜑 → (𝐷‘(𝑀‘𝐴)) ≤ (𝐷‘𝐻)) | ||
| Theorem | minplyann 33689 | The minimal polynomial for 𝐴 annihilates 𝐴 (Contributed by Thierry Arnoux, 25-Apr-2025.) |
| ⊢ 𝑂 = (𝐸 evalSub1 𝐹) & ⊢ 𝑃 = (Poly1‘(𝐸 ↾s 𝐹)) & ⊢ 𝐵 = (Base‘𝐸) & ⊢ (𝜑 → 𝐸 ∈ Field) & ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐸)) & ⊢ (𝜑 → 𝐴 ∈ 𝐵) & ⊢ 0 = (0g‘𝐸) & ⊢ 𝑀 = (𝐸 minPoly 𝐹) ⇒ ⊢ (𝜑 → ((𝑂‘(𝑀‘𝐴))‘𝐴) = 0 ) | ||
| Theorem | minplyirredlem 33690 | Lemma for minplyirred 33691. (Contributed by Thierry Arnoux, 22-Mar-2025.) |
| ⊢ 𝑂 = (𝐸 evalSub1 𝐹) & ⊢ 𝑃 = (Poly1‘(𝐸 ↾s 𝐹)) & ⊢ 𝐵 = (Base‘𝐸) & ⊢ (𝜑 → 𝐸 ∈ Field) & ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐸)) & ⊢ (𝜑 → 𝐴 ∈ 𝐵) & ⊢ 𝑀 = (𝐸 minPoly 𝐹) & ⊢ 𝑍 = (0g‘𝑃) & ⊢ (𝜑 → (𝑀‘𝐴) ≠ 𝑍) & ⊢ (𝜑 → 𝐺 ∈ (Base‘𝑃)) & ⊢ (𝜑 → 𝐻 ∈ (Base‘𝑃)) & ⊢ (𝜑 → (𝐺(.r‘𝑃)𝐻) = (𝑀‘𝐴)) & ⊢ (𝜑 → ((𝑂‘𝐺)‘𝐴) = (0g‘𝐸)) & ⊢ (𝜑 → 𝐺 ≠ 𝑍) & ⊢ (𝜑 → 𝐻 ≠ 𝑍) ⇒ ⊢ (𝜑 → 𝐻 ∈ (Unit‘𝑃)) | ||
| Theorem | minplyirred 33691 | A nonzero minimal polynomial is irreducible. (Contributed by Thierry Arnoux, 22-Mar-2025.) |
| ⊢ 𝑂 = (𝐸 evalSub1 𝐹) & ⊢ 𝑃 = (Poly1‘(𝐸 ↾s 𝐹)) & ⊢ 𝐵 = (Base‘𝐸) & ⊢ (𝜑 → 𝐸 ∈ Field) & ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐸)) & ⊢ (𝜑 → 𝐴 ∈ 𝐵) & ⊢ 𝑀 = (𝐸 minPoly 𝐹) & ⊢ 𝑍 = (0g‘𝑃) & ⊢ (𝜑 → (𝑀‘𝐴) ≠ 𝑍) ⇒ ⊢ (𝜑 → (𝑀‘𝐴) ∈ (Irred‘𝑃)) | ||
| Theorem | irngnminplynz 33692 | Integral elements have nonzero minimal polynomials. (Contributed by Thierry Arnoux, 22-Mar-2025.) |
| ⊢ 𝑍 = (0g‘(Poly1‘𝐸)) & ⊢ (𝜑 → 𝐸 ∈ Field) & ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐸)) & ⊢ 𝑀 = (𝐸 minPoly 𝐹) & ⊢ (𝜑 → 𝐴 ∈ (𝐸 IntgRing 𝐹)) ⇒ ⊢ (𝜑 → (𝑀‘𝐴) ≠ 𝑍) | ||
| Theorem | minplym1p 33693 | A minimal polynomial is monic. (Contributed by Thierry Arnoux, 2-Apr-2025.) |
| ⊢ 𝑍 = (0g‘(Poly1‘𝐸)) & ⊢ (𝜑 → 𝐸 ∈ Field) & ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐸)) & ⊢ 𝑀 = (𝐸 minPoly 𝐹) & ⊢ (𝜑 → 𝐴 ∈ (𝐸 IntgRing 𝐹)) & ⊢ 𝑈 = (Monic1p‘(𝐸 ↾s 𝐹)) ⇒ ⊢ (𝜑 → (𝑀‘𝐴) ∈ 𝑈) | ||
| Theorem | minplynzm1p 33694 | If a minimal polynomial is nonzero, then it is monic. (Contributed by Thierry Arnoux, 26-Oct-2025.) |
| ⊢ 𝐵 = (Base‘𝐸) & ⊢ 𝑍 = (0g‘(Poly1‘𝐸)) & ⊢ (𝜑 → 𝐸 ∈ Field) & ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐸)) & ⊢ 𝑀 = (𝐸 minPoly 𝐹) & ⊢ (𝜑 → 𝐴 ∈ 𝐵) & ⊢ (𝜑 → (𝑀‘𝐴) ≠ 𝑍) & ⊢ 𝑈 = (Monic1p‘(𝐸 ↾s 𝐹)) ⇒ ⊢ (𝜑 → (𝑀‘𝐴) ∈ 𝑈) | ||
| Theorem | minplyelirng 33695 | If the minimial polynomial 𝐹 of an element 𝑋 of a field 𝑅 has nonnegative degree, then 𝑋 is integral. (Contributed by Thierry Arnoux, 26-Oct-2025.) |
| ⊢ 𝐵 = (Base‘𝑅) & ⊢ 𝑀 = (𝑅 minPoly 𝑆) & ⊢ 𝐷 = (deg1‘(𝑅 ↾s 𝑆)) & ⊢ (𝜑 → 𝑅 ∈ Field) & ⊢ (𝜑 → 𝑆 ∈ (SubDRing‘𝑅)) & ⊢ (𝜑 → 𝐴 ∈ 𝐵) & ⊢ (𝜑 → (𝐷‘(𝑀‘𝐴)) ∈ ℕ0) ⇒ ⊢ (𝜑 → 𝐴 ∈ (𝑅 IntgRing 𝑆)) | ||
| Theorem | irredminply 33696 | An irreducible, monic, annihilating polynomial is the minimal polynomial. (Contributed by Thierry Arnoux, 27-Apr-2025.) |
| ⊢ 𝑂 = (𝐸 evalSub1 𝐹) & ⊢ 𝑃 = (Poly1‘(𝐸 ↾s 𝐹)) & ⊢ 𝐵 = (Base‘𝐸) & ⊢ (𝜑 → 𝐸 ∈ Field) & ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐸)) & ⊢ (𝜑 → 𝐴 ∈ 𝐵) & ⊢ 0 = (0g‘𝐸) & ⊢ 𝑀 = (𝐸 minPoly 𝐹) & ⊢ 𝑍 = (0g‘𝑃) & ⊢ (𝜑 → ((𝑂‘𝐺)‘𝐴) = 0 ) & ⊢ (𝜑 → 𝐺 ∈ (Irred‘𝑃)) & ⊢ (𝜑 → 𝐺 ∈ (Monic1p‘(𝐸 ↾s 𝐹))) ⇒ ⊢ (𝜑 → 𝐺 = (𝑀‘𝐴)) | ||
| Theorem | algextdeglem1 33697 | Lemma for algextdeg 33705. (Contributed by Thierry Arnoux, 2-Apr-2025.) |
| ⊢ 𝐾 = (𝐸 ↾s 𝐹) & ⊢ 𝐿 = (𝐸 ↾s (𝐸 fldGen (𝐹 ∪ {𝐴}))) & ⊢ 𝐷 = (deg1‘𝐸) & ⊢ 𝑀 = (𝐸 minPoly 𝐹) & ⊢ (𝜑 → 𝐸 ∈ Field) & ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐸)) & ⊢ (𝜑 → 𝐴 ∈ (𝐸 IntgRing 𝐹)) ⇒ ⊢ (𝜑 → (𝐿 ↾s 𝐹) = 𝐾) | ||
| Theorem | algextdeglem2 33698* | Lemma for algextdeg 33705. Both the ring of polynomials 𝑃 and the field 𝐿 generated by 𝐾 and the algebraic element 𝐴 can be considered as modules over the elements of 𝐹. Then, the evaluation map 𝐺, mapping polynomials to their evaluation at 𝐴, is a module homomorphism between those modules. (Contributed by Thierry Arnoux, 2-Apr-2025.) |
| ⊢ 𝐾 = (𝐸 ↾s 𝐹) & ⊢ 𝐿 = (𝐸 ↾s (𝐸 fldGen (𝐹 ∪ {𝐴}))) & ⊢ 𝐷 = (deg1‘𝐸) & ⊢ 𝑀 = (𝐸 minPoly 𝐹) & ⊢ (𝜑 → 𝐸 ∈ Field) & ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐸)) & ⊢ (𝜑 → 𝐴 ∈ (𝐸 IntgRing 𝐹)) & ⊢ 𝑂 = (𝐸 evalSub1 𝐹) & ⊢ 𝑃 = (Poly1‘𝐾) & ⊢ 𝑈 = (Base‘𝑃) & ⊢ 𝐺 = (𝑝 ∈ 𝑈 ↦ ((𝑂‘𝑝)‘𝐴)) & ⊢ 𝑁 = (𝑥 ∈ 𝑈 ↦ [𝑥](𝑃 ~QG 𝑍)) & ⊢ 𝑍 = (◡𝐺 “ {(0g‘𝐿)}) & ⊢ 𝑄 = (𝑃 /s (𝑃 ~QG 𝑍)) & ⊢ 𝐽 = (𝑝 ∈ (Base‘𝑄) ↦ ∪ (𝐺 “ 𝑝)) ⇒ ⊢ (𝜑 → 𝐺 ∈ (𝑃 LMHom ((subringAlg ‘𝐿)‘𝐹))) | ||
| Theorem | algextdeglem3 33699* | Lemma for algextdeg 33705. The quotient 𝑃 / 𝑍 of the vector space 𝑃 of polynomials by the subspace 𝑍 of polynomials annihilating 𝐴 is itself a vector space. (Contributed by Thierry Arnoux, 2-Apr-2025.) |
| ⊢ 𝐾 = (𝐸 ↾s 𝐹) & ⊢ 𝐿 = (𝐸 ↾s (𝐸 fldGen (𝐹 ∪ {𝐴}))) & ⊢ 𝐷 = (deg1‘𝐸) & ⊢ 𝑀 = (𝐸 minPoly 𝐹) & ⊢ (𝜑 → 𝐸 ∈ Field) & ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐸)) & ⊢ (𝜑 → 𝐴 ∈ (𝐸 IntgRing 𝐹)) & ⊢ 𝑂 = (𝐸 evalSub1 𝐹) & ⊢ 𝑃 = (Poly1‘𝐾) & ⊢ 𝑈 = (Base‘𝑃) & ⊢ 𝐺 = (𝑝 ∈ 𝑈 ↦ ((𝑂‘𝑝)‘𝐴)) & ⊢ 𝑁 = (𝑥 ∈ 𝑈 ↦ [𝑥](𝑃 ~QG 𝑍)) & ⊢ 𝑍 = (◡𝐺 “ {(0g‘𝐿)}) & ⊢ 𝑄 = (𝑃 /s (𝑃 ~QG 𝑍)) & ⊢ 𝐽 = (𝑝 ∈ (Base‘𝑄) ↦ ∪ (𝐺 “ 𝑝)) ⇒ ⊢ (𝜑 → 𝑄 ∈ LVec) | ||
| Theorem | algextdeglem4 33700* | Lemma for algextdeg 33705. By lmhmqusker 33378, the surjective module homomorphism 𝐺 described in algextdeglem2 33698 induces an isomorphism with the quotient space. Therefore, the dimension of that quotient space 𝑃 / 𝑍 is the degree of the algebraic field extension. (Contributed by Thierry Arnoux, 2-Apr-2025.) |
| ⊢ 𝐾 = (𝐸 ↾s 𝐹) & ⊢ 𝐿 = (𝐸 ↾s (𝐸 fldGen (𝐹 ∪ {𝐴}))) & ⊢ 𝐷 = (deg1‘𝐸) & ⊢ 𝑀 = (𝐸 minPoly 𝐹) & ⊢ (𝜑 → 𝐸 ∈ Field) & ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐸)) & ⊢ (𝜑 → 𝐴 ∈ (𝐸 IntgRing 𝐹)) & ⊢ 𝑂 = (𝐸 evalSub1 𝐹) & ⊢ 𝑃 = (Poly1‘𝐾) & ⊢ 𝑈 = (Base‘𝑃) & ⊢ 𝐺 = (𝑝 ∈ 𝑈 ↦ ((𝑂‘𝑝)‘𝐴)) & ⊢ 𝑁 = (𝑥 ∈ 𝑈 ↦ [𝑥](𝑃 ~QG 𝑍)) & ⊢ 𝑍 = (◡𝐺 “ {(0g‘𝐿)}) & ⊢ 𝑄 = (𝑃 /s (𝑃 ~QG 𝑍)) & ⊢ 𝐽 = (𝑝 ∈ (Base‘𝑄) ↦ ∪ (𝐺 “ 𝑝)) ⇒ ⊢ (𝜑 → (dim‘𝑄) = (𝐿[:]𝐾)) | ||
| < Previous Next > |
| Copyright terms: Public domain | < Previous Next > |